jup mình với mọi người

júp mink với ace ơi

\(=x^3-3x^2+6x^2-18x+8x-24\\ =\left(x-3\right)\left(x^2+6x+8\right)\\ =\left(x-3\right)\left(x^2+2x+4x+8\right)\\ =\left(x-3\right)\left(x+2\right)\left(x+4\right)\)

\(x^3+3x^2-10x-24=\left(x^3-3x^2\right)+\left(6x^2-18x\right)+\left(8x-24\right)=x^2\left(x-3\right)+6x\left(x-3\right)+8\left(x-3\right)=\left(x-3\right)\left(x^2+6x+8\right)=\left(x-3\right)\left[\left(x^2+2x\right)+\left(4x+8\right)\right]=\left(x-3\right)\left[x\left(x+2\right)+4\left(x+2\right)\right]=\left(x-3\right)\left(x+2\right)\left(x+4\right)\)

a) \(-10x^2-17x+6\)

\(=-10x^2-20x+3x+6\)

\(=-10x\left(x+2\right)+3\left(x+2\right)\)

\(=\left(x+2\right)\left(3-10x\right)\)

b)\(x^2-10x+9\)

\(=x^2-x-9x+9\)

\(=x\left(x-1\right)-9\left(x-1\right)\)

\(=\left(x-1\right)\left(x-9\right)\)

c) \(x^2-10x+24\)

\(=x^2-4x-6x+24\)

\(=x\left(x-4\right)-6\left(x-4\right)\)

\(=\left(x-4\right)\left(x-6\right)\)

x^2 - 10x + 24

= x^2  - 4x - 6x + 24 

= x(x - 4) - 6(x - 4)

= (x - 6)(x - 4)

ko vt lại đề

x²-6x-4x+24

=(x²-6x)-(4x-24)

=x(x-6)-4(x-6)

=(x-6)(x-4)

\(x^2-10x+24\)

\(\Leftrightarrow x^2-4x-6x+24\)

\(\Leftrightarrow(x^2-4x)-\left(6x-24\right)\)

\(\Leftrightarrow x\left(x-4\right)-6\left(x-4\right)\)

\(\Leftrightarrow\left(x-4\right)\left(x-6\right)\)

-x²+10x-25=-(x²-10x+25)=-(x²-2.5+25)=-(x-5)²

4x² - 6xy + 10x³

= 2x(2x - 3y + 10x²)

\(=2x\left(2x-3y+5x^2\right)\)

\(g,x^4-16=\left(x^2-4\right)\left(x^2+4\right)=\left(x-2\right)\left(x+2\right)\left(x^2+4\right)\\ i,-x^2+10x-25=-\left(x-5\right)^2\\ k,x^3+3x^2+3x+1-27z^3\\ =\left(x+1\right)^3-27z^3\\ =\left(x+1-3z\right)\left[\left(x+1\right)^2+3z\left(x+1\right)+9z^2\right]\\ =\left(x-3z+1\right)\left(x^2+2x+1+3xz+3z+9z^2\right)\\ m,\left(x+y\right)^2-25\left(x+y\right)+24=\left(x+y-5\right)^2-1=\left(x+y-4\right)\left(x+y-6\right)\)

g. x⁴ - 16

<=> x⁴ - 4²

<=> (x²)² - 4²

<=> (x² - 4)(x² + 4)

i. -x² + 10x - 25

<=> -(x² - 10x + 25)

<=> -(x² -10x + 5²)

<=> -(x - 5)²

sao ko ai like tui, buồn

10x-25-x^2

=-x^2+10x-25

= - (x^2-10x+25)

=-(x^2-2x5+25)

= -(x-5)^2

\(x^3-10x^2+25x-16xy^2\)

\(=x\left(x^2-10x+25-16y^2\right)\)

\(=x\left[\left(x-5\right)^2-16y^2\right]\)

\(=x\left(x-4y-5\right)\left(x+4y-5\right)\)

p/s: chúc bạn học tốt