Giải hộ mình câu này với
a) (0,25)4 . 1024
b) \(\frac{230^3}{23^3}\)
c) \(\frac{\left(-7\right)^n}{\left(-7\right)^{n-1}}\left(n\ge1\right)\)
\(\frac{\left(-7\right)^n}{\left(-7\right)^{n-1}}\)(n\(\ge1\)) Tính GTBT
Bài 2 Tính GTBT theo cách hợp lí nếu có thể
c) \(\frac{5^3\times3^3}{5^3\times0,5+125\times2,5}\)d)\(\frac{5\times7^1+7^3\times25}{7^5125-7^3\times50}\)e)\(\frac{8^5\times\left(-5\right)^8+\left(-2\right)^5\times10^9}{2^{16}\times5^7+20^8}\)
h)\(\frac{\left(-0,25\right)^{-5}\times9^4\times\left(-2\right)^{-3}-2^{-2}\times6^3}{2^9\times3^6+6^6\times40}\)
Bài 3 Chứng tỏ rằng
a)
Tính
a, A= \(\left(\frac{3}{5}\right)^2.5^2-\left(2\frac{1}{4}\right)^3:\left(\frac{3}{4}\right)^3+\frac{1}{2}\)
b, B= \(\left[\frac{4}{11}.\left(\frac{1}{25}\right)^0+\frac{7}{22}.2\right]^{2010}-\left(\frac{1}{2^2}:\frac{8^2}{4^4}\right)^{2009}\)
Giải hộ bài này giúp mik nhé
Tính:
a)\({\left( { - 2} \right)^2}.{\left( { - 2} \right)^3}\); b)\({\left( { - 0,25} \right)^7}:{\left( { - 0,25} \right)^5}\); c)\({\left( {\frac{3}{4}} \right)^4}.{\left( {\frac{3}{4}} \right)^3}.\)
a)\({\left( { - 2} \right)^2}.{\left( { - 2} \right)^3} = {\left( { - 2} \right)^{2 + 3}} = {\left( { - 2} \right)^5}\);
b)\({\left( { - 0,25} \right)^7}:{\left( { - 0,25} \right)^5} = {\left( { - 0,25} \right)^{7 - 5}} = {\left( { - 0,25} \right)^2} = {\left( {0,25} \right)^2}\);
c)\({\left( {\frac{3}{4}} \right)^4}.{\left( {\frac{3}{4}} \right)^3} = {\left( {\frac{3}{4}} \right)^{4 + 3}} = {\left( {\frac{3}{4}} \right)^7}.\)
Tính:
a, \(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}-\frac{-3}{35}\right).\frac{-4}{3}}\)
b, \(\left(\frac{1}{2}-1\right)+\left(1-\frac{3}{4}\right)+\left(\frac{7}{8}-1\right)+...+\left(1-\frac{1023}{1024}\right)\)
giải chi tiết giúp mk nha
tối nay mk cần
\(a)\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{14}+\frac{1}{7}-\frac{-3}{35}\right).\frac{-4}{3}}\)\(=\frac{\frac{-19}{60}.\frac{5}{19}}{\frac{3}{10}.\frac{-4}{3}}=\frac{5}{24}\)
Hok tốt
Yume Nguyễn bạn giải giúp mk phần b đc k
\(C=\left(\frac{3}{5}-\frac{4}{15}\right).\left(\frac{2}{7}-\frac{3}{14}\right)-\left(\frac{5}{9}-\frac{7}{27}\right).\left(1-\frac{3}{5}\right)+\left(1-\frac{11}{12}\right).\left(1+\frac{1}{12}\right)\)
CÂU NÀY NÈ CÁC BẠN GIẢI ĐƯỢC HÔNG
\(C=\left(\frac{3}{5}-\frac{4}{15}\right).\left(\frac{2}{7}-\frac{3}{14}\right)-\left(\frac{5}{9}-\frac{7}{27}\right).\left(1-\frac{3}{5}\right)+\left(1-\frac{11}{12}\right).\left(1+\frac{1}{12}\right)\)
\(C=\left(\frac{9}{15}-\frac{4}{15}\right).\left(\frac{4}{14}-\frac{3}{14}\right)-\left(\frac{15}{27}-\frac{7}{27}\right).\left(\frac{5}{5}-\frac{3}{5}\right)+\left(\frac{12}{12}-\frac{11}{12}\right).\left(\frac{12}{12}+\frac{1}{12}\right)\)
