27 + 1 + 2010 = 2038

27 . (1 + 2010) = 54297

2010 - ( 27 . 1) = 1983

27 + 1 + 2010 = 2 038

27 . (1 + 2010) = 54 297

2010 - ( 27 . 1) = 1 983

=2038

=54297

=1983

= -15 + 27 + 1 x 1

= -15 + 27 + 1

= 13

tính :

a)\(\frac{459}{987}\cdot\left(\frac{1}{4}+\frac{1}{12}-\frac{1}{3}\right)-\frac{2009}{2010}\)

\(=\frac{459}{987}\cdot\left(\frac{3}{12}+\frac{1}{12}-\frac{4}{12}\right)-\frac{2009}{2010}\)

\(=\frac{459}{987}\cdot0-\frac{2009}{2010}\)

\(=\frac{-2009}{2010}\)

b) \(\frac{-9}{7}-\frac{5}{7}\cdot\left[\left(\frac{-2}{3}\right)^2-1\right]\div\frac{-5}{9}\)

\(=\frac{-9}{7}-\frac{5}{7}\cdot\left[\frac{4}{9}-1\right]\div\frac{-5}{9}\)

\(=\frac{-9}{7}-\frac{5}{7}\cdot\frac{-5}{9}\div\frac{-5}{9}\)

\(=\frac{-9}{7}-\frac{5}{7}\)

\(=-2\)

tìm x:

a) \(\left(x-\frac{7}{18}\right)-\frac{15}{27}=\frac{-10}{27}\)

\(\left(x-\frac{7}{18}\right)=\frac{-10}{27}+\frac{15}{27}\)

\(\left(x-\frac{7}{18}\right)=\frac{5}{27}\)

\(x=\frac{5}{27}+\frac{7}{18}\)

\(\Rightarrow x=\frac{31}{54}\)

b) \(\left(3\frac{1}{2}-2x\right)\cdot\frac{11}{3}=7\frac{1}{3}\)

\(\left(\frac{7}{2}-2x\right)\cdot\frac{11}{3}=\frac{22}{3}\)

\(\left(\frac{7}{2}-2x\right)=\frac{22}{3}\div\frac{11}{3}\)

\(\left(\frac{7}{2}-2x\right)=2\)

\(2x=\frac{7}{2}-2\)

\(x=\frac{3}{2}\div2=\frac{3}{4}\)

\(\Rightarrow x=\frac{3}{4}\)

\(\frac{-27}{5}.\frac{-4}{15}+\frac{-4}{15}.\left(2010+\frac{27}{5}\right)\)

\(=\frac{-4}{15}.\left(\frac{-27}{5}+2010+\frac{27}{5}\right)\)

\(=\frac{-4}{15}.2010\)

\(=-536\)

Học tốt

\(-\frac{27}{5}.\left(-\frac{4}{15}\right)+\left(-\frac{4}{15}\right).\left(2010-\frac{-27}{5}\right)\)

\(=\left(-\frac{4}{15}\right)\left(2010-\frac{-27}{5}+\frac{-27}{5}\right)\)

\(=-\frac{4}{15}.\left(2010+\frac{27}{15}-\frac{27}{15}\right)\)

\(=-\frac{4}{15}.2010=-536\)

Tính

\(-\frac{27}{5}.\frac{-4}{15}+\frac{-4}{15}\left(2010-\frac{-27}{5}\right)\)

\(=-\frac{27}{5}.\frac{-4}{15}+\frac{-4}{15}\left(\frac{10050}{5}+\frac{27}{5}\right)\)

\(=-\frac{27}{5}.\frac{-4}{15}+\frac{-4}{15}.\frac{10077}{5}\)

\(=-\frac{4}{15}\left(-\frac{27}{5}+\frac{10077}{5}\right)\)

\(=-\frac{4}{15}.2010=-536\)

\(\left|x+\frac{1}{3}\right|+\frac{4}{5}=\left|-3,2+\frac{2}{5}\right|+\left(27-\frac{3}{5}\right)\left(27-\frac{3^2}{6}\right)...\left(27-\frac{3^5}{9}\right)...\left(27-\frac{3^{2010}}{2014}\right)\)

\(\Leftrightarrow\left|x+\frac{1}{3}\right|+\frac{4}{5}=\frac{14}{5}+\left(27-\frac{3^2}{6}\right)\left(27-\frac{3^3}{7}\right)...\left(27-27\right)...\left(27-\frac{3^{2010}}{2014}\right)\)

\(\Leftrightarrow\left|x+\frac{1}{3}\right|+\frac{4}{5}=\frac{14}{5}\)

\(\Leftrightarrow\left|x+\frac{1}{3}\right|=2\)

\(\Rightarrow\hept{\begin{cases}x+\frac{1}{3}=2\\x+\frac{1}{3}=-2\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{5}{3}\\x=-\frac{7}{3}\end{cases}}}\)

bạn ơi, có một chỗ chưa chuẩn .bạn kiểm tra lại giú mình. chỗ vế trái bạn thiếu \(\left(27-\frac{3}{5}\right)\). bạn bổ sung vào cho đúng nhé. dù sao vẫn cảm ơn bạn.

\(3^x:27=3^{1000}\\ \Rightarrow3^x:3^3=3^{1000}\\ \Rightarrow3^{x-3}=3^{1000}\\ \Rightarrow x-3=1000\\ \Rightarrow x=1003\)

-Ta có: x=a/m=2a/2m=a+a/2m<a+b/2m=Z.Suy ra x<Z (1)

-Z=a+b/2m<b+b/2m=2b/2m=b/m=y.Suy ra Z<y (2)

-Từ (1) và (2).Suy ra x<Z<y

Bạn xem cho kĩ nha khéo nhầm tôi chắn bạn tưởng Z là một số, nhưng tôi queenghi chú thích Z là tập hợp.

Ta có: \(3^x:27=3^{2010}\)

\(\Leftrightarrow3^x=3^{2013}\)

Suy ra: x=2013

3^x : 27 = 3²⁰¹⁰

3^x = 3²⁰¹⁰ . 27

3^x = 3²⁰¹⁰ . 3³

3^x = 3²⁰¹³

x = 2013

Chúc bạn học tốt !

* Ta có: ( 2010 – 1000) – 2010

= 2010 – 1000 – 2010

=(2010 – 2010) – 1000

= 0 – 1000 = -1000

* Ta có: ( 427 – 2009 ) – (27 – 2009)

= 427 -2009 – 27 + 2009

= ( 427 – 27) + (2009 – 2009)

= 400 + 0 = 400

* Ta có: (-23) – (77 – 1000)

= (-23) – 77 + 1000

= [(-23) + (-77)] + 1000

= -100 +1000 = 900

Do đó, ta nối được bảng sau: