Ta có:
\(\frac{10^{3^{ }}+2.5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{55}=\frac{5^3.11}{55}=25\)
Violympic toán 7
Các câu hỏi tương tự
\(\dfrac{10^3+2.5^3+5^3}{55}\)
\(\dfrac{10^3+2.5^3+5^3}{55}\)
\(\dfrac{10^3+2.5^3+5^3}{55}-\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{10^3+2.5^3+5^3}{55}\)
giúp mk vs
\(\frac{10^3+2.5^3+5^3}{55}\)
\(\frac{10^3+2.5^3+5^3}{55}\)
Tìm x, biết:
a) \(12-\left|x-3\right|=5x+8\)
b) \(\left(\sqrt{x}+3\right)^{10}=1024.125^2.25^2\)
c) \(\dfrac{3-0,2x}{5}=\dfrac{7}{15}+1,4x\)
d) \(\left(\dfrac{64}{27}\right)^x=\dfrac{4.5^9.7^{10}-5^{11}.7^9}{35^9.4}\)
Các bn giúp mk nhanh nha. Tối nay mk phải nộp cho thầy r. Mk sẽ tick cho.
a)\(\dfrac{a}{3}=\dfrac{b}{5},\dfrac{b}{3}=\dfrac{c}{2}\) a+b+c=27
b)\(\dfrac{2x}{5}=\dfrac{y}{9}=\dfrac{z}{7}\) và y-z=10
Giups mk vs ~!
Tìm x biết : \(\dfrac{\left(6\dfrac{3}{5}-3\dfrac{3}{16}\right).5\dfrac{5}{6}}{\left(21-1,25\right):x}=2,5\)
Help me !!!! Mai mik phải nộp òi thank trc nhiều...