tính bằng cách thuận tiện nhất 4/25×1/3+4/15×13/5-1/15×4×4/5
tính bằng cách thuận tiện nhất
a ( 1+2+3+4+....+99)*(13*15-12*25-15)
b 3*5*36+15+42+30*11
a ( 1+2+3+4+....+99)*(13*15-12*25-15)
= ( 1+2+3+4+....+99)*[15*(13-1)-12*25)]
=( 1+2+3+4+....+99)*[15*12-12*25]
=( 1+2+3+4+....+99)*[12*(15-25)]
=( 1+2+3+4+....+99)*[12*(-10)]
=( 1+2+3+4+....+99)*(-120)
= -594000
b 3*5*36+15+42+30*11
=15*36+15*1+42+15*22
=15*(36+1+22)+42
=15*59+42
=885+42
=927
Tick cho mk nha
a. ( 1+2+3+4+....+99)*(13*15-12*25-15)
=( 1+2+3+4+....+99) . 0
=0
b 3*5*36+15+42+30*11
=540 + 15 +42 + 330
=927
Tính bằng cách thuận tiện nhất
a)12/25+3/5+13/15
b)3/2+2/3+4/3
c)3/5+7/5+3/4
=5/13x(4/5-9/15)
=5/13x1/5
=1/13
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tính bằng cách thuận tiện nhất:
( 2/3 x 4/5) x 5/6 (4/5 + 5/4) x 3/4 27/12 + 17/6 - 25/36 - 15/6
`(2/3xx4/5)xx5/6`
`=2/3xx4/5xx5/6`
`=2/3xx4/6`
`=2/3xx2/3`
`=1`
__
`(4/5+5/4)xx3/4`
`=(16/20+25/20)xx3/4`
`=41/20xx3/4`
`=123/80`
__
`27/12+17/6-25/36-15/6`
`=(27/12-25/36)+(17/6-15/6)`
`=(81/36-25/36)+2/6`
`=56/36+2/6`
`=56/36+12/36`
`=68/36`
`=17/9`
Tính bằng cách thuận tiên nhất:
1):(3/4 x 5/97 + 1/9 x 13/47) x (1/5 - 7/25 x 5/7)
2): 8/17 x 4/15 + 8/17 x 22/15 - 8/15 x 9/17
3): 2021/2 x 1/3 + 4042/4 x 1/5 + 6063/3 x 22/15
4); 4/7 x 2/13 + 8/13 :7/4 + 4/7 : 13/2 + 4/7 x 1/13
5): 2022 x 2021 - 1/ 2021 + 2022 x 2020
6): 18 x 123 + 9 x 4567 x 2 + 3 x 5310 x 6 / (2 + 4 + 6 + 8 + ...+20 + 22) + 48
7): A= 2021 x 2021 x 202020 - 2020 x 2020 x 20212021 / 2020 x 20192019
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
Tính bằng cách thuận tiện nhất :
a) 5/13 nhân 4/15 nhân 13
b) (3/7 + 5/2) nhân 7/5
c) 1/5 nhân 11/18 + 11/18 nhân 3/5
`a) 5 / 13 xx 4 / 15 xx 13 = [ 5 xx 4 xx 13 ] / [ 13 xx 5 xx 3 ] = 4 / 3`
`b) ( 3 / 7 + 5 / 2 ) xx 7 / 5 = 3 / 7 xx 7 / 5 + 5 / 2 xx 7 / 5 = 3 / 5 + 7 / 2 = 6 / 10 + 35 / 10 = 41 / 10`
`c) 1 / 5 xx 11 / 18 + 11 / 18 xx 3 / 5 = 11 / 18 xx ( 1 / 5 + 3 / 5 ) = 11 / 18 xx 4 / 5 = [ 11 xx 2 xx 2 ] / [ 2 xx 9 xx 5 ] = 22 / 45`
\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{4}{3}\)
\(b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\left(\dfrac{6}{14}+\dfrac{35}{14}\right)\times\dfrac{7}{5}=\dfrac{41}{14}\times\dfrac{7}{15}=\dfrac{41}{30}\)
\(c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)
Bài 4 (1 điểm): Tính bằng cách thuận tiện
3 x 4/15 + 2 x 4/15 - 5 x 4/15
= \(\dfrac{4}{15}\) x ( 3 + 2 - 5 )
= \(\dfrac{4}{15}\) x 0
= 0
( 3+2-5) x \(\dfrac{4}{15}\)
= 0 x \(\dfrac{4}{15}\)
=0
bài 8: tính bằng cách thuận tiện nhất
3*4/15-2*4/15-5*4/15
*này là nhân nha
`3xx4/15-2xx4/15-5xx4/15`
`=4/15xx(3-2-5)`
`=4/15xx(-4)`
`=-16/15`