Phan tich da thuc thanh nhan tu
x2-2xy+y2-3x+3y
phan tich da thuc thanh nhan tu
x^2-3x+3y-y^2
x2 - 3x + 3y - y2
= (x2 - y2) - (3x - 3y)
= (x - y)(x + y) - 3(x - y)
= (x - y)(x + y - 3)
= x2 - y2 - 3x+3y = (x-y)(x+y) -3(x-y)
= (x+y+3)(x-y)
nhớ chọn cho mk nha!!!!!!
Phan tich da thuc thanh nhan tu
x2-y2-3x+3y
x2-y2-3x+3y
=(x+y)(x-y)-3.(x-y)
=(x-y)(x+y-3)
phan tich da thuc sau thanh nhan tu
xy+3x-3y-7=0
mình cần gấp
\(xy+3x-3y-7=0\)
\(\Leftrightarrow x\left(y-3\right)-3\left(y-3\right)+2=0\)
\(\Leftrightarrow\left(y-3\right)\left(x-3\right)=-2\)
timf noot
Phan tich da thuc thanh nhan tu : x2 - 4x -y2+4
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(x^2-4x-y^2+4=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)
Phan tich da thuc thanh nhan tu : x2 - 4x -y2+4
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)
x^2 - 2xy + y^2 - z^2 phan tich da thuc thanh nhan tur
\(x^2-2xy+y^2-z^2\\=(x^2-2xy+y^2)-z^2\\=(x-y)^2-z^2\\=(x-y-z)(x-y+z)\)
phan tich da thuc thanh nhan tu ;
\(3x^2-3y^2-2\left(x-y\right)^2\)
\(3x^2-3y^2-2\left(x-y\right)^2\)
\(=3\left(x^2-y^2\right)-2\left(x-y\right)^2\)
\(=3\left(x-y\right)\left(x+y\right)-2\left(x-y\right)^2\)
\(=\left(x-y\right)\left[3\left(x+y\right)-2\left(x-y\right)\right]\)
\(=\left(x-y\right)\left(3x+3y-2x+2y\right)\)
\(=\left(x-y\right)\left(x+5y\right)\)
phan tich da thuc thanh nhan tu xy+xz+3+3y
phan tich da thuc thanh nhan tu :
\(3x^2-3y^2-2\left(x-y\right)^2\)
\(3x^2-3y^2-2\left(x-y\right)^2\)
\(=3\left(x^2-y^2\right)-2\left(x-y\right)^2\)
\(=3\left(x-y\right)\left(x+y\right)-2\left(x-y\right)^2\)
\(=\left(x-y\right)\left[3\left(x+y\right)-2\left(x-y\right)\right]\)
\(=\left(x-y\right)\left(3x+3y-2x+2y\right)\)
\(=\left(x-y\right)\left(x+5y\right)\)
Chúc bạn học tốt!!!