\(1,-\dfrac{4}{7}+\dfrac{2}{3}\times\dfrac{-9}{14}\)

\(=\dfrac{-4}{7}+\dfrac{-18}{42}\)

\(=\dfrac{-4\times6}{7\times6}+\dfrac{-18}{42}\)

\(=\dfrac{-20}{42}+\dfrac{-18}{42}\)

\(=-\dfrac{38}{42}\)

\(=-\dfrac{19}{21}\)

\(2,\dfrac{17}{13}-\left(\dfrac{4}{13}-11\right)\)

\(=\dfrac{17}{13}-\dfrac{4}{13}+11\)

\(=\dfrac{13}{13}+11\)

\(=1+11\)

\(=12\)

\(3,8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

\(=\dfrac{58}{7}-\left(\dfrac{31}{9}+\dfrac{30}{7}\right)\)

\(=\dfrac{58}{7}-\dfrac{31}{9}-\dfrac{30}{7}\)

\(=\dfrac{58}{7}-\dfrac{30}{7}-\dfrac{31}{9}\)

\(=\dfrac{28}{7}-\dfrac{31}{9}\)

\(=\dfrac{28\times9}{7\times9}-\dfrac{31\times7}{9\times7}\)

\(=\dfrac{252}{63}-\dfrac{217}{63}\)

\(=\dfrac{35}{63}\)

\(=\dfrac{5}{9}\)

\(5,\left(\dfrac{2}{3}-1\dfrac{1}{2}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\left(\dfrac{2}{3}-\dfrac{3}{2}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\left(\dfrac{2\times2}{3\times2}-\dfrac{3\times3}{2\times3}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\left(\dfrac{4}{6}-\dfrac{9}{6}\right):\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\dfrac{-5}{6}:\dfrac{4}{3}+\dfrac{1}{2}\)

\(=\dfrac{-5}{6}\times\dfrac{3}{4}+\dfrac{1}{2}\)

\(=\dfrac{-15}{24}+\dfrac{1}{2}\)

\(=\dfrac{-15}{24}+\dfrac{1\times12}{2\times12}\)

\(=\dfrac{-15}{24}+\dfrac{12}{24}\)

\(=\dfrac{-3}{24}\)

\(=-\dfrac{1}{8}\)

\(6,\dfrac{-5}{13}+\dfrac{2}{5}+\dfrac{-8}{13}+\dfrac{3}{5}-\dfrac{3}{7}\)

\(=\left(\dfrac{-5}{13}+\dfrac{-8}{13}\right)+\left(\dfrac{2}{5}+\dfrac{3}{5}\right)-\dfrac{3}{7}\)

\(=\dfrac{-13}{13}+\dfrac{5}{5}-\dfrac{3}{7}\)

\(=-1+1-\dfrac{3}{7}\)

\(=-\dfrac{3}{7}\)

\(7,\dfrac{6}{5}\times\dfrac{3}{7}+\dfrac{6}{5}:\dfrac{7}{10}+\dfrac{6}{5}\)

\(=\dfrac{6}{5}\times\dfrac{3}{7}+\dfrac{6}{5}\times\dfrac{10}{7}+\dfrac{6}{5}\)

\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+1\right)\)

\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+\dfrac{1\times7}{1\times7}\right)\)

\(=\dfrac{6}{5}\times\left(\dfrac{3}{7}+\dfrac{10}{7}+\dfrac{7}{7}\right)\)

\(=\dfrac{6}{5}\times\dfrac{20}{7}\)

\(=\dfrac{120}{35}\)

\(=\dfrac{24}{7}\)

Bài 2: 

a: =>x=-4

b: =>x=44

2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35        18/27 - 2/6=1/3        37/12 - 3=1/12
11/9 x 3/22=1/6         7/13 x 13/7=1       4 x6/7=24/7
2/5 : 3/10=4/3           3/8 : 9/4=1/6            8/21 : 4/7=2/3

2/3 + 3/4

= 17/12
9/4 + 3/5

= 57/20
5/24 + 1/4

=11/24
3/15 - 5/35   

=2/35   

18/27 - 2/6   

=1/3   

37/12 - 3

= 1/12
11/9 x 3/22 

=1/6       

7/13 x 13/7 

=1   

 4 x6/7

=24/7
2/5 : 3/10

=4/3         

 3/8 : 9/4   

=1/6       

8/21 : 4/7

= 2/3

1=17/12
2=57/20
3=11/24
4=2/35        7=1/3        10=1/12
5=1/6         8=1       11=24/7

6=4/3           9=1/6            12=2/3

a,280:  (7 + 3 : x ) = 4

             (7 + 3 : x ) = 280:4

              ( 7+ 3: x)  =70

               3 : x  = 70-7

                3:x=63

                   x=63.3

                   x=   189

b,(x+5).19:13=57

    (x+5).19  =57.13

     (x+5).19  =741

      (x+5)    =741:19

       (x+5)   =39

        x=39-5

       x = 34

c,6.(28-8.x)=72

      (28-8.x)=72:6

      (28-8.x)=12

            8x=28-12

             8x=16

             x=16:8

           X=2

Bài 1 :

\(a)x=\frac{7}{25}+\left(-\frac{1}{5}\right)\)

    \(x=\frac{2}{25}\)

\(b)x=\frac{5}{11}+\left(\frac{4}{-9}\right)\)

    \(x=\frac{1}{99}\)

Mấy câu kia dễ tự làm :>

tách ra

\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)

\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)

