Violympic toán 7
Các câu hỏi tương tự
\(\frac{10^3+2.5^3+5^3}{55}\)
\(\frac{10^3+2.5^3+5^3}{55}\)
giúp mk vs
\(\dfrac{10^3+2.5^3+5^3}{55}\)
\(\dfrac{10^3+2.5^3+5^3}{55}\)
\(\dfrac{10^3+2.5^3+5^3}{55}-\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
tính:
\(b.\dfrac{10^3+2.5^3+5^3}{55}\)
helpppp me! mk sắp phải nọp rùi huhu
Tính :\(A=\frac{115-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{22}}+\frac{\frac{3}{5}+\frac{3}{13}-0,9}{\frac{7}{91}+0,2-\frac{3}{10}}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Thực hiện phép tính:
A=\(\frac{155-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{23}}+\frac{\frac{3}{5}+\frac{3}{13}-0,9}{\frac{7}{91}+0,2-\frac{3}{10}}\)