1 has changed

2 are driving

3 were made

4 went - saw

5 finish

6 have been

7 weren't

8 will write

9 doing

10 to work

11 will clean

12 tastes - are

13 has become

14 went

15 is learning

16 won't be

17 is cut

18 eats

19 stewing

20 to drink

21 is organised

22 built

23 were made

14 was set

25 haven't done

26 is speaking

27 are spoken

a) \(\left(2x+1\right)^2-4\left(x+2\right)^2=9\\ \Rightarrow\left(2x+1\right)^2-\left[2\left(x+2\right)\right]^2=9\\ \Rightarrow\left(2x+1-2x-4\right)\left(2x+1+2x+4\right)=9\\ \Rightarrow-3\left(4x+5\right)=9\\ \Rightarrow-12x-15=9\\ \Rightarrow x=-2\)

b) \(\left(x+3\right)^2-\left(x-4\right)\left(x+8\right)=1\\ \Rightarrow x^2+6x+9-\left(x^2+4x-32\right)=1\\ \Rightarrow x^2+6x+9-x^2-4x+32=1\\ \Rightarrow2x=-40\\ \Rightarrow x=-20\)

\(a,\Rightarrow4x^2+4x+1-4x^2-16x-16=9\\ \Rightarrow-12x=24\Rightarrow x=-2\\ b,\Rightarrow x^2+6x+9-x^2-4x+32=1\\ \Rightarrow2x=-40\Rightarrow x=-20\\ c,\Rightarrow3x^2+12x+12+4x^2-4x+1-7x^2+63=36\\ \Rightarrow8x=-40\Rightarrow x=-5\\ d,\Rightarrow x^3-27+4x-x^3=1\\ \Rightarrow4x=28\Rightarrow x=7\\ e,\Rightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6x^2+12x-6=-19\\ \Rightarrow12x=-15\Rightarrow x=-\dfrac{5}{4}\)

Bài 3:

a: \(M=x^2-4x+5\)

\(=x^2-4x+4+1\)

\(=\left(x-2\right)^2+1\ge1\forall x\)

Dấu '=' xảy ra khi x=2

b: \(N=y^2-y-3\)

\(=y^2-2\cdot y\cdot\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{13}{4}\)

\(=\left(y-\dfrac{1}{2}\right)^2-\dfrac{13}{4}\ge-\dfrac{13}{4}\forall y\)

Dấu '=' xảy ra khi \(y=\dfrac{1}{2}\)

a: \(x^2-9y^2=\left(x-3y\right)\left(x+3y\right)\)

c: \(\left(x+5\right)^2-16=\left(x+1\right)\left(x+9\right)\)

e: \(\left(2x+3\right)^2-\left(x-7\right)^2\)

\(=\left(2x+3+x-7\right)\left(2x+3-x+7\right)\)

\(=\left(3x-4\right)\left(x+10\right)\)

Chọn B

??????

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