mình cũng hỏi về cái này gấp nha ai biết trả lời câu nào thì trả

a) \(2^{4x}-3^{2x}=144-164:41\)

\(\Leftrightarrow16^x-9^x=144-4\)

\(\Leftrightarrow\) ......

bjan tự tính tiếp đc òi                 

\(\dfrac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{29}\cdot9^{10}-7\cdot2^{29}\cdot27^6}\)

\(=\dfrac{5\cdot2^{30}\cdot3^{18}-2^2\cdot2^{27}\cdot3^{20}}{5\cdot2^{29}\cdot3^{20}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{29}\cdot3^{18}\left(5\cdot3^2-7\right)}\)

\(=\dfrac{10-9}{5\cdot9-7}=\dfrac{1}{38}\)

\(A=5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9\)

\(A=5\cdot\left(2^2\right)^{15}\cdot\left(3^2\right)^9-2^2\cdot3^{20}\cdot\left(2^3\right)^9\)

\(A=5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}\)

\(A=5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}\)

\(A=2^{29}\cdot3^{18}\cdot\left(5\cdot2^1\cdot1-1\cdot3^2\right)\)

\(A=2^{29}\cdot3^{18}\cdot\left(5-9\right)\)

\(A=-2^2\cdot2^{29}\cdot3^{18}\)

\(A=-2^{31}\cdot3^{18}\)

_______________

\(B=5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6\)

\(B=5\cdot2^9\cdot2^{19}\cdot3^{19}-7\cdot2^{29}\cdot\left(3^3\right)^6\)

\(B=5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}\)

\(B=2^{28}\cdot3^{18}\cdot\left(5\cdot1\cdot3-7\cdot2\cdot1\right)\)

\(B=2^{28}\cdot3^{18}\cdot\left(15-14\right)\)

\(B=2^{28}\cdot3^{18}\)

Ta có: \(A:B\)

\(=\left(-2^{31}\cdot3^{18}\right):\left(2^{28}\cdot3^{18}\right)\)

\(=\left(-2^{31}:2^{28}\right)\cdot\left(3^{18}:3^{18}\right)\)

\(=-2^3\cdot1\)

\(=-8\)

a) 2^x : 4 = 128

=> 2x  = 512

=> 2^x  = 2⁹

=> x = 9

b) x¹⁵ = x

=> x¹⁵  = x¹⁵

=> x = 1 hoặc 0

c) ( 2x + 1 )³ = 125

=> ( 2x + 1 )³ = 5³

=> 2x + 1 = 5

=> 2x = 4

=> x = 2

a) 2^x : 4 = 128

=> 2^x = 128 . 4

=> 2^x = 512

=> 2^x = 2⁹

=> x = 9

b) x¹⁵ = x

=> x¹⁵ = x¹⁵

=> x = 1 hoặc 0

c) ( 2x + 1 )³ = 125

=> ( 2x + 1 )³ = 5³

=> 2x + 1 = 5

=> 2x = 5 - 1

=> 2x = 4

=> x = 4 : 2

=> x = 2

a) \(\left(x-1\right)^2=49\)

\(\Rightarrow\left(x-1\right)^2=7^2=\left(-7\right)^2\)

\(\Rightarrow x-1=7\)                        hoặc                           \(x-1=-7\)

\(x=7+1=8\)                                                                \(x=-7+1=-6\)

Vậy x = 8 hoặc x = - 6

b) \(3\cdot\left(13-x\right)^2=27\)

\(\left(13-x\right)^2=27\div3=9\)

\(\Rightarrow\left(13-x\right)^2=3^2=\left(-3\right)^2\)

\(\Rightarrow13-x=3\)                                          hoặc                                    \(13-x=-3\)

\(x=13-3=10\)                                                                                            \(x=13+3=16\)

Vậy x = 10 hoặc x = 16

c) \(164-\left(15-x\right)^3=100\)

\(\left(15-x\right)^3=164-100=64\)

\(\Rightarrow\left(15-x\right)^3=4^3\)

\(\Rightarrow15-x=4\)

\(x=15-4=11\)

Vậy x = 11

d) \(\left(x+3\right)^3-15=210\)

\(\left(x+3\right)^3=210+15=225\)

\(\Rightarrow\left(x+3\right)^3=...\)

Tương tự mũ lẻ cậu nhé

e) \(x^2\div4=16\)

\(x^2=16\cdot4=64\)

\(\Rightarrow x^2=8^2=\left(-8\right)^2\)
Vậy x = 8 hoặc x = - 8

a/\(\left(x-1\right)^2\)=49

\(\left(x-1\right)^2\)=\(7^2\)

=>x-1=7

x=7+1

x=8

b/3.\(\left(13-x\right)^2\)=27

\(\left(13-x\right)^2\)=27:3

\(\left(13-x\right)^2\)=9

\(\left(13-x\right)^2\)=\(3^2\)

=>13-x=3

x=13-3

x=10

c/164-\(\left(15-x\right)^3\)=100

\(\left(15-x\right)^3\)=164-100

\(\left(15-x\right)^3\)=64

\(\left(15-x\right)^3\)=\(4^3\)

=>15-x=4

x=15-4

x=11

d/\(\left(x+3\right)^3\)-15=210

\(\left(x+3\right)^3\)=210+15

\(\left(x+3\right)^3\)=225

sai đề bài câu d hay sao ý bạn ạ 

chỉ có \(\left(x+3\right)^2\)thì mới tính được

e/\(x^2\):4=16

\(x^2\)=16.4

\(x^2\)=64

\(x^2\)=\(8^2\)

=>x=8

a)145-5[8^2-4:15]=145-5[64-4/15]=145-5.956/15=145-956/3=-521/3

b)13^2-3[15-16^2]=13^2-3.-241=169--723=892

giải chi tiết hộ mình ạ

chịu

Chịu 

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