\(\frac{7}{x}=\frac{y}{21}=\frac{-42}{54}\)

Ta có : \(\frac{-42}{54}=\frac{-42:6}{54:6}=\frac{-7}{9}\)

+) \(\frac{7}{x}=\frac{-7}{9}\)=> 7.9 = (-7).x => (-7).x = 63 => x = -9

+) \(\frac{y}{21}=\frac{-7}{9}\)=> y.9 = 21.(-7) => y.9 = -147 => y = -49/3

Vậy x = 9,y = -49/3

Ta có:

\(\frac{x+7}{2010}+\frac{x+6}{2011}=\frac{x+5}{2012}+\frac{x+4}{2013}\)

\(\Leftrightarrow\left(\frac{x+7}{2010}+1\right)+\left(\frac{x+6}{2011}+1\right)=\left(\frac{x+5}{2012}+1\right)+\left(\frac{x+4}{2013}+1\right)\)

\(\Leftrightarrow\frac{x+2017}{2010}+\frac{x+2017}{2011}=\frac{x+2017}{2012}+\frac{x+2017}{2013}\)

\(\Leftrightarrow\left(x+2017\right)\left(\frac{1}{2010}+\frac{1}{2011}\right)=\left(x+2017\right)\left(\frac{1}{2013}+\frac{1}{2014}\right)\)

Suy ra \(x+2017=0\)

Vậy \(x=-2017\)

b) Dễ tự làm nhé

\(a,x\cdot\frac{1}{2}\cdot\frac{2}{3}=4\)

\(\Rightarrow x\cdot\frac{1}{3}=4\)

\(\Rightarrow x=12\)

\(b,-\frac{2}{7}\cdot\frac{5}{7}\cdot x=\frac{7}{21}\)

\(\Rightarrow-\frac{10}{49}x=\frac{7}{21}\)

\(\Rightarrow x=-\frac{49}{30}\)

k đi làm tiếp cho

\(\begin{array}{l}a)x - \left( {\dfrac{5}{4} - \dfrac{7}{5}} \right) = \dfrac{9}{{20}}\\x = \dfrac{9}{{20}} + \left( {\dfrac{5}{4} - \dfrac{7}{5}} \right)\\x = \dfrac{9}{{20}} + \dfrac{{25}}{{20}} - \dfrac{{28}}{{20}}\\x = \dfrac{{6}}{{20}}\\x = \dfrac{{ 3}}{{10}}\end{array}\)

Vậy \(x = \dfrac{{ 3}}{{10}}\)

\(\begin{array}{*{20}{l}}{b)9 - x = \dfrac{8}{7} - \left( { - \dfrac{7}{8}} \right)}\\\begin{array}{l}9 - x = \dfrac{8}{7} + \dfrac{7}{8}\\9 - x = \dfrac{{64}}{{56}} + \dfrac{{49}}{{56}}\\9 - x = \dfrac{{113}}{{56}}\end{array}\\{x = 9 - \dfrac{{113}}{{56}}}\\{x = \dfrac{{504}}{{56}} - \dfrac{{113}}{{56}}}\\{x = \dfrac{{391}}{{56}}}\end{array}\)

Vậy \(x = \dfrac{{391}}{{56}}\)

\(\frac{-x}{21}=\frac{20}{7}\)

\(\Rightarrow-x.7=21.20\)

\(\Rightarrow-x.7=420\)

\(\Rightarrow-x=420:7\)

\(\Rightarrow-x=-60\)

\(\frac{-x}{21}=\frac{20}{7}\)

\(\Rightarrow-x.7=20.21\)

\(\Rightarrow-7x=420\)

\(\Rightarrow x=420:-7\)

\(\Rightarrow x=-60\)

Vậy \(x=-60\)

Chúc bạn học tốt !!! 

\(\frac{-x}{21}=\frac{20}{7}\)

\(\Leftrightarrow-x.7=20.21\)

\(\Leftrightarrow-x.7=210\)

\(\Leftrightarrow-x=30\)

\(\Leftrightarrow x=30\)

a) x/5=y/2

= x+y/5+2=21/7=3

=> x/5=3=>x=15

    y/2=3=>x=6

1) a) => \(\frac{x}{2}=\frac{y}{5}vàx+y=21\)

Áp dụng tính chất của dãy tỉ số bằng nhau , ta có :

\(\frac{x}{2}=\frac{y}{5}=\frac{x+y}{2+5}=\frac{21}{7}=3\)

* \(\frac{x}{2}=3\Rightarrow x=2\cdot3=6\)

* \(\frac{y}{5}=3\Rightarrow y=3\cdot5=15\)

c) =.> \(\frac{x}{7}=\frac{y}{5}vày-x=12\)

Áp dụng tính chất của dãy tỉ số bằng nhau , ta có :

\(\frac{x}{7}=\frac{y}{5}=\frac{y-x}{5-7}=\frac{12}{-2}=-6\)

*\(\frac{x}{7}=-6\Rightarrow x=-6\cdot7=-42\)

*\(\frac{y}{5}=-6\Rightarrow y=-6\cdot5=-30\)

\(a,97\times327+327\times3\)

\(=327\times\left(97+3\right)\)

\(=327\times100\)

\(=32700\)

\(b,\frac{1}{7}\times\frac{4}{23}+\frac{1}{7}\times\frac{25}{23}+\frac{1}{7}\times\frac{17}{23}+5\times\frac{1}{7}\)

\(=\frac{1}{7}\times\left(\frac{4}{23}+\frac{25}{23}+\frac{17}{23}+5\right)\)

\(=\frac{1}{7}\times7\)

\(=1\)

a) 97 x 327 + 327 x 3

   = (97 + 3) x 327

   = 100 x 327 = 32700

b) \(\frac{1}{7}\times\frac{4}{23}+\frac{1}{7}\times\frac{25}{23}+\frac{1}{7}\times\frac{17}{23}+5\times\frac{1}{7}\)

   \(=\frac{1}{7}\times\left(\frac{4}{23}+\frac{25}{23}+\frac{17}{23}+5\right)\)

    \(=\frac{1}{7}\times7=\frac{7}{7}=1\)