\(a.\dfrac{-3}{8}-\dfrac{13}{65}+\dfrac{3}{8}=\left(\dfrac{3}{8}-\dfrac{3}{8}\right)-\dfrac{13}{65}=-\dfrac{13}{65}\)

\(b.\left(\dfrac{-13}{7}-\dfrac{4}{9}\right)-\left(-\dfrac{10}{7}-\dfrac{4}{9}\right)=\dfrac{-13}{7}-\dfrac{4}{9}+\dfrac{10}{7}+\dfrac{4}{9}\\ =\left(\dfrac{-13}{7}+\dfrac{10}{7}\right)+\left(\dfrac{4}{9}-\dfrac{4}{9}\right)=-\dfrac{3}{7}\)

\(c.17\dfrac{1}{3}\cdot\left(\dfrac{-3}{7}\right)+3\dfrac{2}{3}\cdot\left(\dfrac{-3}{7}\right)=\dfrac{-3}{7}\cdot\left(17\dfrac{1}{3}+3\dfrac{2}{3}\right)\\ =\dfrac{-3}{7}\cdot\left(\dfrac{52}{3}+\dfrac{11}{3}\right)=\dfrac{-3}{7}\cdot21=-9\)

B=\(\frac{5}{7}\).\(\frac{-4}{13}\)+\(\frac{5}{7}\).\(\frac{7}{13}\)-\(\frac{5}{13}\).\(\frac{3}{7}\)

B=5/7.-4/13+5/7.7/13-3/13.5/7(dùng tính chất đổi chỗ tử số trong 1 tích)

B=5/7.(-4/13+7/13-3/13) (tính chất kết hợp)

B=5/7.0 (tính chất nhân với 0)

B=0

CHÚC BẠN HỌC GIỎI

K MÌN NHÉ

\(B=\frac{5}{7}.\frac{-4}{13}+\frac{5}{7}.\frac{7}{13}-\frac{5}{13}.\frac{3}{7}\)

\(=\frac{5}{7}.\frac{-4}{13}+\frac{5}{7}.\frac{7}{13}-\frac{5}{7}.\frac{3}{13}\)

\(=\frac{5}{7}.\left(\frac{-4}{13}+\frac{7}{13}-\frac{3}{13}\right)\)

\(=\frac{5}{7}.0\)

\(=0\)

\(=\dfrac{7}{11}\left(\dfrac{5}{13}+\dfrac{8}{13}\right)-3-\dfrac{7}{11}=-3\)

\(\text{Phần a nên sửa đề thế này :}\) \(\frac{1}{7}.\frac{-3}{8}+\frac{1}{7}.\frac{-13}{8}\)

\(\text{Giải :}\)

\(\frac{1}{7}.\frac{-3}{8}+\frac{1}{7}.\frac{-13}{8}\)

\(=\frac{1}{7}\left(\frac{-3}{8}+\frac{-13}{8}\right)\)

\(=\frac{1}{7}.\left(-2\right)\)

\(=\frac{-2}{7}\)

\(\frac{3}{5}.\frac{13}{46}-\frac{1}{10}.\frac{16}{23}\)

\(=\frac{3}{5}.\left(\frac{1}{46}.13\right)-\frac{1}{10}.\frac{32}{46}\)

\(=\left(\frac{3}{5}.13\right).\frac{1}{46}-\left(\frac{1}{10}.32\right).\frac{1}{46}\)

\(=\frac{39}{5}.\frac{1}{46}-\frac{32}{10}.\frac{1}{46}\)

\(=\frac{78}{10}.\frac{1}{46}-\frac{32}{10}.\frac{1}{46}\)

\(=\left(\frac{78}{10}-\frac{32}{10}\right).\frac{1}{46}\)

\(=\frac{46}{10}.\frac{1}{46}\)

\(=\frac{1}{10}\)

khó nhìn quá e chỉnh lại đi nha

a 7

b -6800

a: =(-3+3)+(7+13)+(-9+50-54)

=20-13

=7

b: \(=-8\cdot21+8\cdot13-8\cdot72-80\cdot21+80\cdot76-80\cdot132\)

=-6800

a: =(-3+3)+(7+13)+(-9+50-54)

=20-13

=7

b: 

=-6800

\(A=\frac{-3}{7}+\frac{14}{23}+\frac{-14}{17}+\frac{9}{23}-\frac{5}{19}\)

\(\Rightarrow A=-\frac{3}{7}+\left(\frac{14}{23}+\frac{9}{23}\right)-\frac{14}{17}-\frac{5}{19}\)

\(\Rightarrow A=\frac{-3}{7}+1-\frac{14}{17}-\frac{5}{19}\)

Tính nốt nhé

\(B=\frac{5}{9}.\frac{7}{13}.\frac{5}{9}.\frac{9}{13}.\left(-\frac{5}{13}\right).\frac{3}{9}\)

Tương tự câu A

AI GIÚP EM VỚI Ạ

\(#N\)

\(-\dfrac{11}{7}+\dfrac{13}{-2}+-\dfrac{6}{17}=-\dfrac{113}{14}+-\dfrac{6}{17}=-\dfrac{2005}{238}\)

\(\dfrac{13}{-8}+-\dfrac{7}{20}+\dfrac{3}{-8}=\left(-\dfrac{13}{8}+-\dfrac{3}{8}\right)+-\dfrac{7}{20}=-2+-\dfrac{7}{20}=-\dfrac{47}{20}\)

\(-\dfrac{4}{7}+\dfrac{11}{5}+\dfrac{1}{5}+-\dfrac{7}{3}=-\dfrac{4}{7}+\left(\dfrac{11}{5}+\dfrac{1}{5}\right)+-\dfrac{7}{3}=-\dfrac{4}{7}+\dfrac{12}{5}+-\dfrac{7}{3}=-\dfrac{53}{105}\)

\(\dfrac{6}{13}.\dfrac{5}{7}+\dfrac{6}{13}.\dfrac{2}{7}+\dfrac{7}{13}=\dfrac{6}{13}.\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{7}{13}=\dfrac{6}{13}.1+\dfrac{7}{13}=\dfrac{6}{13}+\dfrac{7}{13}=\dfrac{13}{13}=1\)

#Monster

\(\dfrac{6}{13}\).(\(\dfrac{2}{7}+\dfrac{5}{7}\))+\(\dfrac{7}{13}\)

\(\dfrac{6}{13}\).1+\(\dfrac{7}{13}\)

\(\dfrac{6}{13}\)+\(\dfrac{7}{13}\)

1

mik làm ở bài dưới rồi nha.