a)\(\dfrac{x-2}{x+3}=\dfrac{3}{4}\) b)-1,04:x=18,72:16,38
Những câu hỏi liên quan
Tìm x trong tỉ lệ thức
a) -0,52:x-9,36:16,38
b) 2dfrac{2}{5}:x1dfrac{7}{9}:0,2
c)left(dfrac{2}{5}xright):dfrac{1}{3}1dfrac{1}{3}:dfrac{4}{5}
d) 0,3:1dfrac{1}{3}dfrac{2}{5}:left(3x+6right)
e) dfrac{x}{-15}dfrac{-60}{x}
f) dfrac{x-1}{-15}dfrac{-60}{x-1}
g) dfrac{x-1}{7}dfrac{9}{x+1}
h) dfrac{x-2}{x-1}dfrac{x+4}{x+7}
Đọc tiếp
Tìm x trong tỉ lệ thức
a) \(-0,52:x=-9,36:16,38\)
b) \(2\dfrac{2}{5}:x=1\dfrac{7}{9}:0,2\)
c)\(\left(\dfrac{2}{5}x\right):\dfrac{1}{3}=1\dfrac{1}{3}:\dfrac{4}{5}\)
d) \(0,3:1\dfrac{1}{3}=\dfrac{2}{5}:\left(3x+6\right)\)
e) \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
f) \(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\)
g) \(\dfrac{x-1}{7}=\dfrac{9}{x+1}\)
h) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
Tìm x trong tỉ lệ thức
a) −0,52 : x = −9,36 : 16,38
\(\dfrac{-0.52}{x}=\dfrac{-9.36}{16.38}=-\dfrac{4}{7}\\ \Rightarrow x=\dfrac{7.\left(-0.52\right)}{-4}=\dfrac{91}{100}=0.91\)
Đúng 0
Bình luận (0)
Tìm \(x\) trong các tỉ lệ thức sau :
a) \(\dfrac{x}{27}=\dfrac{-2}{3,6}\)
b) \(-0,52:x=-9,36:16,38\)
c) \(\dfrac{4\dfrac{1}{4}}{2\dfrac{7}{8}}=\dfrac{x}{1,61}\)
a) \(\dfrac{x}{27}=\dfrac{-2}{3,6}\)
=> x. 3,6 = 27. (-2)
=> x.3,6 = -54
x = (-54) : 3,6
x = -15
b) -0,52 : x = -9,36 : 16,38
- 0,52 : x = \(\dfrac{-4}{7}\)
x = \(\dfrac{-4}{7}\) . ( -0,52)
x = \(\dfrac{52}{175}\)
Đúng 0
Bình luận (2)
Lời giải:
a)
b)
-0,52 : x = -9,36: 16,38 => -0,52 . 16,38 = x. (-9,36) => x = -8,5176: ( -9,36) => x = 0,91
c)
Đúng 0
Bình luận (1)
a)\(\dfrac{x}{27}=\dfrac{-2}{3,6}\)
=>x.3,6=27.(-2)
=>x . 3,6=-54
=>x=-54:3.6
=>x=-54:\(\dfrac{18}{5}\)
=>x=-54.\(\dfrac{5}{18}\)
=>x=-15
b)-0,52:x=-9,36:16,38
-\(\dfrac{13}{25}:x=-\dfrac{234}{25}:\dfrac{819}{50}\)
\(-\dfrac{13}{25}:x=-\dfrac{4}{7}\)
\(x=-\dfrac{4}{7}:\left(-\dfrac{13}{25}\right)\)
x=\(\dfrac{52}{175}\)
c)\(\dfrac{4\dfrac{1}{4}}{2\dfrac{7}{8}}=\dfrac{x}{1,61}\)
\(\dfrac{\dfrac{17}{4}}{\dfrac{23}{8}}=\dfrac{x}{1,61}\)
