\(a.x+\dfrac{1}{6}=-\dfrac{3}{8}\)

\(\Leftrightarrow x=-\dfrac{13}{24}\)

\(b.2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)

\(\Leftrightarrow2-\dfrac{3}{4}+x=\dfrac{7}{12}\)

\(\Leftrightarrow x=-\dfrac{2}{3}\)

\(c.\dfrac{1}{2}x+\dfrac{1}{8}x=\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{5}{8}x=\dfrac{3}{4}\)

\(\Leftrightarrow x=\dfrac{6}{5}\)

\(d.75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)

\(=\dfrac{75}{100}-\dfrac{3}{2}+\dfrac{1}{2}:\dfrac{5}{12}-\dfrac{1}{4}\)

\(=-\dfrac{3}{4}+\dfrac{6}{5}-\dfrac{1}{4}\)

\(=\dfrac{1}{5}\)

a) \(x+\dfrac{1}{6}=\dfrac{-3}{8}\)

            \(x=\dfrac{-3}{8}-\dfrac{1}{6}\)

           \(x=\dfrac{-13}{24}\)

vậy x =....

b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)

             \(\dfrac{3}{4}-x=2-\dfrac{7}{12}\)

             \(\dfrac{3}{4}-x=\dfrac{17}{12}\)

                    \(x=\dfrac{3}{4}-\dfrac{17}{12}\)

                   \(x=\dfrac{-2}{3}\)

vậy x =....

a) \(\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

 0,5 x + 0,6 ( x - 2 ) = 3

0,5 x + 0.6 x - 1,2 = 3

1,1 x = 4,2

x = \(\frac{42}{11}\)

Kết luận: 

b) \(\frac{1}{3}x-0,5x=0,75\)

\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(-\frac{1}{6}x=\frac{3}{4}\)

\(x=-\frac{9}{2}\)

Kết luận: 

c) \(\frac{3}{-2}x-0,5x=75\%\)

-1,5x - 0,5x = 0,75 

-2x = 0,75 

x = -0,375

Kết luận: 

d) \(-\frac{2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)

-0,4 x + 0,25 = 0,75 - 0,75 x 

-0,4 x + 0,75 x = 0,75 - 0,25

0,35 x = 0,5 

x = \(\frac{10}{7}\)

Kết luận: 

\(a,\frac{1}{2}x+\frac{3}{5}\left(x-2\right)=3\)

\(\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)

\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)

\(\frac{11}{10}x-\frac{6}{5}=3\)

\(\frac{11}{10}x=\frac{21}{5}\)

\(x=\frac{42}{11}\)

\(b,\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(\left(\frac{1}{3}-\frac{1}{2}\right)x=\frac{3}{4}\)

\(\frac{-1}{6}x=\frac{3}{4}\)

\(x=\frac{-9}{2}\)

\(c,\frac{3}{-2}x-\frac{1}{2}x=75\%\)

\(\left(\frac{3}{-2}-\frac{1}{2}\right)x=\frac{3}{4}\)

\(-2x=\frac{3}{4}\)

\(x=\frac{-3}{8}\)

\(\frac{-2}{5}x+\frac{1}{4}=75\%-\frac{3}{4}x\)

\(\frac{-2}{5}x+\frac{3}{4}x=\frac{3}{4}-\frac{1}{4}\)

\(\left(\frac{-2}{5}+\frac{3}{4}\right)x=\frac{1}{2}\)

\(\frac{7}{20}x=\frac{1}{2}\)

\(x=\frac{10}{7}\)

tìm x , biết :

a . 1,5 . x + 2,5 = 1

\(1,5.x=-1,5\)

\(x=\dfrac{-1,5}{1,5}\)

\(x=-1\)

b . ( 0,5 . x - 1,3 ) : 0,5 = -1,7

\(0,5.x-1,3=-0,85\)

\(0,5x=-2,15\)

\(x=\dfrac{-2,15}{0,5}\)

\(x=-4,3\)

c . 1,75 .x - 1,5 . x = 0,84

\(x\left(1,75-1,5\right)=0,84\)

\(x.0,25=0,84\)

\(x=3,36\)

d . x + 75% . x + 125% = 1

\(x+\dfrac{75}{100}.x+\dfrac{125}{100}=1\)

\(x+\dfrac{3}{4}.x+\dfrac{5}{4}=1\)

\(x+\dfrac{3}{4}.x=-\dfrac{1}{4}\)

\(x.\left(1+\dfrac{3}{4}\right)=-\dfrac{1}{4}\)

\(x.1,75=-\dfrac{1}{4}\)

\(x=-\dfrac{1}{7}\)

e . x - 25% .x + 75% = 1

\(x-\dfrac{25}{100}.x+\dfrac{75}{100}=1\)

\(x-\dfrac{1}{4}.x+\dfrac{3}{4}=1\)

\(x-\dfrac{1}{4}.x=\dfrac{1}{4}\)

\(x.\left(1-\dfrac{1}{4}\right)=\dfrac{1}{4}\)

\(x.\dfrac{3}{4}=\dfrac{1}{4}\)

\(x=\dfrac{1}{3}\)

f . | x - 1,5 | = 2,37

TH1 : \(x-1,5=2,37\)

\(x=2,37+1,5\)

\(x=3,87\)

TH2 : \(x-1,5=-2,37\)

\(x=-2,37+1,5\)

\(x=-0,87\)

ko biet ket qua

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Tính ra giờ hay s bạn

Tính ra giờ hay s đấy bạn

\(\Leftrightarrow\dfrac{3}{4}x+\dfrac{1}{4}x+x:\dfrac{1}{2}=33,6\\ \Leftrightarrow\dfrac{3}{4}x+\dfrac{1}{4}x+2x=33,6\\ \Leftrightarrow\left(\dfrac{3}{4}+\dfrac{1}{4}+2\right)x=33,6\\ \Leftrightarrow3x=33,6\\ \Leftrightarrow x=33,6:3\\ \Leftrightarrow x=11,2\)

`75`%\(\times x+0,25\times x+x:0,5=33,6\)

\(0,75\times x+0,25\times x+x\times2=33,6\)

\(x\times(0,75+0,25+2)=33,6\)

\(x=3=33,6\)

`x=33,6:3`

`x=11,2`

=>0,75x-0,5x=3/4

=>1/4x=3/4

hay x=3

\(75\%\cdot x-0,5\cdot x=\dfrac{3}{4}\)

\(\dfrac{3}{4}\cdot x-\dfrac{1}{2}\cdot x=\dfrac{3}{4}\)

\(\left(\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot x=\dfrac{3}{4}\)

\(\dfrac{1}{4}\cdot x=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:\dfrac{1}{4}\)

\(x=\dfrac{12}{4}\)

\(x=3\)

x . (3/4 - 1/2 ) = 3/4

x . 1/4            =  3/4

x                    = 3/4 : 1/4

x                    = 3