Em hãy viết sơ đồ phản ứng sau :
Fe \(\underrightarrow{\left(1\right)}\) Fe2O3 \(\underrightarrow{\left(2\right)}\) FeCl3 \(\underrightarrow{\left(3\right)}\) Fe(OH)3
GIÚP MK VỚI MK CẢM ƠN NHIỀU !
CHUỖI PHẢN ỨNG
Fe\(\underrightarrow{\left(1\right)}\)FeCl3\(\underrightarrow{\left(2\right)}\)Fe(OH)3\(\underrightarrow{\left(3\right)}\)Fe2O3\(\underrightarrow{\left(4\right)}\)Fe(SO4)3
Al\(\underrightarrow{\left(1\right)}\)AlCl3\(\underrightarrow{\left(\text{2}\right)}\)Al(NO3)3\(\underrightarrow{\left(\text{3}\right)}\)Al(OH)3\(\underrightarrow{\left(\text{4}\right)}\)Al2O3
Al\(\underrightarrow{\left(\text{5}\right)}\)Al2O3\(\underrightarrow{\left(\text{6}\right)}\)Al\(\underrightarrow{\left(\text{7}\right)}\)Al(SO4)3\(\underrightarrow{\left(\text{8}\right)}\)AlCl3
\(\left(1\right)2Fe+3Cl_2\xrightarrow[t^0]{}2FeCl_3\\ \left(2\right)FeCl_2+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\\ \left(3\right)2Fe\left(OH\right)_3\xrightarrow[t^0]{}Fe_2O_3+3H_2O\\ \left(4\right)Fe_2O_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+3H_2O\)
____________
\(\left(1\right)2Al+3Cl_2\rightarrow2AlCl_3\\ \left(2\right)AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ \left(3\right)Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ \left(4\right)2Al\left(OH\right)_3\xrightarrow[t^0]{}Al_2O_3+3H_2O\\ \left(5\right)Al_2O_3+3CO\xrightarrow[]{t^0}2Al+3CO_2\\ \left(6\right)4Al+3O_2\xrightarrow[]{t^0}2Al_2O_3\\ \left(7\right)2Al+3H_2SO_4\xrightarrow[]{}Al_2\left(SO_4\right)_3+3H_2\\ \left(8\right)Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
Viết phương trình hóa học của các phản ứng trong quá trình chuyển đổi sau:
FeS2 \(\underrightarrow{\left(1\right)}\) Fe2O3 \(\underrightarrow{\left(2\right)}\) FeCl3 \(\underrightarrow{\left(3\right)}\) Fe(OH)3 \(\underrightarrow{\left(4\right)}\) FeO \(\underrightarrow{\left(5\right)}\) FeSO4 \(\underrightarrow{\left(6\right)}\) Fe
(1) 4FeS2 + 11O2 → 2Fe2O3 + 8SO2
(2) Fe2O3 + 6HCl → 2FeCl3 + 3H2O
(3) FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
(4) 2Fe(OH)3 → Fe2O3 + 3H2O.
(5) FeO + H2SO4 → FeSO4 + H2O.
(6) FeSO4 + Mg → MgSO4 + Fe.
(1) 4FeS2 + 11O2 → 2Fe2O3 + 8SO2
(2) Fe2O3 + 6HCl → 2FeCl3 + 3H2O
(3) FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
(4) 2Fe(OH)3 → Fe2O3 + 3H2O.
(5) FeO + H2SO4 → FeSO4 + H2O.
(6) FeSO4 + Mg → MgSO4 + Fe.
Viết phương trình hóa học hoàn thành sơ đồ chuyển hóa sau ( ghi rõ điều kiện nếu có)
FeO\(\underrightarrow{\left(1\right)}\)FeSO4\(\underrightarrow{\left(2\right)}\)Fe(OH)2\(\underrightarrow{\left(3\right)}\)FeO\(\underrightarrow{\left(4\right)}\)FeCl2.
HELP ME!!!MAI MIK THI RỒI!
`(1)FeO + H_2SO_4 -> FeSO_4 + H_2O`
`(2)FeSO_4 + Ba(OH)_2 -> Fe(OH)_2 + BaSO_4`
`(3)Fe(OH)_2 -> (t^o, chân.không) FeO + H_2O`
`(4)FeO + 2HCl -> FeCl_2 + H_2O`
Hoàn thành chuỗi phản ứng sau, ghi rõ điều kiện phản ứng ( nếu có ):
\(Fe\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{ \left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe\)
Help! Nguyễn Việt HàDiệp Anh TúHoàng Nhất ThiênXuân SángHà Yến NhiKHUÊ VŨmuốn đặt tên nhưng chưa nghĩ ra bạn nào tốt nghĩ giùm mkHùng NguyễnNơ Lê ThịTô Ngọc Hà
2Fe + 3Cl2 --to--> 2FeCl3
FeCl3 + 3NaOH ---> Fe(OH)3 + 3NaCl
2Fe(OH)3 ---to--> Fe2O3 + 3H2O
Fe2O3 + 3H2 ---> 2Fe + 3H2O
chúc học tôt ---
Hoàn thành sơ đồ chuyển hóa sau :
Fe \(\underrightarrow{\left(1\right)}\) Fe3O4 \(\underrightarrow{\left(2\right)}\) H2O \(\underrightarrow{\left(3\right)}\) O2 \(\underrightarrow{\left(4\right)}\) SO2 \(\underrightarrow{\left(5\right)}\) SO3 \(\underrightarrow{\left(6\right)}\) H2SO4 \(\underrightarrow{\left(7\right)}\) ZnSO4
Ai giỏi hóa giúp mk vs . mk cảm ơn nhiều . mk hứa sẽ tích .
