a. 215 - 5 + 10 = 210 + 10 = 220

b. 13 + (-17) = -4

c. 25 . 5 . 2014 . 4 . 2 = (25 . 4) . (5 . 2) . 2014 = 100 . 10 . 2014 = 1000 . 2014 = 2014000

đ. 24.35 + 76.35 - 500 = (24 + 76) . 35 - 500 = 100 . 35 - 500 = 3500 - 500 = 3000

e. 3 + 7 + 11 + 15 + ... + 399 + 403 = 406 . 101 : 2 = 20503

ta có 

A=\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{19.21}=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{19}-\frac{1}{21}=\frac{1}{3}-\frac{1}{21}=\frac{2}{7}\)

\(=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+....+\frac{2}{19.21}\)

\(=2\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{19.21}\right)\)

\(=2\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\right)\)

\(=2\left(\frac{1}{3}-\frac{1}{21}\right)\)

=\(\frac{4}{7}\)

\(A=\)\(\frac{2}{3.5}+\frac{2}{5.7}+.....+\frac{2}{19.21}\)\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{19}-\frac{1}{21}=\frac{1}{3}-\frac{1}{21}=\frac{2}{7}\)

a) A = 37. 173 +62. 173 + 173

= 173. (37 +62 + 1)

= 173.100

= 17 300

b) B = 72.99 + 28.99 - 900

= 99. (72+28) - 900

= 99.100 - 900

= 9 900 - 900

= 9 000

c) C = 2³.3-(1¹⁰ + 15): 4²

= 8.3 - (1 + 15): 4²

= 8.3 - 16:4²

= 8.3 - 1

= 23.

d) D = 6²: 4.3 + 2.5² - 201⁰

= 36:4.3 + 2.25 - 1

= 27 + 50 - 1

= 76.

Ba biểu thức: 4 x 3 – 2; 15 + 2 – 10; 30 – 25 : 5.

Ta có 

Vậy B = 1.

a,  15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0

= 15.{32:[1+15]+3}–1

= 15.5–1

= 74

b,  25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }

= 25.{128:[8+4.2]–16}

= 25.24

= 600

c,  2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }

= 2019.{101–1000:[(32+125–36):11–1]}

= 2019.{101–1000:[121:11–1]}

= 2019.{101–1000:10}

= 2019.1

= 2019