Bài 1

a) 3 2/5 - 1/2

= 17/5 - 1/2

= 34/10 - 5/10

= 29/10

b) 4/5 + 1/5 × 3/4

= 4/5 + 3/20

= 16/20 + 3/20

= 19/20

c) 3 1/2 × 1 1/7

= 7/2 × 8/7

= 4

d) 4 1/6 : 2 1/3

= 25/6 : 7/3

= 25/14

Bài 2

a) 3 × 1/2 + 1/4 × 1/3

= 3/2 + 1/12

= 18/12 + 1/12

= 19/12

b) 1 4/5 - 2/3 : 2 1/3

= 9/5 - 2/3 : 7/3

= 9/5 - 2/7

= 63/35 - 10/35

= 53/35

Bài 1

a) 3 2/5 - 1/2

= 17/5 - 1/2

= 34/10 - 5/10

= 29/10

b) 4/5 + 1/5 × 3/4

= 4/5 + 3/20

= 16/20 + 3/20

= 19/20

c) 3 1/2 × 1 1/7

= 7/2 × 8/7

= 4

d) 4 1/6 : 2 1/3

= 25/6 : 7/3

= 25/14

bủh

\(B=1+\frac{1}{2}\cdot3\cdot2\div2+\frac{1}{3}\cdot4\cdot3\div2+...+\frac{1}{x}\cdot\left(x+1\right)\cdot x\div2\)

    \(=\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+...+\frac{x}{2}=\frac{2+3+4+5+...+x}{2}\)

  để B=115 \(\Rightarrow2+3+4+...+x=230\Rightarrow x=20\)

 VẬY....

Giải thích xíu tổng = ( số cuối + số đầu * số số hạng ) / 2

Câu hỏi của Best Friend Forever - Toán lớp 7 - Học toán với OnlineMath

`a)(1-1/2)xx(1-1/3)xx(1-1/4)xx(1-1/5)`

`=1/2xx2/3xx3/4xx4/5`

`=[1xx2xx3xx4]/[2xx3xx4xx5]`

`=1/5`

`b)(1-3/4)xx(1-3/7)xx(1-3/10)xx(1-3/13)xx .... xx(1-3/97)xx(1-3/100)`

`=1/4xx4/7xx7/10xx10/13xx .... xx94/97xx97/100`

`=[1xx4xx7xx10xx...xx94xx97]/[4xx7xx10xx13xx....xx97xx100]`

`=1/100`

giúp mình vớiiii

a) \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{256}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}+...-\dfrac{1}{128}+\dfrac{1}{128}-\dfrac{1}{256}\)

\(=1-\dfrac{1}{256}\)

\(=\dfrac{255}{256}\)

b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{13.14}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{14}\)

\(=1-\dfrac{1}{14}\)

\(=\dfrac{13}{14}\)

c) \(\dfrac{3}{15.18}+\dfrac{3}{18.21}+\dfrac{3}{21.24}+...+\dfrac{3}{87.90}\)

\(=3.\left(\dfrac{1}{15.18}+\dfrac{1}{18.21}+\dfrac{1}{21.24}+...+\dfrac{1}{87.90}\right)\)

\(=3.\left[\dfrac{1}{3}.\left(\dfrac{1}{15}-\dfrac{1}{18}\right)+\dfrac{1}{3}.\left(\dfrac{1}{18}-\dfrac{1}{21}\right)+\dfrac{1}{3}.\left(\dfrac{1}{21}-\dfrac{1}{24}\right)+...+\dfrac{1}{3}.\left(\dfrac{1}{87}-\dfrac{1}{90}\right)\right]\)

\(=3.\dfrac{1}{3}.\left(\dfrac{1}{15}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{24}+...+\dfrac{1}{87}-\dfrac{1}{90}\right)\)

\(=\dfrac{1}{15}-\dfrac{1}{90}\)

\(=\dfrac{6}{90}-\dfrac{1}{90}\)

