Ta có: \(2020^{45}-2020^{44}\)

\(=2020^{44}\cdot2020-2020^{44}\cdot1\)

\(=2020^{44}\cdot\left(2020-1\right)\)

\(=2020^{44}\cdot2019\)

Ta có: \(2020^{44}-2020^{43}\)

\(=2020^{43}\cdot2020-2020^{43}\cdot1\)

\(=2020^{43}\cdot\left(2020-1\right)\)

\(=2020^{43}\cdot2019\)

Vì \(2020^{44}>2020^{43}\)

nên \(2020^{44}\cdot2019>2020^{43}\cdot2019\)

hay \(2020^{45}-2020^{44}>2020^{44}-2020^{43}\)

a,  10 x + 2 2 . 5 = 10 2

10x = 100–20

10x = 80

x = 8

b,  5 2 + 15 - x = 30

15–x = 5

x = 10

c,  2 2 . 5 2 - 25 + x = 40

100–(25+x) = 40

25+x = 60

x = 35

d,  7 2 x - 6 2 x = 13 . 2 3 - 26

49x–36x = 104–26

13x = 78

x = 6

a) \(\dfrac{1}{2}\)x45+0,5x37+\(\dfrac{5}{10}\)x18

= \(\dfrac{1}{2}\)x45+\(\dfrac{1}{2}\)x37+\(\dfrac{1}{2}\)x18

=\(\dfrac{1}{2}\)x(45+37+18)

=\(\dfrac{1}{2}\)x100

=50

1/2x 45 + 0,5 x 37 + 5/10 x 18 

=22,5+18.5+5/10x18

=41+9

=50

a) 510510x18

= 1212x37+1212x(45+37+18)

=

                                                                    Bài giải

45% của 2,25 là :

            2,25 : 100 x 45 = 1,0125

                       Đáp số : 1,0125 .

10,125

\(22.5\cdot\frac{45}{100}=\frac{22.5\cdot45}{100}=10.125.\)

22,5 x 45 : 100 = 2,125 ( chắc vậy :v )

tra gg

Lên  gg

3x 7/10+ 7/10x 5+ 2x 7/10 = 7

22.5:0.25+22.5x4+45

22.5x(0.25+4)+45

22.5x4.25+45

95.625+45

140.625

mình bằng 225

Kq=225 nhé.K nha

\(N=2\left(x^2+\frac{9y^2}{4}-3xy+5x+\frac{25}{4}-\frac{15}{2}y\right)+\frac{5}{2}\left(y^2-6y+9\right)+10\)

\(N=\left(x-\frac{3}{2}y+\frac{5}{2}\right)^2+\frac{5}{2}\left(y-3\right)^2+10>0\) \(\forall x;y\)

64

tuổi ủng hộ mk nha

chẳng có quy luật j cả

quy luật đâu mà tính