Ta có: \(B=\left|x-\dfrac{1}{7}\right|-\left|x+\dfrac{3}{5}\right|+\dfrac{4}{5}\)

\(=-x+\dfrac{1}{7}-x-\dfrac{3}{5}+\dfrac{4}{5}\)

\(=-2x+\dfrac{12}{35}\)

a) ( x - 3 ) ( x + 7 ) - ( x + 5 ) ( x - 1 )

= ( x² +7x - 3x - 21 ) - ( x² -x + 5x - 5 )

= x² + 4x -21 - x² - 4x +5

= -16

a: Ta có: \(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)\)

\(=x^2+4x-21-x^2-4x+5\)

=-16

=4x^2-4x+1+x^2+6x+9-5x^2+245

=2x+255

=x²+4x-21-(x²+4x-5)

=x²+4x-21-x²-4x+5

=-16

\(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)=x^2+7x-3x-21-x^2+x-5x+5\)

\(=-16\)

\(\left(x-5\right)\left(2x+3\right)-2x\left(x-3\right)+x-7\)

\(=\left(2x^2+3x-10x-15\right)-\left(2x^2-6x\right)+x-7\)

\(=2x^2-7x-15-2x^2+6x+x-7\)

\(=-22\)

\(\left(x-5\right)\left(2x+3\right)-2x\left(x-3\right)+x-7\)

\(=2x^2+3x-10x-15-\left(2x^2-6\right)+x-7\)

\(=2x^2+3x-10x-15-2x^2+6x+x-7\)

\(=\left(2x^2-2x^2\right)+\left(3x-10x+6x+x\right)-15-7\)

\(=-22\)

\(\hept{\begin{cases}\frac{x^2}{2}-\frac{1}{2}=y\left(1-x-y\right)\\x\left(3x+2y-2\right)=y^2-y+5\end{cases}}\)

`Answer:`

`a)`

`A=5(x+1)^2-3(x-3)^2-4(x^2-4)`

`=>A=5(x^2+2x+1)-3(x^2-6x+9)-4x^2+16`

`=>A=5x^2+10x+5-3x^2+18x-27-4x^2+16`

`=>A=(5x^2-3x^2-4x^2)+(10x+18x)+(5-27+16)`

`=>A=-2x^2+28x-6`

`b)`

`B=5(x+1)^2-3(x-3)^2-4(x+2)(x-2)`

`=2x(3x+5)-3(3x+5)-2x(x^2-4x+4)-[(2x)^2-3^2]`

`=6x^2+10x-9x-15-2x^3+8x^2-8x-4x^2+9`

`=(6x^2-4x^2+8x^2)-2x^3+(10x-9x-8x)+(-15+9)`

Thay `x=-7` vào ta được:

`B=10(-7)^2-2(-7)^3-7(-7)-6`

`=>B=10.49-2(-343)+49-6`

`=>B=490+686+49-6`

`=>B=1219`