a: \(25496+28212:4\)

\(=25496+7053\)

=32549

b: \(\dfrac{\left(108610-87352\right)}{3}\)
\(=\dfrac{21258}{3}\)

\(=7086\)

(x+2)+(x+4)+(x+6)+...+(x+32)=352(x+2)+(x+4)+(x+6)+...+(x+32)=352

(x+x+...+x)+(2+4+6+...+32)=352(x+x+...+x)+(2+4+6+...+32)=352

16x+272=35216x+272=352

16x=352−272=8016x=352−272=80

x=80:16=5

bạn học lớp mấy vậy

=>384-4x=352

=>4x=32

=>x=8

\(320-x\cdot4+4^3=352\)

\(\Rightarrow320-x\cdot4+64=352\)

\(\Rightarrow-x\cdot4+64=352-320\)

\(\Rightarrow-x\cdot4+64=32\)

\(\Rightarrow-x\cdot4=32-64\)

\(\Rightarrow-x\cdot4=-32\)

\(\Rightarrow x\cdot4=32\)

\(\Rightarrow x=\dfrac{32}{4}=8\)

Ta có:

352-x+3⁴=422

=> 352+81-x=422

=> 433-x=422

=> x=433-422=11

352 - x + 3⁴ = 422

352 - x + 81 = 422

433 - x = 422

x = 11

\(352-x+3^4=422\)

\(\Rightarrow352-\left(x-3^4\right)=422\)

\(\Rightarrow x-3^4=352-422\)

\(\Rightarrow x-81=-70\)

\(\Rightarrow x=\left(-70\right)+81\)

\(\Rightarrow x=11\)

theo công thức ta có : 

(5+1)*(7+1)*(x+1)=352

6*8*(x+1)=352

x+1=22/3

x=19/3

tôi o chắc chắn

a) 17+x- (-8)=-32

=>x =-32+(-8)-17

=.x = -57

b) -121+35+x=50

=>x=50+121-35

=> x= 136

c)