~~~~~~~~~~~~~~ HELP ME ~~~~~~~~~~~~~~~~~
Fe + O2 -to-> Fe3O4
Fe3O4 + 4H2 -to-> 3Fe + 4H2O
2H2O -đp->2H2 + O2
S + O2 -to-> SO2
2SO2+ O2 -xúctác,to-> 2SO3
SO3 + H2O -> H2SO4
H2SO4 (loãng) + Zn -> ZnSO4 + H2
Viết PTHH thực hiện sơ đồ sau:
a) \(KMnO_4\underrightarrow{\left(1\right)}O_2\underrightarrow{\left(2\right)}SO_2\underrightarrow{\left(3\right)}SO_3\underrightarrow{\left(4\right)}H_2SO_4\underrightarrow{\left(5\right)}Al_{2_{ }}\left(SO_4\right)_3\)
b) \(Ca\underrightarrow{\left(1\right)}CaO\underrightarrow{\left(2\right)}Ca\left(OH\right)_2\underrightarrow{\left(3\right)}CaCo_3\underrightarrow{\left(4\right)}H_2\)
Cảm ơn ạ.
a) (1) 2 KMnO4 -to-> K2MnO4 + MnO2 + O2
(2) S + O2 -to-> SO2
(3) 2 SO2 + O2 -450 độ C, xúc tác -> 2 SO3
(4) SO3 + H2O -> H2SO4
(5) 2 Al + 3 H2SO4 -> Al2(SO4)3 +3 H2
b) Các PTHH:
(1) 2 Ca + O2 -to-> 2 CaO
(2) CaO + H2O -> Ca(OH)2
(3) Ca(OH)2 + CO2 -> CaCO3+ H2O
(4) CaCO3 thì không ra H2 được
2KMnO4-to>K2MnO4+MnO2+O2
O2+S-to>SO2
2SO2+O2-to>2SO3
SO3+H2O->H2SO4
3H2SO4+2Al->Al2(SO4)3+3H2
2>
Ca+O2-to>CaO
CaO+H2O->Ca(OH)2+H2
Ca(OH)2+CO2->CaCO3
CaCO3-->H2??
Viết các phương trình phản ứng sau:
\(Cu\underrightarrow{1}CuO\underrightarrow{2}CuCl_2\xrightarrow[4]{3}Cu\left(OH\right)_2\xrightarrow[6]{5}Cu\left(NO_3\right)_2\underrightarrow{7}Fe\left(NO_3\right)_2\xrightarrow[10]{9}Fe\left(OH\right)_2\)
\(\left(1\right)Cu+\dfrac{1}{2}O_2\xrightarrow[]{t^0}CuO\\ \left(2\right)CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(\left(3\right)CuCl_2+2NaOH\rightarrow Cu\left(OH\right)_2+2NaCl\\ \left(4\right)Cu\left(OH\right)_2+2HNO_3\rightarrow Cu\left(NO_3\right)_2+2H_2O\\ \left(5\right)Cu\left(NO_3\right)_2+Fe\rightarrow Fe\left(NO_3\right)_2+Cu\\ \left(6\right)Fe\left(NO_3\right)_2+2NaOH\rightarrow Fe\left(OH\right)_2+2NaNO_3\)
Viết PTHH hoàn thành chuỗi chuyển hóa sau:
\(Fe\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\underrightarrow{\left(5\right)}FeCl_3\)
(1) 2Fe + 3Cl2 -t0-> 2FeCl3
(2) FeCl3 + 3NaOH - > Fe(OH)3 + 3NaCl
(3) 2Fe(OH)3 -t0-> Fe2O3 + 3H2O
(4) Fe2O3 + 3H2SO4(l) - > Fe2(SO4)3 + 3H2O
(5) Fe2(SO4)3 + 3BaCl2 - > 2FeCl3 + 3BaSO4
1. 2Fe + 3Cl2 \(\rightarrow\)2 FeCl3
2. FeCl3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaCl
3. 2Fe(OH)3 \(\rightarrow\) Fe2O3 + 3H2O
4. Fe2O3 + 3H2SO4 \(\rightarrow\) Fe2(SO4)3 + 3H2O
5. Fe2(SO4)3 + 3BaCl2 \(\rightarrow\) 2FeCl3 + 3BaSO4
Câu 1 ) A / Mg(NO3) \(\underrightarrow{\left(1\right)}\) Mg(OH)2 \(\underrightarrow{\left(2\right)}\) MgCl2\(\underrightarrow{\left(3\right)}\) KCl \(\underrightarrow{\left(4\right)}\) KNO3
B/ \(Na\underrightarrow{\left(1\right)}Na_2O\underrightarrow{\left(2\right)}NaOH\underrightarrow{\left(3\right)}Na_2SO_4\underrightarrow{\left(4\right)}NaCl\underrightarrow{\left(5\right)}NaNO_3\underrightarrow{\left(6\right)}NaCl\underrightarrow{\left(7\right)}NaOH\)
C/\(Mg\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgCl_2\underrightarrow{\left(3\right)}Mg\left(NO_3\right)_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgSO_4\underrightarrow{\left(6\right)}MgCO_3\)