\(C=\frac{5}{15}.\frac{1}{14}.\frac{8}{27}.\frac{2}{5}.\frac{1}{12}.\frac{13}{12}\)
\(C=\frac{5.1.8.2.1.13}{15.14.27.5.12.12}\)
\(C=\frac{5.2.4.2.13}{3.5.14.27.5.4.3.2.2.3}\)
\(C=\frac{13}{3.14.27.5.3.3}\)
\(C=\frac{13}{51030}\)
Thu gọn biểu thức
a) \(C=\frac{7}{9}x^3y^2\left(\frac{6}{11}axy^3\right)+\left(-5bx^2y^4\right)\left(\frac{-1}{2}axz\right)+ax\left(x^2y\right)^3\)
b)\(D=\frac{\left(3x^4y^4\right)^2\left(\frac{6}{11}x^3y\right)\left(8x^{n-7}\right)\left(-2x^{7-n}\right)}{15x^3y^2\left(0,4ax^2y^2z^2\right)^2}\)(với axyz khác 0)
\(C=\frac{7}{9}x^3y^2\left(\frac{6}{11}axy^3\right)+\left(-5bx^2y^4\right)\left(\frac{-1}{2}axz\right)+ax\left(x^2y\right)^3\)
\(\Rightarrow C=\frac{42}{9}ax^4y^5+\frac{5}{2}abx^3y^4z+ax\left(x^6y^3\right)\)
\(\Rightarrow C=\frac{42}{9}ax^4y^5+\frac{5}{2}abx^3y^4z+ax^7y^3\)
\(D=\frac{\left(3x^4y^4\right)^2\left(\frac{6}{11}x^3y\right)\left(8x^{n-7}\right)\left(-2x^{7-n}\right)}{15x^3y^2\left(0,4ax^2y^2z^2\right)^2}\)
\(D=\frac{\left[3.\frac{6}{11}.8.\left(-2\right)\right]\left(x^8x^3x^{n-7}x^{7-n}\right)\left(y^8y\right)}{15.0,4.\left(x^3x^4\right)\left(y^2y^4\right)z^4a}\)
\(D=\frac{\frac{-188}{11}x^{24}y^9}{6x^7y^6z^4a}\)
Làm tiếp bài của Song Ngư (๖ۣۜO๖ۣۜX๖ۣۜA)
\(D=\frac{\frac{-188}{11}x^{17}y^3}{6z^4a}\)
A= \(\frac{1}{\left(x+1\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+7\right)}+\frac{1}{\left(x+7\right)\left(x+10\right)}+...+\frac{1}{\left(x+2017\right)\left(x+2020\right)}\)
làm hộ nha mai mình kiểm tra 1 tiết rồi nhanh nên các bạn ơi....................????????????
a) Tính \(A=\left(0,25\right)^{-1}.\left(\frac{1}{4}\right)^{-2}.\left(\frac{4}{3}\right)^{-2}.\left(\frac{5}{4}\right)^{-1}.\left(\frac{2}{3}\right)^{-3}\)
b) Tìm só nguyên n,biết :\(^{2^{-1}.2^n+4.2^n=9.2^5}\)
b, \(2^n\left(2^{-1}+4\right)=9\cdot2^5\)
=> \(2^n\cdot\frac{9}{2}=9\cdot2^5\)
=> \(2^n=2^6\)
Vậy \(n=6\left(tm\right)\)
a, \(A=4\cdot16\cdot\frac{9}{16}\cdot\frac{4}{5}\cdot\frac{27}{8}=\frac{486}{5}=97,2\)
a)
\(A=\left(0,25\right)^{-1}\cdot\left(\frac{1}{4}\right)^{-2}\cdot\left(\frac{4}{3}\right)^{-2}\cdot\left(\frac{5}{4}\right)^{-1}\cdot\left(\frac{2}{3}\right)^{-3}\)
\(A=4\cdot16\cdot\frac{9}{16}\cdot\frac{4}{5}\cdot\frac{27}{8}=\frac{4\cdot16\cdot9\cdot4\cdot27}{16\cdot5\cdot8}=\frac{9\cdot2\cdot27}{5}=\frac{486}{5}\)
b)
2-1.2n+4.2n=9.25
(1/2+4).2n=288
2n=288:(1/2+4) =64
=>2n=26
=> n = 6
giải hộ milk bài này nha
\(\frac{\left(13\frac{1}{4}-2\frac{5}{7}-10\frac{5}{6}\right)\times230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
giải hộ milk nha cảm ơn rất nhiều