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1,x=6

3,x=-9

Toàn mấy bài trong Violympic 7 vòng 3 bài sắp xếp.

a) x = 1/4

b) x = 1/2

c) x = -1/4

Chọn C. Cặp x, y thỏa mãn là (-1;-6) hoặc (0;2).

1. \(\frac{-17}{21}:\left(\frac{5}{4}-\frac{2}{5}\right)< x+\frac{4}{7}< 1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\)

\(-\frac{17}{21}:\frac{17}{20}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{80}{84}< \frac{84x+48}{84}< \frac{49}{84}\)

\(-80< 84x+48< 49\)

\(\begin{cases}-80< 84x+48\\84x+48< 49\end{cases}\) 

\(\begin{cases}84x>-128\\84x< 1\end{cases}\)

\(\begin{cases}x>-\frac{32}{21}\\x< \frac{1}{84}\end{cases}\)

\(\Rightarrow-\frac{32}{21}< x< \frac{1}{84}\)

\(-\frac{17}{21}\div\left(\frac{5}{4}-\frac{2}{5}\right)< x+\frac{4}{7}< 1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\)

\(-\frac{20}{21}< x+\frac{4}{7}< \frac{7}{12}\)

\(-\frac{32}{21}< x< \frac{1}{84}\)

\(-1^{11}_{21}< x< \frac{1}{84}\)

\(\Rightarrow x\in\left\{-1;0\right\}\)

Vậy x = 0

\(\frac{4}{3}\times1,25\times\left(\frac{16}{5}-\frac{5}{16}\right)< 2x< 4-\frac{4}{3}+3-\frac{3}{2}+2\)

\(\frac{77}{16}< 2x< \frac{37}{6}\)

\(\frac{77}{32}< x< \frac{37}{12}\)

\(2^{13}_{32}< x< 3^1_{12}\)

=> x = 3

2. \(\frac{4}{3}.1,25\left(\frac{16}{5}-\frac{5}{16}\right)< 2x< 4-\frac{4}{3}+3-\frac{3}{2}+2\)

\(\frac{16}{15}.\frac{231}{80}< 2x< \frac{37}{6}\)

\(\frac{77}{25}< 2x< \frac{37}{6}\)

\(\begin{cases}\frac{77}{25}< 2x\\2x< \frac{37}{6}\end{cases}\)

\(\begin{cases}2x>\frac{77}{25}\\x< \frac{37}{12}\end{cases}\)

\(\begin{cases}x>\frac{77}{50}\\x< \frac{37}{12}\end{cases}\)

\(\frac{77}{50}< x< \frac{37}{12}\)

`x(x-1)(x-2)(x-3)=-2`

`<=>[x(x-3)][(x-1)(x-2)]=-2`

`<=>(x^2-3x)(x^2-3x+2)=-2`

Đặt `x^2-3x=t` khi đó ta có:

   `t(t+2)=-2`

`<=>t^2+2t+2=0`

`<=>t^2+2t+1+1=0`

`<=>(x+1)^2=-1` (Vô lí)

  `=>` Không có giá trị `x` t/m