(x-3)=0:2

x-3=0

x=0+3

x=3

kick minh nhe ban

\(\text{2.(x-3)=0}\)

\(\Rightarrow\text{x-3=0}\)

\(x=0+3\)

\(x=3\)

\(2\cdot\left(x-3\right)=0\)

\(=>x-3=0\)

\(x=0+3\)

\(x=3\)

\(\dfrac{7}{12}< \dfrac{x}{24}< \dfrac{2}{3}\) 

→ \(\dfrac{7}{12}=\dfrac{7x2}{12x2}=\dfrac{14}{24}\)

→ \(\dfrac{2}{3}=\dfrac{2x8}{3x8}=\dfrac{16}{24}\)
⇒ x\(=\)15

\(\Leftrightarrow14< x< 16\)

hay x=15

x=15

k nhé

please

3 + x - 5 = 6x -4

3 - 5 + 4 = 6x -x 

2             = 5x 

x = 2 / 5 

\(3+\left(x-5\right)=2\left(3x-2\right)\)

\(3+x-5=6x-4\)

\(x-6x=-4+5-3\)

\(-5x=-2\)

\(x=\frac{2}{5}\)

3 + ( x - 5 ) = 2 ( 3x - 2 )

3 + ( x - 5 ) = 2 . 3x - 2. 2

3 + x + ( -5 ) = 6x - 4

3 + ( -5 ) + x = 6x - 4

-2 + x = 6x - 4

- 6x + x = 2 - 4

- 5 x = -2

x = -2 : ( -5 ) 

x = 0,4

<=> x³ - 4x² - x + 4 = 0

<=> (x² - 1)(x - 4) = 0

<=> (x - 1)(x + 1)(x - 4) = 0

<=> x = 1 hoặc x = -1 hoặc x = 4

\(x^3-4x^2+4-x=0\)

\(\left(x-1\right)\left(x-4\right)\left(x+1\right)=0\)

\(x=\pm1;x=4\)

sắp tới lập nhóm nha :v ( quảng cáo lun ) 

Simplifying 5(2x + 1) = 3(x + -2) Reorder the terms: 5(1 + 2x) = 3(x + -2) (1 * 5 + 2x * 5) = 3(x + -2) (5 + 10x) = 3(x + -2) Reorder the terms: 5 + 10x = 3(-2 + x) 5 + 10x = (-2 * 3 + x * 3) 5 + 10x = (-6 + 3x) Solving 5 + 10x = -6 + 3x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-3x' to each side of the equation. 5 + 10x + -3x = -6 + 3x + -3x Combine terms: 10x + -3x = 7x 5 + 7x = -6 + 3x + -3x Combine terms: 3x + -3x = 0 5 + 7x = -6 + 0 5 + 7x = -6 Add '-5' to each side of the equation. 5 + -5 + 7x = -6 + -5 Combine terms: 5 + -5 = 0 0 + 7x = -6 + -5 7x = -6 + -5 Combine terms: -6 + -5 = -11 7x = -11 Divide each side by '7'. x = -1.571428571 Simplifying x = -1.571428571

ko hieu ban oi

đề bài là j vậy bạn

\(\frac{x+3}{x+5}=\frac{3}{5}\)

=> (x + 3).5 = 3.(x + 5)

=> 5x + 15 = 3x + 15

=> 5x - 3x = 15 - 15

=> 2x = 0

=> x = 0 : 2 = 0

Vậy x = 0

\(\frac{x+3}{x+5}=\frac{3}{5}\)

<=> (x + 3).5 = (x + 5).3

<=> 5x + 15 = 3x + 15

<=> 5x + 15 - 15 = 3x + 15 - 15

<=> 5x = 3x

<=> 5x - 3x = 3x - 3x

<=> 2x = 0

<=> x = 0 : 2

=> x = 0

\(\frac{x+3}{x+5}=\frac{3}{5}\).Tim x.Giup mik.

Mik viet the nay cho cac bn de nhin.Thank^_^

x¹.x²...x²⁰¹⁶

= x^1+2+...+2016

= x^{2 033 136}

\(\dfrac{x+3}{15}=\dfrac{1}{3}\left(1\right)\\ \Leftrightarrow x+3=\dfrac{1}{3}\cdot15\\ \Leftrightarrow x+3=5\\ \Rightarrow x=5-3\\ \Rightarrow x=2\)

Vậy tập nghiệm phương trình (1) là \(\left\{2\right\}\)

(X+3)3=15x1

3X+9=15

3X=15-9

3X=6

X=6:3

X=2

\(\dfrac{x+3}{15}=\dfrac{1}{3}\)
\(\Rightarrow\dfrac{x}{15}+\dfrac{3}{15}=\dfrac{1}{3}\)
\(\Rightarrow\dfrac{x}{15}=\dfrac{1}{3}-\dfrac{3}{15}\)
\(\Rightarrow\dfrac{x}{15}=\dfrac{2}{15}\)
\(\Rightarrow x=2\)

\(\frac{4}{x}=\frac{5-2y}{3}\Leftrightarrow x\left(5-2y\right)=12\)

Do \(x,y\)là số nguyên nên \(x,5-2y\)là các ước của \(12\)mà \(5-2y\)là số lẻ nên ta có bảng giá trị: 

Vậy phương trình có các nghiệm là: \(\left(12,2\right),\left(4,1\right),\left(-12,3\right),\left(-4,4\right)\).

THX BN NHA