\(=\dfrac{5}{90}=\dfrac{1}{18}\)

tớ đang cần gấp

a)255/256
b)13/14
c) 1/18

a) 1/2x1/3 +1/3x1/4

cách 1: 1/2 x1/3+ 1/3 x1/4

=1/6 + 1/12 

= 1/4

cách 2: 1/2 x1/3+ 1/3 x1/4

= 1/3x (1/2+1/4)

= 1/3x3/4

= 1/4

b) (3/4+ 1/2)x2

cách 1: (3/4+1/2)x2

= 5/4x2

= 5/4

cách 2: (3/4+1/2)x2

=3/4 x2 + 1/2x2

=3/2+2/2

= 5/4

a. \(\frac{1}{2}\times\frac{1}{3}+\frac{1}{3}\times\frac{1}{4}\) 

Cách 1 = \(\frac{1}{3}\times\left(\frac{1}{2}+\frac{1}{4}\right)\)                                 Cách 2 =\(\frac{1}{6}+\frac{1}{12}\)

            = \(\frac{1}{3}\times\frac{3}{4}\)                                                                 =\(\frac{1}{4}\)

            =\(\frac{1}{4}\)

b. \(\left(\frac{3}{4}+\frac{1}{2}\right)\times2\)                        

Cách 1    =\(\frac{5}{4}\times2\)                                              Cách 2           =\(\frac{3}{4}\times2+\frac{1}{2}\times2\)

                =\(\frac{5}{2}\)                                                                              =\(\frac{3}{2}+1\)

                                                                                                          =\(\frac{5}{2}\)

c. \(\frac{1}{2}\times\frac{1}{3}-\frac{1}{3}\times\frac{1}{4}\)

C1           =\(\frac{1}{3}\times\left(\frac{1}{2}-\frac{1}{4}\right)\)                                 C2              =\(\frac{1}{6}-\frac{1}{12}\)

                =\(\frac{1}{3}\times\frac{1}{4}\)                                                                      =\(\frac{1}{12}\)

                =\(\frac{1}{12}\)

d. \(\left(\frac{4}{3}-\frac{1}{2}\right)\times\frac{2}{3}\)

C1           =\(\frac{5}{6}\times\frac{2}{3}\)                                        C2              =\(\frac{4}{3}\times\frac{2}{3}-\frac{1}{2}\times\frac{2}{3}\)

                =\(\frac{5}{9}\)                                                                       =\(\frac{8}{9}-\frac{2}{6}\)

                                                                                                   =\(\frac{5}{9}\)

Bạn chú ý đăng lẻ câu hỏi! 1/

a/ \(=x^3-2x^5\)

b/\(=5x^2+5-x^3-x\)

c/ \(=x^3+3x^2-4x-2x^2-6x+8=x^3=x^2-10x+8\)

d/ \(=x^2-x^3+4x-2x+2x^2-8=3x^2-x^3+2x-8\)

e/ \(=x^4-x^2+2x^3-2x\)

f/ \(=\left(6x^2+x-2\right)\left(3-x\right)=17x^2+5x-6-6x^3\)

a) \(A=\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)...\left(1-\dfrac{1}{2003}\right).\left(1-\dfrac{1}{2004}\right)\)

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}...\dfrac{2002}{2003}.\dfrac{2003}{2004}\)

\(=\dfrac{1}{2004}\)

b) \(B=5\dfrac{9}{10}:\dfrac{3}{2}-\left(2\dfrac{1}{3}.4\dfrac{1}{2}-2.2\dfrac{1}{3}\right):\dfrac{7}{4}\)

\(=\dfrac{59}{10}:\dfrac{3}{2}-\left(\dfrac{7}{3}.\dfrac{9}{2}-2.\dfrac{7}{3}\right).\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\left(\dfrac{21}{2}-\dfrac{14}{3}\right).\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\dfrac{35}{6}.\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\dfrac{10}{3}\)

\(=\dfrac{3}{5}\)

ai trả lời đúng thì mình sẽ tick cho