1)
a)12.32-23.(20150+13)
b)175-[(32-23).5-15]:3
c)18.37+18.64+18
Tính nhanh :
18 . 37 + 18 . 64 - 18
175 - [( 32 - 23 ) . 5 - 15 ] : 3
mk chỉ km dc câu đầu thoiii,SORRY
18.37+18.64-18
=18.37+18.64-18.1
=18.(37+64-1)
=18.100=1800
hc tốt#
a)18.37+18.64-18
=18.(37+64-1)
=18.100
=1800
b)175-[(32-23).5-15]:3
=175-(9.5-15):3
=175-30:3
=175-10
=165
nhớ k cho mk nha
Bài 1 Tính nhanh
a) -3/7 + 5/13 + 3/7
b) -5/21+-2/21+8/24
c) -5/11+(-6/11+2)
d) (-1/32+1/2)+15/32
e)5/17+ -6/13 + 3/4 + 7/-13+12/17
f) 7/23+-18/18+-4/9+16/23+-5/8
g)1/3+-3/4+3/5+-1/36+1/15+-2/9
h)-1/2+1/3+-1/4+-2/8+4/18+4/9
a)\(-\dfrac{3}{7}+\dfrac{5}{13}+\dfrac{3}{7}\)
=\(\left(-\dfrac{3}{7}+\dfrac{3}{7}\right)+\dfrac{5}{13}\)
=\(0+\dfrac{5}{13}\)
=\(\dfrac{5}{13}\)
Bài 2: Thực hiện phép tính (tính hợp lí nếu có thể) a, 4 . 52 – 18 : 32 b, 32. 22 - 32 . 19 c, 24 . 5 - [131- (13 - 4)2] d, 100: {250 : [450 - (4 . 53 – 22 . 25)]} e, 23 . 15 – [115 - (12 - 5)2] f, 30.{175 : [355 - (135 + 37 . 5)]} g, 5871: [928 – ( 247 - 82) . 5] + 21750 |
Đáp Án
a)52:4x3+2x52
=13x3+2x52
=39+104
=143
b)5x42-18:32
=100-0.5625
=99.4375
của bạn nha
bài 1
a. 5/18 + 8/19 - 7/21 + ( -10/36 + 11/19 + 1/3) - 5/8
b.1/13 + ( -5/18 - 1/13 + 12/17 ) - ( 12/17 - 5/18 + 7/5 )
c.15/14 - (17/23 - 80/87 + 5/4)+(17/23 - 15/14 + 1/4 )
d.1/25 - 4/27 + ( -23/27 + -1/25 - 5/43 ) + 5/43 - 4/7
bài 2
a. x +1/3 = 3/4
b. x - 2/5 = 5/7
c. -x - 2/3 = -6/7
d. 4/7 - x = 1/3
e. x+ 5/2 = -3/2
f. x + 5/6 = -1/12
GIÚP MÌNH VỚI Ạ MÌNH CẢM ƠN TRƯỚC
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
Bài 1 d;
\(\dfrac{1}{25}\) - \(\dfrac{4}{27}\) + (-\(\dfrac{23}{27}\) + \(\dfrac{-1}{25}\) - \(\dfrac{5}{43}\)) + \(\dfrac{5}{43}\) - \(\dfrac{4}{7}\)
= \(\dfrac{1}{25}\) - \(\dfrac{4}{27}\) - \(\dfrac{23}{27}\) - \(\dfrac{1}{25}\) - \(\dfrac{5}{43}\) + \(\dfrac{5}{43}\) - \(\dfrac{4}{7}\)
= (\(\dfrac{1}{25}\) - \(\dfrac{1}{25}\)) - (\(\dfrac{4}{27}\) + \(\dfrac{23}{27}\)) - (\(\dfrac{5}{43}\) - \(\dfrac{5}{43}\)) - \(\dfrac{4}{7}\)
= 0 - 1 - 0 - \(\dfrac{4}{7}\)
= \(\dfrac{-11}{7}\)
ài 1: Tính giá trị của biểu thức sau:
1)2763 + 152 2)(-7) + (-14)
3)(-35) + (-9) 4)(-5) + (-248)
5)(-23) + 105 6)78 + (-123)
7)23 + (-13) 8)(-23) + 13
9)26 + (-6) 10) (-75) + 50
11)80 + (-220) 12) (-23) + (-13)
13)(-26) + (-6) 14 (-75) + (-50)
15)-18 + (-12) 16)17 + -33
17)(– 20) + -88 18) -3 + 5
19)-37 + 15 20)-37 + (-15)
21)(--32) + 5 22)(--22)+ (-16)
23)(-23) + 13 + ( - 17) + 57 24)14 + 6 + (-9) + (-14)