D/\(CuSO_4\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuO\underrightarrow{\left(3\right)}CuCl_2\underrightarrow{\left(4\right)}Cu\left(OH\right)_2\underrightarrow{\left(5\right)}CuSO_4\)
E/\(CuCl_2\underrightarrow{\left(1\right)}Cu\left(OH\right)_2\underrightarrow{\left(2\right)}CuSO_4\underrightarrow{\left(3\right)}Cu\underrightarrow{\left(4\right)}CuO\)
F/ \(Cu\left(OH\right)_2\underrightarrow{\left(1\right)}CuO\underrightarrow{\left(2\right)}CuCl_2\underrightarrow{\left(3\right)}Cu\left(NO_3\right)_2\underrightarrow{\left(4\right)}NaNO_3\)
G/\(Fe_2O_3\underrightarrow{\left(1\right)}FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\)
H/ \(ZnCl_2\underrightarrow{\left(1\right)}Zn\left(OH\right)_2\underrightarrow{\left(2\right)}ZnCl_2\underrightarrow{\left(3\right)}NaCl\underrightarrow{\left(4\right)}NaNO_3\)
M/\(CuO\underrightarrow{\left(1\right)}CuCl_2\underrightarrow{\left(2\right)}Cu\left(OH\right)_2\underrightarrow{\left(3\right)}CuO\underrightarrow{\left(4\right)}CuSO_4\)
N/\(Fe\left(OH\right)_2\underrightarrow{\left(1\right)}FeO\underrightarrow{\left(2\right)}FeCl_2\underrightarrow{\left(3\right)}Fe\left(ỌH_2\right)\underrightarrow{\left(4\right)}FeSO_4\underrightarrow{\left(5\right)}FeCl_2\underrightarrow{\left(6\right)}Fe\left(NO_3\right)_2\)
Z/ \(Mg\left(OH\right)_2\underrightarrow{\left(1\right)}MgO\underrightarrow{\left(2\right)}MgSO_4\underrightarrow{\left(3\right)}MgCl_2\underrightarrow{\left(4\right)}Mg\left(OH\right)_2\underrightarrow{\left(5\right)}MgCl_2\underrightarrow{\left(6\right)}Mg\left(NO_3\right)_2\)
X/\(Al\left(OH\right)_3\underrightarrow{\left(1\right)}Al_2O_3\underrightarrow{\left(2\right)}AlCl_3\underrightarrow{\left(3\right)}Al\underrightarrow{\left(4\right)}Al_2\left(SO_4\right)_3\)
g) 1. Fe2O3 + 6HCl → 2FeCl3 + 3H2O
2. FeCl3 + 3NaOH → 3NaCl + Fe(OH)3↓
3. 2Fe(OH)3 \(\underrightarrow{to}\) Fe2O3 + 3H2O
4. Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O
h) 1. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2↓
2. Zn(OH)2 + 2HCl → ZnCl2 + 2H2O
3. ZnCl2 + 2NaOH → 2NaCl + Zn(OH)2↓
4. NaCl + AgNO3 → NaNO3 + AgCl↓
m) 1. CuO + 2HCl → CuCl2 + H2O
2. CuCl2 + 2NaOH → 2NaCl + Cu(OH)2↓
3. Cu(OH)2 \(\underrightarrow{to}\) CuO + H2O
4. CuO + H2SO4 → CuSO4 + H2O
Viết PTHH biểu diễn các chuyển đổi sau:
\(Fe\) \(\underrightarrow{\left(1\right)}\) \(FeCl_3\underrightarrow{\left(2\right)}Fe\left(OH\right)_3\underrightarrow{\left(3\right)}Fe_2O_3\underrightarrow{\left(4\right)}Fe_2\left(SO_4\right)_3\)
(1) 2Fe + 3Cl2 -t0-> 2FeCl3
(2) FeCl3 + 3NaOH - > Fe(OH)3\(\downarrow\) + 3NaCl
(3) \(2Fe\left(OH\right)3-^{t0}->Fe2O3+3H2O\)
(4) \(Fe2O3+3H2SO4->Fe2\left(SO4\right)3+3H2O\)
(1) 2Fe + 3Cl2 \(\rightarrow\) 2FeCl3
(2) FeCl3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaCl
(3) 2Fe(OH)3 \(\rightarrow\) Fe2O3 + 3H2O
(4) Fe2O3 + 3H2SO4 \(\rightarrow\) Fe2(SO4)3 + 3H2O