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2^x-3-3.2^x=-92

<=>2^x:2³-3.2^x=-92

<=>2^x.(\(\dfrac{1}{8}\)-3)=-92

<=>2^x.\(\dfrac{-23}{8}\)=-92

<=>2^x=32

<=>2^x=2⁵

=>x=5

1) \(\dfrac{1}{4}x-\dfrac{1}{3}=\dfrac{-5}{9}\)

\(\Rightarrow\dfrac{1}{4}x=-\dfrac{2}{9}\Rightarrow x=-\dfrac{8}{9}\)

2) \(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x\left(2^{-3}-3\right)=-92\)

\(\Rightarrow2^x.\dfrac{-23}{9}=-92\)

\(\Rightarrow2^x=32\Rightarrow x=5\)

\(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x:2^3-3.2^x=-92\)

\(\Rightarrow2^x.\frac{1}{2^3}-3.2^x=-92\)

\(\Rightarrow2^x.\left(\frac{1}{2^3}-3\right)=-92\)

\(\Rightarrow2^x.\frac{-23}{8}=-92\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

\(10+2\cdot x=4^5:4^3\)

\(\Rightarrow10+2\cdot x=4^{5-3}\)

\(\Rightarrow10+2\cdot x=4^2\)

\(\Rightarrow10+2\cdot x=16\)

\(\Rightarrow2\cdot x=16-10\)

\(\Rightarrow2\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{2}=3\)

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\(2\cdot x-6^2:18=3\cdot2^2\)

\(\Rightarrow2\cdot x-36:18=12\)

\(\Rightarrow2\cdot x-2=12\)

\(\Rightarrow2\cdot x=12+2\)

\(\Rightarrow2\cdot x=14\)

\(\Rightarrow x=\dfrac{14}{2}=7\)

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\(70-5\cdot\left(x-3\right)=3\cdot2\)

\(\Rightarrow70-5\cdot\left(x-3\right)=6\)

\(\Rightarrow70-5x+15=6\)

\(\Rightarrow-5x+15=6-70\)

\(\Rightarrow-5x+15=64\)

\(\Rightarrow-5x=64-15\)

\(\Rightarrow-5x=49\)

\(\Rightarrow x=-\dfrac{49}{5}\)

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dễ tích mình rồi mình giải cho

1) \(-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)

\(-\frac{2}{3}x+\frac{1}{6}=\frac{2}{3}x-\frac{1}{3}\)

\(-\frac{2}{3}x-\frac{2}{3}x=-\frac{1}{3}-\frac{1}{6}\)

\(-\frac{4}{3}x=-\frac{1}{2}\)

\(x=\left(-\frac{1}{2}\right):\left(-\frac{4}{3}\right)\)

\(x=\frac{3}{8}\)

3.2^{x - 3} - 2^{x - 3} = 64

=> 2^{x - 3}.(3 - 1) = 64

=> 2^{x - 3}.2 = 64

=> 2^{x - 3} = 32

=> 2^{x - 3} = 2⁵

=> x - 3 = 5

=> x = 8

Vậy x = 8

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