Cau 1)

21+(x+23)=50

X+23=50-21

X=29-23

X=6

Cau 2)

125+(x-100)=150

X-100=150-125

X=25+100

X=125

Cau 3)

24+(10-x)=26

10-x=26-24

X=10-2

X=8

2: \(=\dfrac{-2}{75}+\dfrac{5}{39}=\dfrac{33}{325}\)

3: \(=\dfrac{6}{11}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{6}{11}\)

4: \(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-1\right)=-2\cdot\dfrac{7}{19}=-\dfrac{14}{19}\)

5: \(=\dfrac{2}{7}\left(\dfrac{4}{23}-\dfrac{27}{23}+1\right)=0\)

6: \(=\dfrac{3}{8}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{11}{8}=\dfrac{3}{8}+\dfrac{11}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)

1. 3x - 9 = (-1) - x

=> 3x + x = (-1) + 9

=> 4x = 8

=> x = 8 : 4

=> x = 2

2. 2x - 2³ = 17 - 3x

=> 2x - 8 = 17 - 3x

=> 2x + 3x = 17 + 8

=> 5x = 25

=> x = 25 : 5

=> x = 5

3. |x - 3| + 8 = 12

=> |x - 3| = 12 - 8

=> |x - 3| = 4

=> \(\orbr{\begin{cases}x-3=4\\x-3=-4\end{cases}}\)

=> \(\orbr{\begin{cases}x=4+3\\x=-4+3\end{cases}}\)

=> \(\orbr{\begin{cases}x=7\\x=-1\end{cases}}\)

4. 12 - 2|x| = |-2012|

=> 12 - 2|x| = 2012

=> 2|x| = 12 - 2012

=> 2|x| = -2000

=> |x| = -2000 : 2

=> |x| = -1000

=> x không có số nào thỏa mãn

5. 19 - (14 + 19) = x - (27 - 9)

=> 19 - 14 - 19 = x - 18

=> -14 = x - 18

=> x - 18 = -14

=> x = -14 + 18

=> x = 4

6. 15 - |x - 3| = 2

=> |x - 3| = 15 - 2

=> |x - 3| = 13

=> \(\orbr{\begin{cases}x-3=13\\x-3=-13\end{cases}}\)

=> \(\orbr{\begin{cases}x=13+3\\x=-13+3\end{cases}}\)

=> \(\orbr{\begin{cases}x=16\\x=10\end{cases}}\)

7. |x - 5| - 27 = -6

=> |x - 5| = -6 + 27

=> |x - 5| = 21

=> \(\orbr{\begin{cases}x-5=21\\x-5=-21\end{cases}}\)

=> \(\orbr{\begin{cases}x=21+5\\x=-21+5\end{cases}}\)

=> \(\orbr{\begin{cases}x=26\\x=-16\end{cases}}\)

8. 3 . |x - 2| = |-15|

=> 3 . |x - 2| = 15

=> |x - 2| = 15 : 3

=> |x - 2| = 5

=> \(\orbr{\begin{cases}x-2=5\\x-2=-5\end{cases}}\)

=> \(\orbr{\begin{cases}x=5+2\\x=-5+2\end{cases}}\)

=> \(\orbr{\begin{cases}x=7\\x=-3\end{cases}}\)

9. 11 - 2|x| = -3

=> 2|x| = 11 - (-3)

=> 2|x| = 14

=> |x| = 14 : 2

=> |x| = 7

=> \(\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)

10.|x - 2| = 1

=> \(\orbr{\begin{cases}x-2=1\\x-2=-1\end{cases}}\)

=> \(\orbr{\begin{cases}x=1+2\\x=-1+2\end{cases}}\)

=> \(\orbr{\begin{cases}x=3\\x=1\end{cases}}\)

