1)1/x+2y +1/y+2x=3
4/x+2y - 3/y+2x=9
2)3x/x+1 -2/y+4=4
2x/x+1 -5/y+4=9
Những câu hỏi liên quan
phân tích đa thức thành nhân tử 1, A = 2x^2 + 5x^3 + x^2y 2, A = 4x^2y - 8xy^2 + 18x^2y^2 3, A = -3x^2y + 6x^2 y^2 4, A = 2x^3 y^4 - 4x^5 y^6 + 6y^7 x^8 5, A = 14x^2y - 21xy^2 + 28x^2 y^2 6, A = -8x^4 y^3 - 12x^2 y^4 + 20x^3 y^4 7, A = 5x . (x - 1) - 15x . (1 - x) 8, A = 2x^2 . (y - 1) - 15x . (1 - x) 9, A = 9x^2 . (y + z ) + 3x . (y + z) 10, A = 10x . ( x - y) - 8y . (y - x) 11, A = 2x . ( x + y) - 6x^2 . (x + y) 12, A = 10xy . ( x - y) - 6y . (y - x) giải giúp e với ạ
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Bài 1
1) (x^2-2x+3)*(x-4)
2) (2x^2-3x-1)*(5x+2)
3) (x^2-2xy+y^2)*(y^2+2xy+x^2+1)
4) (x-7)*(x+5)*(x-5)
5) (x+2y)*(x-y)
6) (x+5)*(x^2-2x+3)
7) 2x(x+5)*(x-1)
8) (x-2y)*(x+2y)
9) (x-1)*(x^2+x+1)
10) (1-2x^2+x)*(x-4+x^2)
1. (2x+3y)^2
2. (5x-y)^2
3. (2x+y^2)^3
4. (2x-1) (4x^2+2x+1)
5. (5+3x)^3
6.(x^2+2/5y) (x^2-2/5y)
7.(x+1/4)^2
8. (2/3x^2-1/2y)^3
9. (3x^2-2y)^3
10.(x-3y) (x^2+3xy+9y^2)
11. (x^2-3) (x^4+3x^2+9)
12. (x+2y+z) (x+2y-z)
mn giúp em với
Bài 20*: Tìm x,y nguyên sao cho.1) 2y. (x+1)=6 2) (2x-1). (y-2)=6 3) (2x-4). 2y= -12 4) (2x-2y).3x=-36 5) (x+y+1). (2y+3)=36
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1, ( x+1/3)^3
2, ( 2x+y^2)^3
3, ( 1/2x^2+1/3y)^3
4, ( 3x^2-2y)^3
5, ( 2/3x^2-1/2y)^3
6, ( 2x+1/2)^3
7, ( x-3)^3
8, ( x+1).(X^2+3x+9)
9, ( x-3).( x^2+3x+9)
10, ( x-2).( x^2+2x+4)
11, ( x+4).( x^2-4x+16)
12, ( x-3y).( x^2+3xy+9y^2)
13, ( x^2-1/3). ( x^4+1/3x^2+1/9)
14, ( 1/3x+2y).( 1/9x^2-2/3xy+4y^2)
Đưa về HĐT
giải giúp mik bt này vs mn!
1)left{{}begin{matrix}2x^2+y^2+x3left(xy+1right)+2ydfrac{2}{3+sqrt{2x-y}}+dfrac{2}{3+sqrt{4-5x}}dfrac{9}{2x-y+9}end{matrix}right.
2)left{{}begin{matrix}left(x+3y+1right)sqrt{2xy+2y}yleft(3x+4y+3right)left(sqrt{x+3}-sqrt{2y-2}right)left(x-3+sqrt{x^2+x+2y-4}right)4end{matrix}right.
3)left{{}begin{matrix}x-dfrac{1}{x}y-dfrac{1}{y}2yx^3+1end{matrix}right.
4)left{{}begin{matrix}sqrt{2x-3}left(y^2+2011right)left(5-yright)+sqrt{y}yleft(y-x+2right)3x+3end{matrix}right.
5...
Đọc tiếp
giải giúp mik bt này vs mn!