\(\dfrac{17}{4}:\dfrac{23}{8}=\dfrac{x}{1,61}\)
\(\dfrac{17}{4}.\dfrac{8}{23}=\dfrac{x}{1,61}\)
\(\dfrac{34}{23}=\dfrac{x}{1,61}\)
=>34.1,61=x.23
rồi bạn tự tính tự làm nốt nhé
Đúng 0
Bình luận (1)
Xem thêm câu trả lời
a,(\(\dfrac{4}{5}+\dfrac{2}{3}\)) x 2 x \(\dfrac{3}{4}\)
b,\(\dfrac{4}{5}\) x \(\dfrac{2}{3}\) x \(\dfrac{3}{4}\)
Rút gọn biểu thức:A [(32)^{dfrac{2}{3}}]^{dfrac{-2}{5}}B dfrac{x^{-2}+y^{-2}}{x^{-1}+y^{-1}}C (a^{dfrac{1}{3}}-b^{dfrac{2}{3}})(a^{dfrac{2}{3}}+a^{dfrac{1}{3}}×b^{dfrac{4}{3}}+b^{dfrac{4}{9}})D (x+y^dfrac{3}{2}÷sqrt{x})^dfrac{2}{3}÷[dfrac{sqrt{x}-sqrt{y}}{sqrt{x}}+dfrac{sqrt{y}}{sqrt{x}-sqrt{y}}]^dfrac{2}{3}E [dfrac{1}{x^{dfrac{1}{2}}-4x^{dfrac{-1}{2}}}-dfrac{2sqrt[3]{x}}{xsqrt[3]{x}-4sqrt[3]{x}}]^{-2}-sqrt{x^2+8x+16}
Đọc tiếp
Rút gọn biểu thức:
A = \([(32)^{\dfrac{2}{3}}]^{\dfrac{-2}{5}}\)
B= \(\dfrac{x^{-2}+y^{-2}}{x^{-1}+y^{-1}}\)
C = \((a^{\dfrac{1}{3}}-b^{\dfrac{2}{3}})(a^{\dfrac{2}{3}}+a^{\dfrac{1}{3}}×b^{\dfrac{4}{3}}+b^{\dfrac{4}{9}})\)
D = \((x+y^\dfrac{3}{2}÷\sqrt{x})^\dfrac{2}{3}÷[\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{x}}+\dfrac{\sqrt{y}}{\sqrt{x}-\sqrt{y}}]^\dfrac{2}{3}\)
E = \([\dfrac{1}{x^{\dfrac{1}{2}}-4x^{\dfrac{-1}{2}}}-\dfrac{2\sqrt[3]{x}}{x\sqrt[3]{x}-4\sqrt[3]{x}}]^{-2}-\sqrt{x^2+8x+16}\)
Bài 6: Tìm x, biết
a) dfrac{3}{2} x dfrac{4}{5} - X dfrac{2}{3}
b) X x 3dfrac{1}{3} 3dfrac{1}{3} : 4dfrac{1}{4}
c) 5dfrac{2}{3} : x 3dfrac{2}{3} - 2dfrac{1}{2}
Đọc tiếp
Bài 6: Tìm x, biết
a) \(\dfrac{3}{2}\) x \(\dfrac{4}{5}\) - X =\(\dfrac{2}{3}\)
b) X x 3\(\dfrac{1}{3}\) = 3\(\dfrac{1}{3}\) : 4\(\dfrac{1}{4}\)
c) 5\(\dfrac{2}{3}\) : x = 3\(\dfrac{2}{3}\) - 2\(\dfrac{1}{2}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\dfrac{3}{2}\times\dfrac{4}{5}-x=\dfrac{2}{3}\)
\(\dfrac{6}{5}-x=\dfrac{2}{3}\)
\(x=\dfrac{6}{5}-\dfrac{2}{3}\)
\(x=\dfrac{18}{15}-\dfrac{10}{15}\)
\(x=\dfrac{8}{15}\)
Vậy, `x =`\(\dfrac{8}{15}\)
`b)`
\(x\times3\dfrac{1}{3}=3\dfrac{1}{3}\div4\dfrac{1}{4}\)
