Đơn chất: 

\(O_2-PTK:32\left(đvC\right)\\ Ba-PTK:137\left(đvC\right)\)

Hợp chất:

\(HCl-PTK:36,5\left(đvC\right)\\ BaSO_3-PTK:217\left(đvC\right)\\ NaHSO_4-PTK:120\left(đvC\right)\\ BaSO_4-PTK:233\left(đvC\right)\\ Ba\left(OH\right)_2-PTK:171\left(đvC\right)\\ H_2SO_4-PTK:98\left(đvC\right)\\ Fe\left(NO_3\right)_2-PTK:180\left(đvC\right)\\ Al_2O_3-PTK:102\left(đvC\right)\\ Fe\left(OH\right)_3-PTK:107\left(đvC\right)\)

Đơn chất: O₂, Ba

Hợp chất: HCl, BaSO₃, NaHSO₄, BaSO₄, Ba(OH)₂, H₂SO₄, Fe(NO₃)₂, Al₂O₃, Fe(OH)₃

PTK_O2 = 16.2 = 32(đvC)

PTK_HCl = 1.1 + 1.35,5 = 36,5 (đvC)

NTK_Ba = 137 (đvC)

PTK BaSO₃ = 137.1 + 32.1 + 16.3 = 217 (đvC)

PTK: NaHSO₄ = 23.1 + 1.1 + 32.1 + 16.4 = 120 (đvC)

PTK BaSO₄ = 137.1 + 32.1 + 16.4 = 233(đvC)

PTK Ba(OH)₂ = 137.1 + 16.2 + 1.2 = 171(đvC)

PTK H₂SO₄ = 1.2 + 32.1 + 16.4 = 98 (đvC)

PTK Fe(NO₃)₂ = 56.1 + 14.2 + 16.6 = 180(đvC)

PTK Al₂O₃ = 27.2 + 16.3 = 102(đvC)

PTK Fe(OH)₃ = 56.1 + 16.3 + 1.3 = 107(đvC)

cho mình hỏi cái mấy bạn ơi

a.CuO, K₂O, P₂O_5, FeO

b.Ba(NO₃)₂, Cu(OH)₂, Fe₂(SO₄)₃

a) CTHH: P_xO_y

\(\dfrac{x}{y}=\dfrac{II}{III}=\dfrac{2}{3}\)

=> CTHH: P₂O₃

b) CTHH: N_xH_y

\(\dfrac{x}{y}=\dfrac{I}{III}=\dfrac{1}{3}\)

=> CTHH: NH₃

c) CTHH: Fe_xO_y

\(\dfrac{x}{y}=\dfrac{II}{II}=\dfrac{2}{2}\)

=> CTHH: FeO

CTHH: KNO₃

Ý nghĩa: 

- Hợp chất KNO₃ do nguyên tố K, N, O

- Gồm 1 K liên kết với 1 N và 3O

- PTK = 39 + 14 + 16 . 3 = 101 đvC

\(K_2NO_3\)

\(MgS,Mg\left(NO_3\right)_2,MgCO_3,Mg_3\left(PO_4\right)_2\)

\(Fe_2S_3,Fe\left(NO_3\right)_3,Fe_2\left(CO_3\right)_3,FePO_4\)

\(\left(NH_4\right)_2S,NH_4NO_3,\left(NH_4\right)_2CO_3,\left(NH_4\right)_3PO_4\)

mgs, mg(no3)2, mgco3, mg3(po4)2, 

Câu 1:

NO₂: IV

N₂O₃: III

N₂O₅: V

NH₃:III

Câu 2:

P₂O₃, NH₃, Fe₂O₃, Cu(OH)₂, Ca(NO₃)₂, Ag₂SO4, Ba₃(PO₄)₂, Fe₂(SO₄)₃, Al₂(SO₄)₃, NH₄NO₃

KNO₃ , Mg(NO₃)2, Al(NO₃)₃

MgSO₄, , K₂SO4,Al₂(SO4)₃

K₃PO4, Mg₂(PO4), AlPO₄

Câu 11:

\(a,Na_2O,MgO,SO_2,Al_2O_3,P_2O_5,CuO,CaO\\ b,KCl,BaCl_2,FeCl_3,ZnCl_2\\ c,Na_2SO_4,Al_2\left(SO_4\right)_3,CuSO_4,FeSO_4,ZnSO_4\)

Câu 7:

\(a,\) Gọi hóa trị Fe,Cu,SO₄ trong các HC lần lượt là x,y,z(x,y,z>0)

\(Fe_1^xCl_3^I\Rightarrow x=I\cdot3=3\Rightarrow Fe\left(III\right)\\ Fe_1^xO_1^{II}\Rightarrow x=II\cdot1=2\Rightarrow Fe\left(II\right)\\ Cu_2^yO_1^{II}\Rightarrow y=\dfrac{II\cdot1}{2}=1\Rightarrow Cu\left(I\right)\\ Cu_1^y\left(NO_3\right)_2^I\Rightarrow y=I\cdot2=2\Rightarrow Cu\left(II\right)\\ Na_2^I\left(SO_4\right)_1^z\Rightarrow z=I\cdot2=2\Rightarrow SO_4\left(II\right)\)

\(b,\) Gọi hóa trị S,N trong các HC lần lượt là a,b(a,b>0)

\(S_1^aO_3^{II}\Rightarrow a=II\cdot3=6\Rightarrow S\left(VI\right)\\ H_2^IS_1^a\Rightarrow a=I\cdot2=2\Rightarrow S\left(II\right)\\ N_2^bO_1^{II}\Rightarrow b=\dfrac{II\cdot1}{2}=1\Rightarrow N\left(I\right)\\ N_1^bO_1^{II}\Rightarrow b=II\cdot1=2\Rightarrow N\left(II\right)\\ N_1^bO_2^{II}\Rightarrow b=II\cdot2=4\Rightarrow N\left(IV\right)\\ N_2^bO_5^{II}\Rightarrow b=\dfrac{II\cdot5}{2}=5\Rightarrow N\left(V\right)\)