f: =20:4+5

=5+5

=10

e: =125-100=25

tự tính

\(\dfrac{3}{5}+\dfrac{13}{25}-\dfrac{5}{9}-\dfrac{3}{7}\)

\(=\dfrac{15}{25}+\dfrac{13}{25}-\dfrac{35}{63}-\dfrac{27}{63}\)

\(=\dfrac{28}{25}-\dfrac{62}{63}=\dfrac{214}{1575}\)

bằng 214/1575

25-[50-(2^3.17-2^3.14)]

=25-[50-(8.17-8.14)]

=25-[50-(136-112)]

=25-[50-24]

=25-26

=-1

|-128|: [45^2-(2010-2008.1^2010)]

=128:[45^2-(2010-2008.1)]

=128:[45^2-(2010-2008)]

=128:[45^2-2]

=128:[2025-2]

=128:2023

=0,063 (chắc mik làm sai b đấy :(  )

25-[50-(2^3.17-2^3.14)]=25-{50-[2^3.(17-14)]}

                                     =25-{50-[8.3]}

                                     =25-{50-24}

a)300
b)374
c)4545
d)410000
e)7000
f)180000

a)300
b)374
c)4545
d)410000
e)7000
f)180000

a)300
b)374
c)4545
d)410000
e)7000
f)180000

Thực hiện phép tính:

a, 5/17 + -5/34 . 2/5=5/17 + -1/17=4/17

b, 1/2 . 5/6 + 2/3 . 3/4 =5/12 + 6/12 =11/12

c, ( -2/5 + 1/3 ) . ( 3/2 - 3/7 )=-1/15 . 15/14=1/14

a: \(=3^2+\left(3^4\right)^{-0.75}-5^{2\cdot0.5}\)

\(=9-5+3^{-3}=4+\dfrac{1}{27}=\dfrac{109}{27}\)

b: \(=2^{4-6\sqrt{7}}\cdot2^{6\sqrt{7}}=2^{4-6\sqrt{7}+6\sqrt{7}}=2^4=16\)

Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)

a) 25 –[ 50 – (  2 3   .   17   –   2 3   . 14 )]

= 25 – ( 50 – 23 . 3 ) = 25 – ( 50 – 24 )

= 25 – 26 = -1

b) |-128| : [  45 2   –   (   2010   –   2008 0   .   1 2010 )]

= 128 : [ 2025 – ( 2010 – 1 . 1 )] = 128 : ( 2025 – 2009 ) = 128 : 16 = 8