\(x\times\dfrac{10}{3}=\dfrac{40}{51}\)
\(x=\dfrac{40}{51}\div\dfrac{10}{3}\)
\(x=\dfrac{4}{17}\)
Vậy, \(x=\dfrac{4}{17}\)
`c)`
\(5\dfrac{2}{3}\div x=3\dfrac{2}{3}-2\dfrac{1}{2}\)
\(\dfrac{17}{3}\div x=\dfrac{7}{6}\)
\(x=\dfrac{17}{3}\div\dfrac{7}{6}\)
\(x=\dfrac{34}{7}\)
Vậy, `x = `\(\dfrac{34}{7}\)
Đúng 1
Bình luận (0)
a) \(\dfrac{3}{2}x\dfrac{4}{5}-x=\dfrac{2}{3}\Rightarrow\dfrac{6}{5}-x=\dfrac{2}{3}\Rightarrow x=\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18}{15}-\dfrac{10}{15}=\dfrac{8}{15}\)
b) \(x.3\dfrac{1}{3}=3\dfrac{1}{3}:4\dfrac{1}{4}\Rightarrow\dfrac{10}{3}.x=\dfrac{10}{3}:\dfrac{17}{4}\Rightarrow\dfrac{10}{3}.x=\dfrac{10}{3}.\dfrac{4}{17}\Rightarrow x=\dfrac{10}{3}.\dfrac{4}{17}:\dfrac{10}{3}=\dfrac{10}{3}.\dfrac{4}{17}.\dfrac{3}{10}=\dfrac{4}{17}\)
c) \(5\dfrac{2}{3}:x=3\dfrac{2}{3}-2\dfrac{1}{2}\Rightarrow\dfrac{17}{3}:x=\dfrac{11}{3}-\dfrac{5}{2}\Rightarrow\dfrac{17}{3}:x=\dfrac{22}{6}-\dfrac{15}{6}\Rightarrow\dfrac{17}{3}:x=\dfrac{7}{6}\Rightarrow x=\dfrac{17}{3}:\dfrac{7}{6}=\dfrac{17}{3}.\dfrac{7}{6}=\dfrac{119}{18}\)
Đúng 0
Bình luận (0)
Tìm x, biết:
a) dfrac{2}{5} + dfrac{3}{4}: x dfrac{-1}{2}
b) dfrac{5}{7} - dfrac{2}{3} . x dfrac{4}{5}
c) dfrac{1}{2} x + dfrac{2}{3} x dfrac{-2}{3}
d) dfrac{4}{7}x - x dfrac{-9}{14}
Đọc tiếp
Tìm x, biết:
a) \(\dfrac{2}{5}\) + \(\dfrac{3}{4}\): x = \(\dfrac{-1}{2}\)
b) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) . x = \(\dfrac{4}{5}\)
c) \(\dfrac{1}{2}\) x + \(\dfrac{2}{3}\) x = \(\dfrac{-2}{3}\)
d) \(\dfrac{4}{7}\)x - x= \(\dfrac{-9}{14}\)
a, 2/5 + 3/4 : x = -1/2
3/4 : x = -1/2 - 2/5
3/4 : x = -9/10
x = 3/4 : -9/10
x = -5/6
Đúng 7
Bình luận (0)
b, 5/7 - 2/3 . x = 4/5
2/3 . x = 4/5 + 5/7
2/3 . x = 53/35
x = 53/35 : 2/3
x = 159/70
Đúng 6
Bình luận (0)
c và d mình làm dược nhưng ko ghi được cái suy ra
Đúng 6
Bình luận (0)
Xem thêm câu trả lời
Bài 2 Tìm x
a) 4\(\dfrac{2}{3}:x-\dfrac{3}{5}=\dfrac{4}{3}\)
b) \(\dfrac{4}{3}+2\dfrac{1}{2}\)x \(X=2\)
c) \(X:3\dfrac{1}{3}=2\dfrac{2}{5}+\dfrac{7}{10}\)
a) ....
