- Đây có phải là toán lớp 8 nữa không vậy :)? Mình học toán nâng cao nhưng chưa bao giờ thấy dạng này :).

b1:

do x;y thuộc số nguyên N và x,y\(\ge\)2

=>\(-4xy+1< +7x-7y< 4xy+1\)

\(\Rightarrow4x^2y^2-4xy+1< 4x^2y^2+7x-7y< 4x^2y^2+4xy+1\)

\(\Rightarrow\left(2xy-1\right)^2< 4x^2y^2+7x-7y< \left(2xy+1\right)^2\)

mà \(4x^2y^2+7x-7y\) là số chính phương và 1<2xy-1<2xy-1 nên ta có:

\(4x^2y^2+7x-7y-\left(2xy\right)^2\Leftrightarrow x=y\)

1.

TH1: \(x>0\Rightarrow7\left(x-y\right)>0\Rightarrow A>4x^2y^2\)

\(4xy-7x+7y+1>4xy-8x+7y+1=4x\left(y-2\right)+7y+1>0\) do \(x;y\ge2\)

\(\Rightarrow4xy+1>7x-7y\Rightarrow A< 4x^2y^2+4xy+1\)

\(\Rightarrow\left(2xy\right)^2< A< \left(2xy+1\right)^2\)

\(\Rightarrow A\) nằm giữa 2 SCP liên tiếp nên ko thể là SCP

TH2: \(x< y\) , tương tự ta có: \(7\left(x-y\right)< 0\Rightarrow A< 4x^2y^2\)

\(4xy+7x-7y-1>4xy+7x-8y-1=4y\left(x-2\right)+\left(7x-1\right)>0\)

\(\Rightarrow7x-7y>-4xy+1\Rightarrow A>4x^2y^2-4xy+1\)

\(\Rightarrow\left(2xy-1\right)^2< A< \left(2xy\right)^2\)

\(\Rightarrow A\) ko thể là SCP

TH3: \(x=y\Rightarrow A=\left(2xy\right)^2\) là SCP (thỏa mãn)

Vậy \(x=y\)

tk:

\(a,=x^2+x+4x+4=\left(x+1\right)\left(x+4\right)\\ b,=x^2+2x-3x-6=\left(x-3\right)\left(x+2\right)\\ c,=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\\ d,=3\left(x^2-2x+5x-10\right)=3\left(x-2\right)\left(x+5\right)\\ e,=-3x^2+6x-x+2=\left(x-2\right)\left(1-3x\right)\\ f,=x^2-x-6x+6=\left(x-1\right)\left(x-6\right)\\ h,=4\left(x^2-3x-6x+18\right)=4\left(x-3\right)\left(x-6\right)\\ i,=3\left(3x^2-3x-8x+5\right)=3\left(x-1\right)\left(3x-8\right)\\ k,=-\left(2x^2+x+4x+2\right)=-\left(2x+1\right)\left(x+2\right)\\ l,=x^2-2xy-5xy+10y^2=\left(x-2y\right)\left(x-5y\right)\\ m,=x^2-xy-2xy+2y^2=\left(x-y\right)\left(x-2y\right)\\ n,=x^2+xy-3xy-3y^2=\left(x+y\right)\left(x-3y\right)\)

Bào quan riboxom trong chất tế bào có chức năng gì? 

a) \(=\left(x^2+x\right)+\left(4x+4\right)=x\left(x+1\right)+4\left(x+1\right)=\left(x+1\right)\left(x+4\right)\)

b) \(=\left(x^2+2x\right)-\left(3x+6\right)=x\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(x-3\right)\)

c) \(=\left(x^2-2x\right)-\left(3x-6\right)=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)

d) \(3x^2+9x-30=3\left(x^2+3x-10\right)=3\left[\left(x^2+5x\right)-\left(2x+10\right)\right]=3\left[x\left(x+5\right)-2\left(x+5\right)\right]=3\left(x-2\right)\left(x+5\right)\)

e) \(=-\left(3x^2-5x-2\right)=-\left[\left(3x^2-6x\right)+\left(x-2\right)\right]=-\left[3x\left(x-2\right)+\left(x-2\right)\right]=-\left(3x+1\right)\left(x-2\right)\)

f) \(x^2-7x+6=\left(x^2-x\right)-\left(6x-6\right)=x\left(x-1\right)-6\left(x-1\right)=\left(x-1\right)\left(x-6\right)\)

h) \(=4\left(x^2-9x+14\right)=4\left[\left(x^2-7x\right)-\left(2x-14\right)\right]=4\left[x\left(x-7\right)-2\left(x-7\right)\right]=4\left(x-2\right)\left(x-7\right)\)

i) \(=3\left(3x^2-8x+5\right)=3\left[\left(3x^2-3x\right)-\left(5x-5\right)\right]=3\left[3x\left(x-1\right)-5\left(x-1\right)\right]=3\left(x-1\right)\left(3x-5\right)\)

k) \(=-\left(2x^2+5x+2\right)=-\left[\left(2x^2+4x\right)+\left(x+2\right)\right]=-\left[2x\left(x+2\right)+\left(x+2\right)\right]=-\left(x+2\right)\left(2x+1\right)\)

l) \(=\left(x^2-5xy\right)-\left(2xy-10y^2\right)=x\left(x-5y\right)-2y\left(x-5y\right)=\left(x-5y\right)\left(x-2y\right)\)

m) \(=\left(x^2-2xy\right)-\left(xy-2y^2\right)=x\left(x-2y\right)-y\left(x-2y\right)=\left(x-2y\right)\left(x-y\right)\)

n) \(=\left(x^2-3xy\right)+\left(xy-3y^2\right)=x\left(x-3y\right)+y\left(x-3y\right)=\left(x+y\right)\left(x-3y\right)\)

what is her mother going to prepare for her bỉthdat party

there are three sticks of butter in the cupboard

i have enough food for the first three day of your stay

mắ nhìn cún sách ám ảnh vải sau có key với giải thích chi tiết á b

Giusp mình với mọi người ơi!!!

 1 had better eat more fruits and vegetables.

2 likes painting very much.

3 play  card.

*Le's -> Let's

4 had better not eat canned  food.

5 don't we go camping for some days?