142*3+425*5+752/4?
Đặt tính rồi tính :
567 − 425 738 − 207
752 − 140 865 − 814
Phương pháp giải:
- Đặt tính: Viết phép tính sao cho các chữ số cùng hàng thẳng cột với nhau.
- Tính: Trừ các số lần lượt từ phải sang trái.
Lời giải chi tiết:
4+3*5/2-5+69*754-425*13-139*2+67/25*796-425+4652*2439/3341+342/653894-426*46341
= 49629,83799- 19741266= - 19691636,16
Trong các số 75, 120, 365, 752, 565 số chia hết cho cả 3 và 5 là:
A.752, 120 B. 365, 565 C. 75, 365 D. 120, 75
giúp em nha
142*4+142*5+142
\(142\times4+142\times5+142=142\times\left(4+5+1\right)=142\times10=1420\)
tính bằng cách thuận tiện nhất
5,5+3/4-5+1/4
5/2x2/3+1/4:3/2
tính x ;
435-[ x +16]=425: 17
x x 1/4-3/4=6:3/4
x +2 3/4=5 2/3
5,5 + \(\dfrac{3}{4}\) - 5 + \(\dfrac{1}{4}\)
(5,5 - 5) + (\(\dfrac{3}{4}\) + \(\dfrac{1}{4}\))
= 0,5 + 1
= 1,5
\(\dfrac{5}{2}\) x \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) : \(\dfrac{3}{2}\)
= \(\dfrac{5}{2}\) x \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) x \(\dfrac{2}{3}\)
= (\(\dfrac{5}{2}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)
= (\(\dfrac{10}{4}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)
= \(\dfrac{11}{4}\) x \(\dfrac{2}{3}\)
= \(\dfrac{11}{6}\)
Tính \(x\):
435 - [\(x\) + 16] = 425 : 17
435 - [\(x\) + 16] = 25
[\(x\) + 16] = 435 - 25
\(x\) + 16 = 410
\(x\) = 410 - 16
\(x\) = 394
\(x\) x \(\dfrac{1}{4}\) - \(\dfrac{3}{4}\) = 6 : \(\dfrac{3}{4}\)
\(x\) \(\times\) \(\dfrac{1}{4}\) - \(\dfrac{3}{4}\) = 6 x \(\dfrac{4}{3}\)
\(x\) x \(\dfrac{1}{4}\) - \(\dfrac{3}{4}\) = 8
\(x\) x \(\dfrac{1}{4}\) = 8 + \(\dfrac{3}{4}\)
\(x\) x \(\dfrac{1}{4}\) = \(\dfrac{32}{4}\) + \(\dfrac{3}{4}\)
\(x\) x \(\dfrac{1}{4}\) = \(\dfrac{35}{4}\)
\(x\) = \(\dfrac{35}{4}\) : \(\dfrac{1}{4}\)
\(x\) = \(\dfrac{35}{4}\) x 4
\(x\) = 35
tìm X
435 - ( x +16 ) = 425 : 17
(x + 3/4 ) * 7/4 +7 /6 =5
a) \(435-\left(x+16\right)=425:17\)
\(435-\left(x+16\right)=25\)
\(x+16=435-25\)
\(x+16=410\)
\(x=410-16\)
\(x=394\)
b) \(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(x+\frac{3}{4}=\frac{23}{6}:\frac{7}{4}\)
\(x+\frac{3}{4}=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{3}{4}\)
\(x=\frac{121}{84}\)
435 - ( x + 16 ) = 425 : 17
435 - ( x + 16 ) = 25
x + 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
\(435-\left(x+16\right)=425\div17\)
\(435-\left(x+16\right)=25\)
\(x+16=435-25\)
\(x+16=410\)
\(x=410-16\)
\(x=394\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)
\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x\times\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(x+\frac{3}{4}=\frac{23}{6}\div\frac{7}{4}\)
\(x\times\frac{3}{4}=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{3}{4}\)
\(x=\frac{121}{84}\)
\(\)
bài tìm x
a) 435 - ( x + 16 ) = 425 : 17
b) ( x + 4/3 ) * 7/4 = 5 - 7/6
a) \(435-\left(x+16\right)=425:17\)
\(435-\left(x+16\right)=25\)
\(\Rightarrow x+16=435-25=410\)
\(\Rightarrow x=410-16=394\)
b) \(\left(x+\frac{4}{3}\right)\cdot\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{4}{3}\right)\cdot\frac{7}{4}=\frac{23}{6}\)
\(\Rightarrow x+\frac{4}{3}=\frac{23}{6}:\frac{7}{4}=\frac{46}{21}\)
\(\Rightarrow x=\frac{46}{21}-\frac{4}{3}=\frac{6}{7}\)
Ủng hộ mk nka!!!^_^^_^^_^
a) 435 - ( x + 16 ) = 25
x+ 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
b) (x+4/3 ) * 7/4 = 23/6
x+4/3= 23/6 : 7/4
x+4/3 = 46/21
x = 46/21 - 4/3
x = 6/7
435-(x+16)=425:17
435-(x+16)=25
x+16 =435-25
x+16 =410
x =394
b) \(\left(x+\frac{4}{3}\right)\times\frac{7}{4}=5-\frac{7}{6}\)
\(\left(x+\frac{4}{3}\right)\times\frac{7}{4}=\frac{23}{6}\)
\(\left(x+\frac{4}{3}\right)=\frac{23}{6}:\frac{7}{4}\)
\(\left(x+\frac{4}{3}\right)=\frac{46}{21}\)
\(x=\frac{46}{21}-\frac{4}{3}\)
\(x=\frac{6}{7}\)
T mk nha bạn ^...^ !!!
Làm tính chia:
a) 8 4 : 8 - 3 b) 5 3 6 : 5 3 4 ;
c) ( - 18 ) 4 : 9 4 ; d) 6 5 2 : 7 5 2 .
tìm số dư trong phép chia ( theo Ptp đồng dư) a)1^5+3^5+5^5+....+75^5+99^5:4 b) 35^2 -35^3+35^4-35^8+35^16+35^32:425
a) \(S=1^5+3^5+....+75^5+99^5\)
\(\left(2a+1\right)^5-\left(2a+1\right)=2a\left(2a+1\right)\left(2a+2\right)\left[\left(2a+1\right)^2+1\right]\)
\(\left(2a+1\right)^5-\left(2a+1\right)=4a\left(2a+1\right)\left(a+1\right)\left[\left(2a+1\right)^2+1\right]⋮4\)
\(S=\left(1^5-1\right)+\left(3^5-3\right)+....+\left(75^5-75\right)+\left(99^5-99\right)+\left(1+3+5+...+75+99\right)\)
\(\Leftrightarrow\begin{matrix}1^5-1⋮4\\3^5-3⋮4\\5^5-5⋮4\\...........\\75^5-5⋮4\\99^5-99⋮4\end{matrix}\)
\(S_1=1+3+5+7+...+75+99=\frac{\left(1+75\right)\left[\frac{75-1}{2}+1\right]}{2}+99=38.38+96+3\)
\(\Rightarrow S_1:4\) dư 3
\(\Leftrightarrow S\) chia 4 dư 3