1.3x-9=(-1)-x               

  3x+x=-1+9

  4x    =8

   x     =8/4

  x      =2

a)\(=\dfrac{3}{3}+\dfrac{4}{3}=\dfrac{7}{3}\)

b)\(=\dfrac{5}{9}\times\dfrac{3}{2}=\dfrac{15}{18}=\dfrac{5}{6}\)

d)\(=\left(\dfrac{12}{8}-\dfrac{3}{8}\right)\times2=\dfrac{9}{8}\times2=\dfrac{18}{8}=\dfrac{9}{4}\)

c)\(=\dfrac{4}{3}-\dfrac{5}{6}=\dfrac{8}{6}-\dfrac{5}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)

a) 1 + 4/3 = 7/3

b) 5/9 : 2/3 = 5/6

c ) 4/3 -1/3 x 5/2

= 1 x 5/2

= 5/2

d) ( 3/2 - 3/8) : 1/2

= 9/8 : 1/2

= 9/4

e) 15/16 : 3/8 x 3/4 

= 5/2 x 3/4

= 15/8

f) 7/19 x 1/3 x 7/19 x 2/3

= 7/19 x (1/3 x 2/3)

= 7/19 x 2/9

= 14/171

g) 3/5 x 8/27 x 25/3

= 3/5 x 25/3 x 8/27 

= 5 x 8/27

= 40/27

h) 1/5 + 4/11 + 4/5 + 7/11

= (1/5 + 4/5) + (4/11 + 7/11)

= 1 + 1

= 2

e)\(\dfrac{15}{16}\times\dfrac{8}{3}\times\dfrac{3}{4}=\dfrac{360}{192}=\dfrac{15}{8}\)

f) \(=\dfrac{7}{19}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{7}{19}\times\dfrac{3}{3}=\dfrac{7}{19}\)

g)\(=\dfrac{600}{120}=\dfrac{600:120}{120:120}=\dfrac{5}{1}=5\)

h)\(=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{4}{11}+\dfrac{7}{11}\right)=\dfrac{5}{5}+\dfrac{11}{11}=1+1=2\)

1: =-2/9(15/17+2/17)=-2/9

2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)

=-2-7/30=-67/30

3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)

=21/20+27/14=417/140

4: =-25/13(5/19+14/19)=-25/13

5: =-7/5-45/21=-7/5-15/7=-124/35

1: =-2/9(15/17+2/17)=-2/9

2: =34⋅75+97⋅32=34⋅75+97⋅32

=21/20+27/14=417/140

4: =-25/13(5/19+14/19)=-25/13

5: =-7/5-45/21=-7/5-15/7=-124/35

1. TÍNH 

`5/7 xx 4 : 5/9 = 5/7 xx 4 xx 9/5 = 20/7 xx 9/5 = 36/7`

`4/9 : 2 xx 5/7 = 4/9 xx 1/2 xx 5/7 = 2/9 xx 10/63 `

`8 xx 2/3 : 1/2= 8xx 2/3 xx 2/1 = 8 xx 2/3 xx 2 = 16/3 xx 2=32/3`

1:

a: \(=\dfrac{-4}{7}+\dfrac{4}{7}+\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=-\dfrac{1247}{1190}\)

b:

Sửa đề: \(\dfrac{-5}{13}+\dfrac{4}{19}+\dfrac{-8}{13}+\dfrac{15}{19}+\dfrac{45}{6}\) 

\(=\dfrac{-5}{13}-\dfrac{8}{13}+\dfrac{4}{19}+\dfrac{15}{19}+\dfrac{45}{6}=\dfrac{9}{2}\)

\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)

\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)

\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)

\(< =>\frac{35}{18}+1-\frac{17}{18}\)

\(< =>\frac{53}{18}-\frac{17}{18}\)

\(< =>2\)

\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)

\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)

\(< =>\frac{2}{7}\cdot\frac{1}{3}\)

\(< =>\frac{2}{21}\)

\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)

\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)

\(< =>\frac{15}{4}\)

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