25) (-123) +-13+ (-7) 26) 0+45+(--455)+-796
câu nầy hơn khó nên mình ko giải đc bạn đợ mình giải đã
1) 2763 + 152 = 2951
2)(-7) + (-14) = -21
3)(-35) + (-9) =-44
4) (-5) + (-248) = -253
Bài 1: Thực hiện tính:
1) 2763 + 152 2) (– 7) + (– 14) 3) (– 35) + (– 9) 4) (–5) + (–248) 5) (–23) + 105
6) 78 + (–123) 7) 23 + (-13) 8) (– 23) + 13 9) 26 + (– 6) 10) (–75) + 50
11) 80 + (–220) 12) (–23) + (–13) 13) (– 26) + (– 6) 14) (– 75) + (–50)
15)–18 + (–12) 16) 17 + –33 17) (– 20) +-88
18) –3 + 5 19)–37 + 15 20)–37 + (–15)
21) (––32) + 5
Cho mik xin lại đề bài mik nhìn ki hiểu j hết
1)2763 + 152 = 2915
2)(-7) + (-14) = -21
3)(-35) + (-9) = -44
4; (-5) + (-248)
= - (5 + 248)
= - 253
5; (-23) + 105
= -23 + 105
= 82;
6; 78 + (-123)
= 78 - 123
= -(123 - 78)
= - 45
7; 23 + (-13)
= 23 - 13
= 10
Bài 2
a) 12+ 22 + 32 + 42+52 và (1+2+3+4+5)2
b) 13+ 23+33 +43 và (1+2+3+4)3
c) 16 . 5200 và 5202
d) 18 . 4500 và 21004
e) 2022 . 2023 2024 + 20232024 và 20232025
a: \(12+2^2+3^2+4^2+5^2\)
\(=12+4+9+16+25\)
\(=16+50=66\)
\(\left(1+2+3+4+5\right)^2=15^2=225\)
=>\(12+2^2+3^2+4^2+5^2< \left(1+2+3+4+5\right)^2\)
b: \(1^3+2^3+3^3+4^3=\left(1+2+3+4\right)^2< \left(1+2+3+4\right)^3\)
c: \(5^{202}=5^2\cdot5^{200}=25\cdot5^{200}>16\cdot5^{200}\)
d: \(18\cdot4^{500}=18\cdot2^{1000}\)
\(2^{1004}=2^4\cdot2^{1000}=16\cdot2^{1000}\)
=>\(18\cdot4^{500}>2^{1004}\)
e: \(2022\cdot2023^{2024}+2023^{2024}=2023^{2024}\left(2022+1\right)\)
\(=2023^{2025}\)
a)11/53+(32/47+-10/53)+-64/94+1/53+1/3
b) (-1+45/115+47/51)+(-9/23+-1/3)
c) -13/49+12/48+1/12+3/18
d) 13/15+(-4/5+7/18)+-5/12+1/16
Tính thuận tiện
a) A=(15 - 6 13/18) : 11 1/27 - 2 1/8 : 1 11/40
b) B=(-3,2) . -15/64 + (0,8 - 2 4/15): 3 2/3
c) C= -7/9 . 4/11 + -7/9. 7/11 + 5 7/9
d) D= 50% .1 1/3 . 10 . 7/35 . 0,75
e) E= (2/5)^2 + 5 1/2 (4,5 - 2) + 23/-4
a: \(=\left(15-6-\dfrac{13}{18}\right):\dfrac{298}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{298}-\dfrac{5}{3}=\dfrac{3}{2}-\dfrac{5}{3}=\dfrac{9-10}{6}=\dfrac{-1}{6}\)
b: \(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\dfrac{-22}{15}:\dfrac{11}{2}\)
\(=\dfrac{3}{4}-\dfrac{4}{15}=\dfrac{29}{60}\)
c: \(=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}=\dfrac{-7}{9}+\dfrac{7}{9}+5=5\)
d: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot10\cdot\dfrac{1}{5}\cdot\dfrac{3}{4}=1\)
e: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+\dfrac{-23}{4}=\dfrac{204}{25}\)