1)10-x=5-7

x=10-(-2)

x=12

2)x+5=0+32

x=32-5

x=27

3) -12+2x-9+x=0

-12+(2x+x-9)=0

3x-9=0+12

3x=12+9

x=21:3

x=7

4) 15-x=1-11

x=15-(-10)

x=25

5) 4-(27+3)=x-9

4-30=x-9

-26+9=x

x=-17

a. \(\left|x-3\right|-7=13\Leftrightarrow\left|x-3\right|=20\)

TH1: \(x-3=20\Leftrightarrow x=23\)

TH2: \(x-3=-20\Leftrightarrow x=-17\)

b. \(72-3.\left|x+1\right|=9\Leftrightarrow\left|x+1\right|=21\)

TH1: \(x+1=21\Leftrightarrow x=20\)

TH2: \(x+1=-21\Leftrightarrow x=-22\)

c. \(17-\left(43-\left|x\right|\right)=45\Leftrightarrow\left|x\right|=71\)

TH1: \(x=71\)

TH2: \(x=-71\)

d. \(3\left|x-1\right|-5=7\Leftrightarrow\left|x-1\right|=4\)

TH1: \(x-1=4\Leftrightarrow x=5\)

TH2: \(x-1=-4\Leftrightarrow x=-3\)

e. \(-12\left(x-5\right)+7\left(3-x\right)=5\Leftrightarrow-12x+60+21-7x=5\Leftrightarrow-19x=-76\Leftrightarrow x=4\)

a.

\(\left|x-3\right|-7=13\)

\(\left|x-3\right|=13+7\)

\(\left|x-3\right|=20\)

\(x-3=\pm20\)

               \(x=20+3\)

               \(x=23\)

               \(x=-20+3\)

               \(x=-17\)

Vậy x = 23 hoặc x = - 17.

b.

\(72-3\times\left|x+1\right|=9\)

\(3\times\left|x+1\right|=72-9\)

\(3\times\left|x+1\right|=63\)

\(\left|x+1\right|=63\div3\)

\(\left|x+1\right|=21\)

\(x+1=\pm21\)

               \(x=21-1\)

               \(x=20\)

               \(x=-21-1\)

               \(x=-22\)

Vậy x = 20 hoặc x = - 22.

c.

\(17-\left(43-\left|x\right|\right)=45\)

\(43-\left|x\right|=17-45\)

\(43-\left|x\right|=-28\)

\(\left|x\right|=43-\left(-28\right)\)

\(\left|x\right|=71\)

\(x=\pm71\)

Vậy x = 71 hoặc x = - 71.

d.

\(3\times\left|x-1\right|-5=7\)

\(3\times\left|x-1\right|=7+5\)

\(3\times\left|x-1\right|=12\)

\(\left|x-1\right|=12\div3\)

\(\left|x-1\right|=4\)

\(x-1=\pm4\)

               \(x=4+1\)

               \(x=5\)

               \(x=-4+1\)

               \(x=-3\)

Vậy x = 5 hoặc x = - 3.

e.

\(-12\times\left(x-5\right)+7\times\left(3-x\right)=5\)

\(-12\times x+\left(-12\right)\times\left(-5\right)+7\times3-7\times x=5\)

\(-12\times x+60+21-7\times x=5\)

\(-19\times x+81=5\)

\(-19\times x=5-81\)

\(-19\times x=-76\)

\(x=\frac{-76}{-19}\)

\(x=4\)

Chúc bạn học tốt

I x-3 I - 7 = 13

I x - 3 I= 13+7

I x - 3 I= 30

x - 3 =30

x= 30+3

x= 33

(82 - 5.x) : 13 - 4 = 0

(82 - 5.x) : 13 = 0 + 4

(82 - 5.x) : 13 = 4

(82 - 5.x) = 4 . 13

(82 - 5.x) = 52

5.x  = 82 - 52

5.x = 30

x = 30 : 5 = 6

(32 . 45) : 2 = (x + 70) : 14 - 40

720 = (x + 70) : 14 - 40

(x + 70) : 14 = 720 + 40

(x + 70) : 14 = 760

(x + 70) = 760 . 14

(x + 70) = 10640

x = 10640 - 70

x = 10570

Tìm x biết : 

( 82 - 5 . x ) : 13 - 4 = 0 

( 82 - 5 . x ) : 13 = 0 + 4 

( 82 - 5 . x )  : 13 = 4 

82 - 5 . x = 4 × 13 

82 - 5 . x = 52 

5 . x = 82 - 52 

5 . x = 30 

x = 30 : 5 

x = 6

Vậy x = 6

  a) ( 82- 5x ): 13- 4= 0

( 82- 5x ): 13           = 0+ 4

( 82- 5x ): 13           = 4

82- 5x                      = 4. 13

82- 5x                      = 52

5x                            =  82- 52

5x                            = 30

x                              = 30: 5

x                              = 6

  b) ( 32. 45 ): 2= ( x+ 70 ): 14- 40

1440: 2             = ( x+ 70 ): 14- 40

720                    = ( x+ 70): 14- 40

   => ( x+ 70 ): 14= 720+ 40

( x+ 70 ): 14       = 760

x+ 70                  = 760. 14

x+ 70                  = 10640

x                         = 10640- 70

x                         = 10570

a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)

b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)

\(\dfrac{-5}{6}-\left(\dfrac{-3}{8}+\dfrac{1}{10}\right)\)
\(\dfrac{-5}{6}-\dfrac{-3}{8}-\dfrac{1}{10}\)