a)  13 4 + 9 10 = 83 x ⇔ 13.5 + 9.2 20 = 83 x ⇔ 83 20 = 83 x ⇔ x = 20

b)  x = 2 5 + 1 4 + − 1 3 ⇔ x = 2.12 + 1.15 + ( − 1 ) .20 60 ⇔ x = 19 60

     3x - 4 \(⋮\) 3 - x

\(\Rightarrow\) 3x - 4 + 3 . (3 - x) \(⋮\) 3 - x

\(\Rightarrow\) 5 \(⋮\) 3 - x

\(\Rightarrow\) 3 - x \(\in\) Ư(5) = {1 ; - 1 ; 5 ; - 5}

\(\Rightarrow\) x \(\in\) {2 ; 4 ; - 2 ; 8}

a ) − 1 2 ≤ x < 2 3 = > x = 0. b ) − 1 < x ≤ 1 = > x ∈ {0;1}

\(a,\left(-31\right).\left(x+7\right)=0\\ \Rightarrow x+7=0\\ \Rightarrow x=-7\\ b,\left(8-x\right).\left(x+13\right)=0\\ \Rightarrow\left[{}\begin{matrix}8-x=0\\x+13=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=8\\x=-13\end{matrix}\right.\\ c,\left(x^2-25\right)\left(3-x\right)=0\\ \Rightarrow\left(x-5\right)\left(x+5\right)\left(3-x\right)=0\\\Rightarrow \left[{}\begin{matrix}x-5=0\\x+5=0\\3-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\\x=3\end{matrix}\right.\\ d,\left(x-3\right)\left(x^2+4\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-3=0\\x^2+4=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x^2=-4\left(loại\right)\end{matrix}\right.\\ \Rightarrow x=3\)

a, (–31) . (x +7)=0

<=>  x +7 = 0

<=> x = -7

Vậy x \(\in\left\{-7\right\}\)

b, (8 – x) . (x + 13) = 0

<=> \(\left[{}\begin{matrix}8-x=0\\x+13=0\end{matrix}\right.\)   <=> \(\left[{}\begin{matrix}x=8\\x=-13\end{matrix}\right.\)

Vậy x \(\in\left\{8;-13\right\}\)

c,(x²– 25) . (3– x )=0

<=> (x - 5) (x + 5) (3 - x) = 0

<=> \(\left[{}\begin{matrix}x-5=0\\x+5=0\\3-x=0\end{matrix}\right.\)   <=> \(\left[{}\begin{matrix}x=5\\x=-5\\x=3\end{matrix}\right.\)

Vậy x \(\in\left\{5;-5;3\right\}\)

d, ( x - 3 ) (x² + 4) = 0

<=> \(\left[{}\begin{matrix}x-3=0\\x^2+4=0\end{matrix}\right.\)   <=> \(\left[{}\begin{matrix}x=3\\x^2=-4\end{matrix}\right.\)_{(vô lý)}

Vậy x \(\in\left\{3\right\}\)

TL

Mik lm đc câu a thui nha :

HT

trả lời lại được ko

a,   11/13 - ( 5/42 - x ) = - (5/28 - 11/13)

    11/13 - (5/42 - x) = - 5/28 + 11/13

    - (5/42 - x) + 5/28 = -11/13 + 11/13

 - 5/42 + x + 5/28 = 0

- 5/42 + x = 0 - 5/28

- 5/42 + x = - 5/28

x = -5/28 +5/42

x = - 5/84

b, / x + 4/15 \ - / - 3,75 \ = - / - 2,15 \

./ x + 4/15 \ - 3,75 = - 2,15

/ x + 4/15 \ = -2,15 + 3,75

/ x + 4/15 \ = 1,6

x + 4 / 15 = 1,6                      hoặc x+ 4/15 = - 1,6

x = 1,6 - 4/15                                   x = - 1,6 -4/15

x = 4/3                                              x = -28/15

Vậy x = 4/3 hoặc x = - 28/15

c, ( 0,25 - 30% x ) . 1/3 = 1/4 - 31/6

( 1/4 - 3/10 x ) . 1/3 = - 59/12

( 1/4 - 3/10 x ) = - 59/12 : 1/3

1/4 - 3/10 x = - 59/4

3/10 x = 1/4 + 59/4

3/10 x = 15

x = 15 : 3/10

x = 50

d, ( x - 1/2 ) : 1/3 + 5/7 = 68/7

( x - 1/2 ) : 1/3 = 68/7 - 5/7

( x - 1/2 ) : 1/3 = 63/7

( x - 1/2 ) = 63/7 . 1/3

x -1/2 = 3 

x = 3 + 1/2

x = 7/2

a) ĐK: \(x\ne4,x\ne2;x\ne-2\)

b) \(A=\dfrac{x^3}{x-4}-\dfrac{x}{x-2}-\dfrac{2}{x+2}\)

\(A=\dfrac{x^3}{\left(x+2\right)\left(x-2\right)}-\dfrac{x\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}-\dfrac{2\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{x^3-x^2-2x-2x+4}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{x^3-x^2-4x+4}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{x^2\left(x-1\right)-4\left(x-1\right)}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{\left(x-1\right)\left(x^2-4\right)}{x^2-4}\)

\(A=x-1\)

c) \(A=0\) khi:

\(x-1=0\)

\(\Leftrightarrow x=1\left(tm\right)\)

d) A dương khi: \(A>0\)

\(x-1>0\)

\(\Leftrightarrow x>1\)

Kết hợp với đk: 

\(x>1,x\ne4,x\ne2\)

a) 2x-13=15

2x       = 15+13

2x      =  18

x        = 18:2

x        =9

c. /3x-7/=2

+) Nếu 3x-7=2 thì  x = 3

+)Nếu 3x-7=-2 thì x = 5/3 không thuộc Z

Vậy x = 3