\(\dfrac{1}{2}\) \(\times\) ( \(x\) - \(\dfrac{2}{3}\)) - \(\dfrac{1}{3}\) \(\times\) ( 2\(x\)  - 3) = \(x\)

\(\dfrac{1}{2}\)  \(\times\) \(\dfrac{3x-2}{3}\) -   \(\dfrac{2x-3}{3}\) = \(x\)

\(\dfrac{3x-2}{6}\) - \(\dfrac{4x-6}{6}\) = \(\dfrac{6x}{6}\)

3\(x-2-4x\) + 6 = 6\(x\) 

-\(x\) + 4 - 6\(x\) = 0

7\(x\)  = 4

    \(x\) =  \(\dfrac{4}{7}\) 

\(\dfrac{-2}{3}\left(x-\dfrac{1}{4}\right)=\dfrac{1}{3}\left(2x-1\right)\)

\(\Leftrightarrow\dfrac{-2}{3}x+\dfrac{1}{6}=\dfrac{2}{3}x-\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{-2}{3}x-\dfrac{2}{3}x=\dfrac{-1}{3}-\dfrac{1}{6}\)

\(\Leftrightarrow\dfrac{-4}{3}x=\dfrac{-1}{2}\)

\(\Leftrightarrow x=\dfrac{3}{8}\)

Vậy \(x=\dfrac{3}{8}\)

\(A=3^x+3^{x+1}+...+3^{x+100}\)

=>\(3A=3^{x+1}+3^{x+2}+...+3^{x+101}\)

=>\(2A=3^{x+101}-3^x\)

=>\(A=\dfrac{3^{x+101}-3^x}{2}\)

=>\(3^{x+101}-3^x=3^{105}-3^4\)

=>x=4

x=4

(x+2)(x-1)-(x-3)(x+5)=0

x²+2x-x-2-x²+3x-5x+15=0

-x+13=0

x=13

vậy......

x²-x+2x-2-x²+5x-3x-15=0    nhân vô

2x-15=0   tối giản

2x=15  đổi vế

x=15/2 chia

bạn nhân lộn rồi 

-3 nhân x = -3x chớ

          \(4\left(x+1\right)-\left(3x+1\right)=14\)

\(\Leftrightarrow\)\(4x+4-3x-1=14\)

\(\Leftrightarrow\)\(x+3=14\)

\(\Leftrightarrow\)\(x=11\)

Vậy....