a) {132 - [116- (16 - 8)]:2}.5

= [132 - (116 - 8): 2] .5

= (132 - 108 : 2). 54

= (132 - 54).5

= 78.5 = 390

b) 36: {136 : 200 - (12+ 8. 20)]}

= 36: {336 : [200 - ( 12 + 160)]}

= 36 : [336 : ( 200 - 172)

= 36 : ( 336 : 28) = 3

c) 86 - [15. (64 - 39): 75+11] 

= 86 - (15.25 : 75 + 11) 

= 86 - ( 5 + 11) 

= 70

d)  55 - [ 49 - ( 2 3 . 17 - 2 3 . 14 ) ]

= 55 - 49 - 2 3 . 3

= 55- ( 49 - 24)

= 30

a) {132 – [116 – (16 – 8)]:2}.5

= [132 – (116 – 8): 2] .5

= (132 – 108 : 2). 5

= (132 –54).5

= 78.5 = 390

b) 36: {136 : 200 – (12+ 8. 20)]}

= 36: {336 : [200 – ( 12 + 160)]}

= 36 : [336 : ( 200 – 172)

= 36 : ( 336 : 28)

= 36 : 12 = 3

c) 86 – [15. (64 - 39): 75+11]

= 86 – (15.25 : 75 + 11)

= 86 – ( 5 + 11)

= 70.

d) 55 – [49 – (2³ . 17 – 2³.14)]

= 55 – (49 – 2³ .3)

= 55 – ( 49 – 24)

= 30

ai lm tr mình cho tích

 a)12 x 11 + 21 x 11 x 11 + 11 x 33

= ( 12 x 11 ) + ( 21 x 11 x 11 ) + ( 11 x 33 )

= 

= 

b)132x11-11x32-54x11

= ( 132 x 11 ) - ( 11 x 32 ) - ( 54 x 11 )

= 

\(a,=11\times\left(12+21+33\right)=11\times66=726\\ b,=11\times\left(132-32-54\right)=11\times46=506\\ c,=11\times\left(245+365\right)=11\times610=6710\\ d,=75\times\left(78+89+123\right)=75\times290=21750\\ e,=\left(2\times50\right)\times\left(250\times8\right)=100\times2000=200000\\ g,=1994\times\left(867+11\right)=1994\times878=1750732\)

a) 12 x 11 + 21 x 11 + 11 x 33

= 11 x ( 12 + 21 + 33)

= 11 x 66

= 726

b) 132 x 11 - 11 x 32 - 54 x 11

= 11 x ( 132 - 32 - 54)

= 11 x 46

= 506

c) 245 x 11 + 11 x 365

= 11 x ( 245 + 365 )

= 11 x 610 = 6710

d) 78 x 75 + 75 x 89 + 75 x 123

= 75 x ( 78 + 89 + 123)

= 75 x 290 = 21750

e) 2 x 250 x 50 x 8

= (2 x 50) x ( 250 x 8)

= 100 x 2000 = 200000

g) 1994 x 867 + 1994 x 11

= 1994 x ( 867 + 11)

= 1994 x 878 = 1750732

\(A=\dfrac{5}{11}.\dfrac{5}{7}+\dfrac{5}{11}.\dfrac{2}{7}+\dfrac{6}{11}=\dfrac{5}{11}\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{6}{11}=\dfrac{5}{11}.1+\dfrac{6}{11}=\dfrac{5}{11}+\dfrac{6}{11}=\dfrac{11}{11}=1\)

\(B=\dfrac{3}{13}.\dfrac{6}{11}+\dfrac{3}{13}.\dfrac{9}{11}-\dfrac{3}{13}.\dfrac{4}{11}=\dfrac{3}{13}\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}.1=\dfrac{3}{13}\)

\(C=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right).0=0\)

thu gọn 7^3*7^5

Oh no nhiều kí tự đặc biệt quá

dễ quá mình ko làm  đc 

\(=\sqrt{3}-1-6\sqrt{3}+\sqrt{3}+1=-4\sqrt{3}\)

b, \(\dfrac{4}{9}\) + \(\dfrac{6}{11}\) + \(\dfrac{5}{9}\) + \(\dfrac{16}{11}\) + 7

= (\(\dfrac{4}{9}\) + \(\dfrac{5}{9}\)) + (\(\dfrac{6}{11}\) + \(\dfrac{16}{11}\)) + 7

= 1 + 2 + 7

= 10

a, Đáng lẽ đề phải là:

0,2 x 517 x 7 + 0,7 x 483 x 2 em ạ