=> 14/3 : x = 4/3 + 3/5 = 29/15
=> x = 14/3 : 29/15 = 70/29
b) ...
=> 4/3 + 5/2x = 2
=> 5/2x = 2 - 4/3 = 2/3
=> x = 2/3 : 5/2 = 4/15
c)...
=> x : 10/3 = 31/10
=> x = 31/10 x 10/3 = 31/3
Đúng 2
Bình luận (0)
Tìm x:
a) dfrac{11}{12} - (dfrac{2}{5} + dfrac{3}{4}x) dfrac{2}{3}
b) dfrac{-2}{5} + dfrac{5}{3} . (dfrac{3}{2} - dfrac{4}{15}x) dfrac{-7}{6}
c) dfrac{1}{2} + dfrac{3}{4}x dfrac{1}{4}
Đọc tiếp
Tìm x:
a) \(\dfrac{11}{12}\) - (\(\dfrac{2}{5}\) + \(\dfrac{3}{4}\)x) \(\dfrac{2}{3}\)
b) \(\dfrac{-2}{5}\) + \(\dfrac{5}{3}\) . (\(\dfrac{3}{2}\) - \(\dfrac{4}{15}\)x) = \(\dfrac{-7}{6}\)
c) \(\dfrac{1}{2}\) + \(\dfrac{3}{4}\)x = \(\dfrac{1}{4}\)
`#3107`
a)
\(\dfrac{11}{12}-\left(\dfrac{2}{5}+\dfrac{3}{4}x\right)=\dfrac{2}{3}?\\ \Rightarrow\dfrac{2}{5}+\dfrac{3}{4}x=\dfrac{11}{12}-\dfrac{2}{3}\\ \Rightarrow\dfrac{2}{5}+\dfrac{3}{4}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{4}-\dfrac{2}{5}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{3}{20}\\ \Rightarrow x=-\dfrac{3}{20}\div\dfrac{3}{4}\\ \Rightarrow x=-\dfrac{1}{5}\)
Vậy, \(x=-\dfrac{1}{5}\)
b)
\(\dfrac{-2}{5}+\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}\\ \Rightarrow\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}-\dfrac{-2}{5}\\ \Rightarrow\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=-\dfrac{23}{30}\\ \Rightarrow\dfrac{3}{2}-\dfrac{4}{15}x=-\dfrac{23}{30}\div\dfrac{5}{3}\\ \Rightarrow\dfrac{3}{2}-\dfrac{4}{15}x=-\dfrac{23}{50}\\ \Rightarrow\dfrac{4}{15}x=\dfrac{3}{2}-\left(-\dfrac{23}{50}\right)\\ \Rightarrow\dfrac{4}{15}x=\dfrac{49}{25}\\ \Rightarrow x=\dfrac{147}{20}\)
Vậy, \(x=\dfrac{147}{20}\)
c)
\(\dfrac{1}{2}+\dfrac{3}{4}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{4}-\dfrac{1}{2}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{1}{4}\\ \Rightarrow x=-\dfrac{1}{4}\div\dfrac{3}{4}\\ \Rightarrow x=-\dfrac{1}{3}\)
Vậy, \(x=-\dfrac{1}{3}.\)
\(#Emyeu1aithatroi...\)
Đúng 1
Bình luận (0)
(2/5 + 3/4 . x)= 11/12 -2/3
(2/5 +3/4 . x)= 1/4
3/4 . x = 1/4 - 2/5
3/4 . x = -3/20
x = -3/20 : 3/4
x = -1/5
Vậy .....
