Tìm x biết:
a. IxI + Ix+2I = 3
b. [ 12/25 . ( 0,75 + 7/4) - 1 ] x = [ 7/5 - 3/25 . ( 10,6 - 3/5 ) ]
Giúp mk vs!
bài 6:Tìm x, biết:A,1/4x-1/3=-5/9;B,3,5-Ix-1/2I=0,75;C,x-1/x-5=6/7;D,(x-4)mũ 2=25;E,2 mũ x+2 mũ x-4=272;F,(x+1/2)(2/3-2x)=0
Tìm x , bt : [12/25 . ( 0.75 + 7/4 ) - 1 ] x = [1 và 2/5 - 3/25 . ( 10,6 - 3/5 )]
A -17/30 + 11/15 - 7/12
1/2+3/4-(3/4-4/5)
-7/25×11/13+ -7/25×2/13-18/25
(-3,2)+ -15/64+(0,8-2 4/15)÷3 2/3
-5/9+5/9÷(1 2/3- 2 1/12)
-5/7×2/11+ -5/7×9/11+ 1 5/7
(3/8+ -3/4+7/12)÷5/6+1/2
50%×1 1/3×10×7/35×0,75
Mn giúp mk với
\(\dfrac{1}{2}+\dfrac{3}{4}-\left(\dfrac{3}{4}-\dfrac{4}{5}\right)\)
=\(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}\)
=\(\left(\dfrac{1}{2}+\dfrac{4}{5}\right)+\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)
=\(\left(\dfrac{5}{10}+\dfrac{8}{10}\right)+0\)
=\(\dfrac{13}{10}\)
\(-\dfrac{7}{25}.\dfrac{11}{13}+\left(-\dfrac{7}{25}\right).\dfrac{2}{13}-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}.\cdot\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}.1-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}-\dfrac{18}{25}\)
=\(-\dfrac{25}{25}\) = \(-1\)
(-3,2) +\(\dfrac{15}{64}+\left(0.8-2\dfrac{4}{15}\right):3\dfrac{2}{3}\)
=\(-\dfrac{16}{5}+\dfrac{15}{64}+(\dfrac{4}{5}-\dfrac{34}{15}):\dfrac{11}{3}\)
=\(-\dfrac{16}{5}+\dfrac{15}{64}+(-\dfrac{22}{5}):\dfrac{11}{3}\)
=\(-\dfrac{16}{5}+\dfrac{15}{64}+\dfrac{-2}{5}\)
=(\(-\dfrac{16}{5}+\dfrac{-2}{5}\)) +\(\dfrac{15}{64}\)
=\(-\dfrac{18}{5}+\dfrac{15}{64}\)
\(-\dfrac{1152}{320}+\dfrac{75}{320}\)
\(-\dfrac{1077}{320}\)
bài 2:tìm x,biết:
a)x+3/9=7/6x2/3
b)x-2/3=1/8:5/4
giải ra giúp mik vs ạ! mik cảm ơn...mik đag cần gấp
a: \(x+\dfrac{3}{9}=\dfrac{7}{6}\cdot\dfrac{2}{3}\)
=>\(x+\dfrac{1}{3}=\dfrac{14}{18}=\dfrac{7}{9}\)
=>\(x=\dfrac{7}{9}-\dfrac{1}{3}=\dfrac{7}{9}-\dfrac{3}{9}=\dfrac{4}{9}\)
b: \(x-\dfrac{2}{3}=\dfrac{1}{8}:\dfrac{5}{4}\)
=>\(x-\dfrac{2}{3}=\dfrac{1}{8}\cdot\dfrac{4}{5}=\dfrac{1}{10}\)
=>\(x=\dfrac{1}{10}+\dfrac{2}{3}=\dfrac{3+20}{30}=\dfrac{23}{30}\)
9-25=(7-x)-(25+7)
-6x=18
35-3.IxI =5.(2 mũ 3-4)
10+2.IxI=2.(3 mũ 2-1)
A) 14-x-10=(-9)+15
B) IxI=5+7=10
C) IxI=(-12)+(-15)+8
D) Ix+5I=4-(-3)+5
E) IxI<4
Giúp mik với
a, 14 - x - 10 = -9 + 15
=> - x = 6 - 14 + 10
=> - x = 2
=> x = -2
vay_
b, |x| + 5 + 7 = 10
=> |x| = -2
=> x thuoc tap hop rong
vay_
A) 14-x-10 = ( -9) + 15
14-x-10 = 6
14-x=6 + 10
14-x = 16
x = 14 - 16
x = -2
a,\(14-x-10=\left(-9\right)+15\)
\(-x=\left(-9\right)+15-14+10\)
\(x=-2\)
b,\(\left|x\right|=5+7-10\)
\(\left|x\right|=2\)
\(\Rightarrow x=\pm2\)
c,\(\left|x\right|=\left(-12\right)+\left(-15\right)+8\)
\(\Rightarrow\left|x\right|=-19\)
Vì \(\left|x\right|\ge0\Rightarrow x\in\varnothing\)
d,\(\left|x+5\right|=4-\left(-3\right)+5\)
\(\Rightarrow\left|x+5\right|=12\)
\(\Rightarrow\orbr{\begin{cases}x+5=12\\x+5=-12\end{cases}\Rightarrow\orbr{\begin{cases}x=7\\x=-17\end{cases}}}\)
\(\left|x\right|< 4\)
\(\Rightarrow x\in\left\{-4;-3;-2;-1;0;1;2;3\right\}\)
Giúp mình nhé !!!!!!!!!!!!!!
Bài 1 : Tìm x \(\in\) Z biết :
-2.IxI - 5x = 423x + Ix+1I = -(-2)35x + 5x+2 = 650(x2 - 25)(x3 + 64) = 0(-3x + 21)(5.IxI - 15) = 0Bài 2 : Tìm các cặp số nguyên (x;y) biết :
x.(y - 3) = -12(x - 1)(y + 2) = 7xy - 3x -3y = 0xy - 9x + y = 13Bài 3 : Tìm x \(\in\) Z biết :
(x + 3) (x - 2) < 0(x - 1)(x + 5) > 0Ix-3I < 5(x - 1)(2x + 8).Ix-(-3)I = 0Bài 2. Tìm x biết:
a) 31,5 – x = (18,6 – 12,3) : 3
b) 4.(\(\dfrac{-5}{6}\))−x=\(\dfrac{7}{12}\)+\(\dfrac{-1}{3}\)
c) \(\dfrac{1}{2}\)−\(\dfrac{1}{2}\)x=\(\dfrac{2}{3}\)
a.
31,5 – x = (18,6 – 12,3) : 3
31,5 - x = 2,1
x = 31,5 - 2,1
x = 29,4
b.
???
Bài 2. Tìm x biết:
a) 31,5 – x = (18,6 – 12,3) : 3
31,5 – x = 6,3 : 3
31,5 – x = 2,1
x = 31,5 – 2,1
x = 29,4
b) Đề sai.
tính :
a) 3/7 x 1/4 - 3/4 x 3 và 1/4
b ) - 5 / 27 x - 9/ 25 - 7 / 23 x 46 / 14
c ) - 25 / 28 : 5 / 7 + - 0,75 + 20 %
giúp mình nhanh mình cần gấp