tim GTNN cua bieu thuc C=x3-3x+2017
tim GTNN cua bieu thuc A=x-2017|x - 2017| + |x - 2018| + |x - 2019|
Tim GTNN cua bieu thuc sau:A=(6 - 3x) - 14
Tim GTNN cua bieu thuc sau
A=(6-3x)-14
\(\frac{2017-2015x}{\sqrt{1-x^2}}\)
tim GTNN cua bieu thuc tren
giup mk vs
tim GTNN cua bieu thuc sau
B=/y-2018/+/y-2017/
\(B=\left|y-2018\right|+\left|2017-y\right|>=\left|-2018+2017\right|=1\)
Dấu '=' xảy ra khi (y-2018)(y-2017)<=0
=>2017<=y<=2018
1) Tim GTNN cua bieu thuc sau
a) M = x^2 + 4x + 9
b) N = x^2 - 20x +101
5) Tim GTLN cua bieu thuc sau
a) C = -y^2 + 6y -15
b) B = -x^2 + 9x - 12
c) D = 3x - x^2
Bài 1:
a: \(M=x^2+4x+4+5=\left(x+2\right)^2+5>=5\)
Dấu '=' xảy ra khi x=-2
b: \(N=x^2-20x+101=x^2-20x+100+1=\left(x-10\right)^2+1>=1\)
Dấu '=' xảy ra khi x=10
tim GTLN hoac GTNN cua bieu thuc D= -3x2 +12x+11
Tim GTNN cua bieu thuc \(\frac{3x^2-18x+9}{x^2-4x+4}\)
Theo mình đề này chỉ có max thôi nha!
\(B=\frac{3x^2-18x+9}{x^2-4x+4}=-\frac{3\left(x+3\right)^2}{5\left(x-2\right)^2}+\frac{18}{5}\le\frac{18}{5}\)
Đẳng thức xảy ra khi \(x=-3\)
tim gia tri lon nhat cua bieu thuc :
b) D= 2 I 7x+5I +11/ I 7x+5I +4
tim GTNN cua bieu thuc :
c) C= 5+ -8/ 4x I5x+7I 24