%mCu(trong CuO)= (64/80).100= 80%

%mCu(trong CuS)= \(\frac{64}{96}.100\approx66,667\%\)

%mCu(trong CuCO3)= \(\frac{64}{124}.100\approx51,613\%\)

%mCu(trong CuSO4)= (64/160).100=40%

%mCu(trong CuCl2)= \(\frac{64}{135}.100\approx47,407\%\)

=> %mCu(trong CuO) > %mCu(trong CuS) > %mCu(trong CuCO3)>%mCu(trong CuCl2)>%mCu(trong CuSO4)

=>%mCu(trong CuO)= (64/80).100= 80%

=>%mCu(trong CuS)= 6496.100≈66,67%

=>%mCu(trong CuCO3)= 64124.100≈51,61%

=>%mCu(trong CuSO4)= (64/160).100=40%

=>%mCu(trong CuCl2)= 64135.100≈47,41%

so sánh : %mCu(trong CuO) > %mCu(trong CuS) > %mCu(trong CuCO3)>%mCu(trong CuCl2)>%mCu(trong CuSO4)

Chọn đáp án D

CuCO3 -nhiệt phân-> CuO + CO2
Cu(OH)2 -nhiệt phân-> CuO + H2O
CuO + CO -> Cu + CO2

Đáp án C

Các chất thỏa mãn : Cu ; Cu₂O ; CuS ; Cu₂S ; CuSO₃

=>C

\(CuSO_4+BaCl_2\rightarrow CuCl_2+BaSO_4\downarrow\)

\(CuCl_2+Na_2CO_3\rightarrow CuCO_3\downarrow+2NaCl\)

\(CuCO_3\underrightarrow{t^o}CuO+CO_2\)

\(CuO+2HNO_3\rightarrow Cu\left(NO_3\right)_2+H_2O\)

CuSO₄ + 2HCl ---> CuCl₂ + H₂SO₄

CuCl₂ + K₂CO₃ ---> CuCO₃ + 2KCl

CuCO₃ ---t^o---> CuO + CO₂

CuO + 2HNO₃ ---> Cu(NO₃)₂ + H₂O

CuSO4 + BaCl2 --> CuCl2 + BaSO4

CuCl2 + Na2CO3 --> CuCO3 + Nacl

CuCO3 t⁰ --> CuO +CO2

CuO + HNO3 --> Cu(NO3)2 + H2O

(1) 2CuO--(to)--->2Cu+O2

(2) CuO+ CO2---> CuCO3

Thôi đến đây đã.

CuSO3-> CuSO4->CuCl2->CuS->Cu(NO3)2->Cu(OH)2->CuCO3->CuO->Cu

Đáp án là C. 4 : Pt ,CuS, BaSO₄, NaHSO₄  

Đáp án C.

Các chất: Pt, CuS, BaSO₄, NaHSO₄

(1)2Cu + O2=2CuO
(2)CuO+H2O=Cu(OH)2
(3)Cu+S=CuS
(4)CuS+4H2SO4=4H2O+4SO2+CuSO4
(5)CuSO4+2HCl=CuCl2+H2SO4
(6)CuCl2+2AgNO3=Cu(NO3)2+2AgCl
(7)2Cu(NO3)2=2CuO+4NO2+O2
(8)Cu(OH)2=CuO+H2O
(9)2CuSO4=2CuO+2SO2+O2
(10)CuO+2HNO3=Cu(NO3)2+H2O
(11)3Cu+8HNO3=3Cu(NO3)2+4H2O+2NO

(1)2Cu + O2------>2CuO
(2)CuO+H2O------>Cu(OH)2
(3)Cu+S------>CuS
(4)CuS+4H2SO4----->4H2O+4SO2+CuSO4
(5)CuSO4+2HCl----->CuCl2+H2SO4
(6)CuCl2+2AgNO3---->Cu(NO3)2+2AgCl
(7)2Cu(NO3)2------>2CuO+4NO2+O2
(8)Cu(OH)2----->CuO+H2O
(9)2CuSO4----->2CuO+2SO2+O2
(10)CuO+2HNO3----->Cu(NO3)2+H2O
(11)3Cu+8HNO3------->3Cu(NO3)2+4H2O+2NO

A