2+3x4
2/3x4/5-1/3x4/5
\(\frac{2}{3}\times\frac{4}{5}-\frac{1}{3}\times\frac{4}{5}\)
\(=\frac{8}{15}-\frac{4}{15}\)
\(=\frac{4}{15}\)
k mk nha mấy bạn
Tính tổng:
A = 1x2+3x4+4x5+...+99x100
B = 1x22+2x32+3x42+4x52+...+99x1002
Mẫu: 2/3x4=2x4/3=8/3 Mẫu:4x2/3=4x2/3=8/3
a)3/4x5=... b)1/3x2=...
b)3x4/5=... c)3x1/4=...
a) 3x5/4= 15/4
b) 1x2/3= 2/3
c) 3x4/5= 12/5
d) 3x1/4= 3/4
2/3:4 và 2/3x4
\(\dfrac{2}{3}:4=\dfrac{2}{3}:\dfrac{4}{1}=\dfrac{2}{3}\) x \(\dfrac{1}{4}=\) \(\dfrac{2}{12}=\dfrac{1}{6}\)
\(\dfrac{2}{3}\) x \(4=\) \(\dfrac{2}{3}\) x \(\dfrac{4}{1}=\dfrac{8}{3}\)
2x2x2x2+3x4-2:2 x5=
1/ Cho 2 đa thức:
A (x) = 3x4 - 4x3 + 5x2 - 4x - 3
B (x) = - 3x4 + 4x3 - 5x2 + 2x + 6
a) Tính C (x) = A (x) + B (x)
b) Tìm nghiệm của đa thức C (x)
a: \(C\left(x\right)=A\left(x\right)+B\left(x\right)\)
\(=3x^4-4x^3+5x^2-4x-3-3x^4+4x^3-5x^2+2x+6\)
=-2x+3
b: Đặt C(x)=0
=>-2x+3=0
hay x=3/2
a=1x1^2+2x2^3+3x4^2+......+98x99^2
2/3x4+2/4x5+2/5x6+...+2/2001x2002
2/1x2+2/2x3+2/3x4+....+2/1999x2000
easy mà
=2.(1/1.2+1/2.3+...+1/1999.2000)
=2.(1/1-1/2+1/2-1/3+....1/1999-1/2000)
=2.(1-1/2000)
=2.1999/2000
=3998/2000=... tự rút gọn :D