1)\(\left\{{}\begin{matrix}2x^2+y^2+x=3\left(xy+1\right)+2y\\\dfrac{2}{3+\sqrt{2x-y}}+\dfrac{2}{3+\sqrt{4-5x}}=\dfrac{9}{2x-y+9}\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}\left(x+3y+1\right)\sqrt{2xy+2y}=y\left(3x+4y+3\right)\\\left(\sqrt{x+3}-\sqrt{2y-2}\right)\left(x-3+\sqrt{x^2+x+2y-4}\right)=4\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x-\dfrac{1}{x}=y-\dfrac{1}{y}\\2y=x^3+1\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}\sqrt{2x-3}=\left(y^2+2011\right)\left(5-y\right)+\sqrt{y}\\y\left(y-x+2\right)=3x+3\end{matrix}\right.\)
5)\(\left\{{}\begin{matrix}x^3+2x^2=x^2y+2xy\\2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14=x-2}\end{matrix}\right.\)
5,\(hpt\Leftrightarrow\left\{{}\begin{matrix}x\left(x+y\right)\left(x+2\right)=0\\2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14}=x-2\end{matrix}\right.\)
Thay từng TH rồi làm nha bạn
3,\(hpt\Leftrightarrow\left\{{}\begin{matrix}x-y=\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}\\2y=x^3+1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x-y\right)\left(1+\frac{1}{xy}\right)=0\\2y=x^3+1\end{matrix}\right.\)
thay nhá
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Bài 1:ĐKXĐ: \(2x\ge y;4\ge5x;2x-y+9\ge0\)\(\Rightarrow2x\ge y;x\le\frac{4}{5}\Rightarrow y\le\frac{8}{5}\)
PT(1) \(\Leftrightarrow\left(x-y-1\right)\left(2x-y+3\right)=0\)
+) Với y = x - 1 thay vào pt (2):
\(\frac{2}{3+\sqrt{x+1}}+\frac{2}{3+\sqrt{4-5x}}=\frac{9}{x+10}\) (ĐK: \(-1\le x\le\frac{4}{5}\))
Anh quy đồng lên đê, chắc cần vài con trâu đó:))
+) Với y = 2x + 3...
giải các hệ phương trình:
1, 2x+3|y-1|=5 và 3x+2y=7
2, |x+1|+|y-1|=5 và |x+1|-4y+4=0
3, (2x+1)/4-(y-3)/3=1/12 và (x+5)/2=(y+7)/3 -4
4, 1/x+1/y=1/12 và 8/x+15/y=1
5, 2/(x+2y) +1/(y+2x)=3 và 4/(x+2y) -3/(y+2x)=1
Tìm x thỏa mãn điều kiện
(2x+1)^3-(2x+1).(4x^2-2x+1)-3.(2x-1)^2=15
y.(y+3)^2-(y+2).(y^2-2y+4)-6.(y+5).(y-5)=97
(x-3)^3-(x-3).(x^2+3x+9)+9.(x+1)^2=18
x.(x-4).(x+4)-(x-5).(x^2+5x+25)=13
2.Rút gọn biểu thức rồi tính giá trị
3.(x-1).(x^2+x+1)+(x-1)^3-4x.(x+1).(x-1) tại x=-1
(3xy-2).(9x^2y^2+6xy+4)-3xy.(3xy+1)^2 tại x=-2010,y=-1/2010
Bài 2:
a: \(3\left(x-1\right)\left(x^2+x+1\right)+\left(x-1\right)^3-4x\left(x+1\right)\left(x-1\right)\)
\(=3\left(x^3-1\right)+x^3-3x^2+3x-1-4x\left(x^2-1\right)\)
\(=3x^3-3+x^3-3x^2+3x-1-4x^3+4x\)
\(=-3x^2+7x-4\)
\(=-3\cdot\left(-1\right)^2+7\cdot\left(-1\right)-4\)
=-3-4-7=-14
b: \(=27x^3y^3-8-3xy\left(9x^2y^2+6xy+1\right)\)
\(=27x^3y^3-8-27x^3y^3-18x^2y^2-3xy\)
\(=-18x^2y^2-3xy-8\)
\(=-18\cdot\left[\left(-2010\right)\cdot\left(-\dfrac{1}{2010}\right)\right]^2-3\cdot\left(-2010\right)\cdot\dfrac{-1}{2010}-8\)
\(=-18-3-8=-29\)
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a, x^2-36/2x+10*3/6-x
b,5x-15/4x+4:x^2-9/x^2+2x+1
c,3-2x/ x^2-9 + 1/2x-6
d, -5/4+2y + y-2/2y+y^2
nhìn mà mù mắt , rắc rối vl
\(\frac{x^2-36}{2x+10}.\frac{3}{6-x}\)
\(=\frac{\left(x^2-36\right).3}{\left(2x+10\right)\left(6-x\right)}\)
\(=\frac{3\left(x+6\right)\left(x-6\right)}{\left(2x+10\right)\left(6-x\right)}\)
\(=-\frac{3\left(x+6\right)\left(x-6\right)}{2\left(x+5\right)\left(x-6\right)}\)
\(=-\frac{3\left(x+6\right)}{2\left(x+5\right)}\)