\(\frac{10^3+2\times5^3+5^3}{55}\)= \(\frac{1000+2\times125+125}{55}\)= \(\frac{1000+250+125}{55}\)= \(\frac{1250+125}{55}\)= \(\frac{1375}{55}\)= 25.

\(=\dfrac{5^3\cdot2^3+2\cdot5^3+5^3}{55}=\dfrac{5^3\left(2^3+2+1\right)}{55}=5^2=25\)

\(\frac{10^3+2.5^3+5^3}{55}\)

\(=\frac{\left(2.5\right)^3+2.5^3+5^3}{5.11}\)

=\(\frac{2^3.5^3+2.5^3+5^3}{5.11}\)

=\(\frac{5^3.\left(2^3+2+1\right)}{5.11}\)

=\(\frac{5^3.\left(8+2+1\right)}{5.11}\)

=\(\frac{5^3.11}{5.11}\)

=\(5^2\)

=25

Chúc bn học tốt !

\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)

\(A=\left(\frac{\frac{3}{2}+1-\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{4}}+\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{-5}{8}+\frac{1}{2}-\frac{5}{11}-\frac{5}{12}}\right):\frac{378}{401}+115\)

\(A=\left(\frac{3.\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}{5.\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}+\frac{-3.\left(\frac{-1}{8}+\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)}{5.\left(\frac{-1}{8}+\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)}\right).\frac{401}{378}+115\)

\(A=\left(\frac{3}{5}+\frac{-3}{5}\right).\frac{401}{378}+115\)

\(A=0.\frac{401}{378}+115=115\)

A = \(\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)

= \(\left(\frac{\frac{3}{2}+\frac{3}{3}-\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{4}}+\frac{\frac{3.125}{100}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{-\frac{5.125}{100}+\frac{5}{10}-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)

= \(\left(\frac{3\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}+\frac{3\left(\frac{125}{100}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}{-5\left(\frac{125}{100}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}\right):\frac{1890}{2005}+115\)

= \(\left(\frac{3}{5}+-\frac{3}{5}\right):\frac{1890}{2005}+115\)

= 115

\(A=\left(\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}\right):\frac{1890}{2005}+115\)

\(=\left(\frac{\frac{3}{2}+\frac{3}{3}-\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{4}}+\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{-5}{8}+\frac{5}{10}-\frac{5}{11}-\frac{5}{12}}\right):\frac{378}{401}+115\)

\(=\left(\frac{3\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}\right)}+\frac{3\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}{-5\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}-\frac{1}{12}\right)}\right):\frac{378}{401}+115\)

\(=\left(\frac{3}{5}+\frac{-3}{5}\right).\frac{401}{378}+115\)

\(=0.\frac{401}{378}+115\)

\(=115\)

Vậy A = 115

= 25 nha bạn 

các bạn tick mình cho tròn 220 điểm hỏi đáp với

\(=\frac{5^3.\left(2^3+2+1\right)}{55}=\frac{5^2.5.11}{5.11}=5^2=25\)

Lần sau bạn nên viết đề rõ hơn nhé!

Đề: Tính nhanh: \(\frac{10^3+2\cdot5^3+5^3}{55}\)

ta có: \(\frac{10^3+2\cdot5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{5\cdot11}=\frac{5^3\cdot11}{5\cdot11}=5^2=25\)

Học tốt nhé ^3^

Ta có : \(\frac{10^3+2.5^3+5^3}{55}=\frac{2^3.5^3+2.5^3+5^3}{5.11}=\frac{5^3\left(2^3+2+1\right)}{5.11}=\)\(\frac{5^3.11}{5.11}=5^2=25\)

Vậy \(\frac{10^3+2.5^3+5^3}{5.11}\)=25.

\(=\frac{5^3\cdot2^3+2+5^3}{55}=\frac{5^3\left(8+2+1\right)}{55}=\frac{125\cdot11}{11\cdot5}=\frac{25\cdot1}{1\cdot1}=25\)

25

AI TICK GIÙM MÌNH MỘT CÁI ĐI MÀ!!!!!!!!!!!!!!!!!!!!!