Đúng 0
Bình luận (0)
a) dfrac{x^2-x}{x-2}+dfrac{4-3x}{x-2}
b) dfrac{a+2b}{3a-b}+dfrac{2a-5b}{b-3a}
c) dfrac{2}{x^2-9}+dfrac{1}{x+3}
d) dfrac{4x}{x^2-4}+dfrac{x}{x+2}+dfrac{2}{x-2}
e) dfrac{3x^2-x+3}{x^3-1}+dfrac{1-x}{x^2+x+1}+dfrac{2}{1-x}
f) dfrac{1}{x^2+3x+2}+dfrac{1-x}{x^2+x+1}+dfrac{2}{1-x}
g) dfrac{a^3}{left(a-bright)left(a-cright)}+dfrac{b^3}{left(b-aright)left(b-cright)}+dfrac{c^3}{left(c-aright)left(c-bright)}
h) dfrac{1}{1-x}+dfrac{1}{1+x}+dfrac{2}{1+x^2}+dfrac{4}{1+x^4}+dfrac{8}{1+x^8}
Đọc tiếp
a) \(\dfrac{x^2-x}{x-2}+\dfrac{4-3x}{x-2}\)
b) \(\dfrac{a+2b}{3a-b}+\dfrac{2a-5b}{b-3a}\)
c) \(\dfrac{2}{x^2-9}+\dfrac{1}{x+3}\)
d) \(\dfrac{4x}{x^2-4}+\dfrac{x}{x+2}+\dfrac{2}{x-2}\)
e) \(\dfrac{3x^2-x+3}{x^3-1}+\dfrac{1-x}{x^2+x+1}+\dfrac{2}{1-x}\)
f) \(\dfrac{1}{x^2+3x+2}+\dfrac{1-x}{x^2+x+1}+\dfrac{2}{1-x}\)
g) \(\dfrac{a^3}{\left(a-b\right)\left(a-c\right)}+\dfrac{b^3}{\left(b-a\right)\left(b-c\right)}+\dfrac{c^3}{\left(c-a\right)\left(c-b\right)}\)
h) \(\dfrac{1}{1-x}+\dfrac{1}{1+x}+\dfrac{2}{1+x^2}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}\)
a, \(\dfrac{x^2-x}{x-2}+\dfrac{4-3x}{x-2}\)
\(=\dfrac{x^2-x+4-3x}{x-2}=\dfrac{x^2-4x+4}{x-2}\)
Đúng 0
Bình luận (0)
c) \(\dfrac{2}{x^2-9}+\dfrac{1}{x+3}\)
Ta có: \(\dfrac{1}{x+3}=\dfrac{1\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}=\dfrac{x-3}{x^2-9}\)
\(\Rightarrow\dfrac{2}{x^2-9}+\dfrac{1}{x+3}=\dfrac{2}{x^2-9}+\dfrac{x-3}{x^2-9}=\dfrac{2+x-3}{x^2-9}=\dfrac{x-1}{x^2-9}\)
Đúng 0
Bình luận (0)
b: \(=\dfrac{a+2b}{3a-b}-\dfrac{2a-5b}{3a-b}\)
\(=\dfrac{a+2b-2a+5b}{3a-b}=\dfrac{-a+7b}{3a-b}\)
c: \(=\dfrac{2+x-3}{\left(x+3\right)\left(x-3\right)}=\dfrac{x+1}{\left(x+3\right)\left(x-3\right)}\)
d: \(=\dfrac{4x+x^2-2x+2x+4}{\left(x+2\right)\left(x-2\right)}=\dfrac{x^2+4x+4}{\left(x+2\right)\left(x-2\right)}=\dfrac{x+2}{x-2}\)
e: \(=\dfrac{3x^2-x+3+1-2x+x^2-2x^2-2x-2}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(=\dfrac{2x^2-5x+2}{\left(x-1\right)\left(x^2+x+1\right)}\)
Đúng 0
Bình luận (0)