( 1 + x ) + ( 2 + x ) + ( 3 + x ) + ...+ ( 100 + x ) = 2018

\(\Rightarrow\)( 1 + 2 + 3 + ... + 100 ) + ( x + x + x + ... + x ) = 2018

\(\Rightarrow\){( 1 + 100 ) . [( 100 - 1 ) : 1 + 1 ] : 2 } + ( x + x + ... + x ) = 2018

\(\Rightarrow\)5050 + x . 100 = 2018

\(\Rightarrow\)  x100 = 2018 - 5050 = -3032

\(\Rightarrow\)x = -3032 : 100 = -30,32

vậy x = -30,32

mà nè sai thì xin lỗi đề hơi có vấn đề nếu sai thì sorry nha !!!

ta có 605x > 0 suy ra x>0

ta có x+1+x+2+x+...+100=605x

100x +5050=605x

505x=5050

x=10

\(6\cdot x-5=613\)

     \(6\cdot x=613+5\)

     \(6\cdot x=618\)

          \(x=618\div6\)

          \(x=103\)

Vậy \(x=103\)

\(12\cdot x+3\cdot x=30\)

\(x\cdot\left(12+3\right)=30\)

              \(x\cdot15=30\)

                    \(x=30\div15\)

                    \(x=2\)

Vậy \(x=2\)

\(125-25\cdot\left(x-1\right)=100\)

              \(25\cdot\left(x-1\right)=125-100\)

              \(25\cdot\left(x-1\right)=25\)

                        \(x-1=25\div25\)

                        \(x-1=1\)

                                 \(x=1+1\)

                                 \(x=2\)

Vậy \(x=2\)

\(\left(x-2\right)\cdot\left(x-14\right)=0\)

\(\Rightarrow\)  \(x-2=0\) hoặc \(x-14=0\)

TH1:  \(x-2=0\)                                 TH2: \(x-14=0\)

                 \(x=0+2\)                                          \(x=0+14\)        

                 \(x=2\)                                                   \(x=14\)

Vậy \(x=2\) hoặc \(x=14\)

\(128-3\cdot\left(x+4\right)=23\)

              \(3\cdot\left(x+4\right)=128-23\)

              \(3\cdot\left(x+4\right)=105\)

                      \(x+4=105\div3\)

                      \(x+4=35\)

                               \(x=35-4\)

                               \(x=31\)

Vậy \(x=31\)

12.x+3.x=30

x.(12+3)=30

x.15=30

x     =30:15

x     =2

125-25.(x-1)=100

      25.(x-1)=125-100

      25.(x-1)=25

          x-1=25:25

          x-1=1

          x   =1+1

          x=2

(x-2).(x-14)=0

x=14

128-3.(x+4)=23

      3.(x+4)=128-23

      3.(x+4)=105

         x+4=105:3

         x+4=35

         x   = 35+4

         x    =39

\(6x=618\Rightarrow x=103\)

\(x\left(12+3\right)=30\Rightarrow15x=30\Rightarrow x=2\)

\(25\left(x-1\right)=125-100=25\Rightarrow x-1=1\Rightarrow x=2\)

a,2x+53=135

2x=135-53

2x=82

x=82:2

x=41

bạn viết khó hỉu quá nên mk giúp bạn dc câu a thui 

k hộ mk với

\(A=3^x+3^{x+1}+...+3^{x+100}\)

=>\(3A=3^{x+1}+3^{x+2}+...+3^{x+101}\)

=>\(2A=3^{x+101}-3^x\)

=>\(A=\dfrac{3^{x+101}-3^x}{2}\)

=>\(3^{x+101}-3^x=3^{105}-3^4\)

=>x=4

x=4

\(\dfrac{1}{2}\) \(\times\) ( \(x\) - \(\dfrac{2}{3}\)) - \(\dfrac{1}{3}\) \(\times\) ( 2\(x\)  - 3) = \(x\)

\(\dfrac{1}{2}\)  \(\times\) \(\dfrac{3x-2}{3}\) -   \(\dfrac{2x-3}{3}\) = \(x\)

\(\dfrac{3x-2}{6}\) - \(\dfrac{4x-6}{6}\) = \(\dfrac{6x}{6}\)

3\(x-2-4x\) + 6 = 6\(x\) 

-\(x\) + 4 - 6\(x\) = 0

7\(x\)  = 4

    \(x\) =  \(\dfrac{4}{7}\) 

(x + 1 ) + (x + 2) + (x + 3) + ... + (x + 100) = 7450

(x + x + x + ... + x) + (1 + 2 + 3 + ... + 100) = 7450

     100 số x                    100 số hạng

100.x + (1 + 100).100:2 = 7450

100.x + 101.50 = 7450

100.x + 5050 = 7450

100.x = 7450 - 5050

100.x = 2400

x = 2400 : 100

x = 24

Vậy x = 24

(x+1)+(x+2)+(x+3)+......+(x+100)=7450

=> 100x + (1 + 2 + 3 + ...+ 100) = 7450 

=> 100x + 5050 = 7450

=> 100x = 2400

=> x = 24

(x+1)+(x+2)+(x+3)+...+(x+100)=7450

(x+x+x+...+x)+(1+2+3+...+100)=7450

100x+5050=7450

100x=7450-5050

100x=2400

x=24.

(x - 1) (x + 1) - (x + 1) (x + 2) = - 19

<=> x² - 1 - (x² + 3x + 2) = - 19

<=> x² - 1 - x² - 3x - 2 = -19

<=> - 3x = -16

<=> x = 16/3

vậy x = 16/3

(2x - 1) .3 - (x + 3). (-2) = -x +1

<=> (6x - 3) - (-2x - 6 ) = 1 - x

<=> 6x - 3 + 2x + 6 = 1 - x

<=> 8x + 3 = 1 - x

<=> 9x = - 2

<=> x = - 2/9

vậy x = - 2/9

Bài 1: Tìm x

a) x . (x + 3) = 0

=> \(\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=0\\x=0-3\end{cases}}\)

=> \(\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)

b) (x -1) (x² - 1) = 0

=> \(\orbr{\begin{cases}x-1=0\\x^2-1=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=0+1\\x^2=0+1\left(bỏ\right)\end{cases}}\)

=> x = 1

Bài 2: Tìm x, biết

a) -12(x - 5) + 7(3 - x) = 5

-12x - (-12 . 5) + 7 . 3 - 7x = 5

-12x + 60 + 21 - 7x = 5

-12x - 7x = 5 - 21 - 60

-19x = -76

x = -76 : (-19)

x = 4

Thanks pạn nha