tìm x :
x+5=10
x-33=99
x:6=3
các bn ơi giúp mk với mai mk đi hc rùi
47 . ( 23 + 50 ) -23 . ( 47 + 50 )
(- 33 ) . ( - 5 ) - 33 . 4 + 33
25 . 99 + | -25 | . 99 -99 . ( -37 ) + | -13 | . 99
bài tìm x
2 . ( x - 5 ) = -12
x mũ 3 -1 =26
2 . ( x -5 ) - 3 . ( x + 7 ) =14
-7 . ( 5 - x ) - 2 . ( x - 10 ) = 15
8 . ( x - | -7 | ) - 6 . ( x- 2 ) = | -8 | . 6 - 50
12 . ( x - 4 ) + 6 . ( x- 2 ) - 16 . ( x+ 3 ) = 7 . | - 4 |
47. (23 + 50)- 23. ( 47+50 )
= 47. 23+ 47. 50- 23. 47 - 23. 50
=47. 50 - 23. 50
= 50 .( 47 -23)
=50. 24 = 1200
(-33 ). (-5) - 33 . 4 + 33
= 33 ( 5 - 4 + 1)
=33 . 2 = 66
giup minh voi
3 | + | 3 | + … + | 3 | = | |
1 x 4 | 4 x 7 | 262 x 265 |
|
99 -3 x 99 -6 x 99-9 x .... co 33 so hang
1: Thực hiện phép tính
a: -14. ( 13-57)+57.(10-145)
b: -38.(25-4)+(25.(-4+38)
c: -39.(5-99)+99.(10-39)
2: Tính nhanh
a: 32+(-149)+(-311)+(-89)+(-51)
b: 17-452-548
c: 31+53-431
d: 8-(2014-2008)+2014
e: 1268-(78+1268)-(-78)
f: -48795-(489-48795)+4
g: (-33+180-75)-(180+25)
3: Tìm x€ Z, biết:
a: -2x -40= (5-x)- (-15+60)
b: 2.(x-5)- 3.(x +7)=14
c: -7.(5-x) - 2.(x-10)=15
d: 5.(x-6)-2.(x+3)=12
e: 3.(x-6)- (8-x)= 12
f: 4.(x-5)- (x+7)= -19
g: 7.(x-3)-5.(3-x) =11-15
h: x+18= 6-2x
i: 259-51|4x +3|= (-10)^2.3 +10^1
k: x+15= 20- 4x
l: -12+ x = 5x-20
mik nghĩ chắc trả ai rảnh để trả lời hết đâu dù biết làm
a) Thực hiện phép tính
( 1 - 1/2 ) x ( 1 - 1/3 ) x ( 1 - 1/4 ) x ( 1 - 1/5 ) x ... x ( 1 - 1/99 )
b) Tìm X biết
( X +1/2 ) + ( X +1/6 ) + ( X +1/12 ) + ( X +1/20 ) + ... + ( X +1/90 ) = 99/10
tìm số nguyên x
5/x+1+4/x+1=3/-13
-x+2+2x+3+x+1/4+2x+1/6=8/3
3/2x+1+10/4x+2-6/6x+2=12/26
giúp mình mik đang vội]
\(\dfrac{5}{x}+1+\dfrac{4}{x}+1=\dfrac{3}{-13}\\ \Rightarrow\dfrac{9}{x}+2=-\dfrac{3}{13}\\ \Rightarrow\dfrac{9}{x}=-\dfrac{59}{13}\\ \Rightarrow x=-\dfrac{207}{59}\)
a. \(\dfrac{5}{x+1}+\dfrac{4}{x+1}=\dfrac{-3}{13}\)
ĐKXĐ: x ≠ -1
⇔ \(\dfrac{65}{13\left(x+1\right)}+\dfrac{52}{13\left(x+1\right)}=\dfrac{-3\left(x+1\right)}{13\left(x+1\right)}\)
⇔ 65 + 52 = -3(x + 1)
⇔ 117 = -3x - 3
⇔ 117 + 3 = -3x
⇔ 120 = -3x
⇔ x = \(\dfrac{120}{-3}=-40\) (TM)
b. -x + 2 + 2x + 3 + x + \(\dfrac{1}{4}\) + 2x + \(\dfrac{1}{6}\) = \(\dfrac{8}{3}\)
⇔ -x + 2x + x + 2x = \(\dfrac{8}{3}-\dfrac{1}{6}-\dfrac{1}{4}-3-2\)
⇔ 4x = -2,75
⇔ x = \(\dfrac{-2,75}{4}=\dfrac{-11}{16}\)
c. \(\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+2}\) = \(\dfrac{12}{26}\)
⇔ \(\dfrac{3}{2x+1}+\dfrac{10}{2\left(2x+1\right)}-\dfrac{6}{2\left(3x+1\right)}=\dfrac{12}{26}\)
⇔ \(\dfrac{312\left(3x+1\right)}{104\left(2x+1\right)\left(3x+1\right)}\) + \(\dfrac{520\left(3x+1\right)}{104\left(2x+1\right)\left(3x+1\right)}\) - \(\dfrac{312\left(2x+1\right)}{104\left(2x+1\right)\left(3x+1\right)}\)
= \(\dfrac{48\left(2x+1\right)\left(3x+1\right)}{104\left(2x+1\right)\left(3x+1\right)}\)
⇔ 312(3x +1) + 520(3x + 1) - 312(2x + 1) = 48(2x + 1)(3x + 1)
⇔ 936x + 312 + 1560x + 520 - 624x - 312 = (96x + 48)(3x + 1)
⇔ 936x + 312 + 1560x + 520 - 624x - 312 = 288x2 + 96x + 144x + 48
⇔ 936x + 1560x - 624x - 96x - 144x - 288x2 = 48 - 312 - 520 + 312
⇔ 1632x - 288x2 = -472
⇔ -288x2 + 1632x + 472 = 0 (Tự giải tiếp, dùng phương pháp tách hạng tử)
⇔ x = 5,942459684 \(\approx\) 6
c: Ta có: \(\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}=\dfrac{12}{26}\)
\(\Leftrightarrow\dfrac{3}{2x+1}+\dfrac{5}{2x+1}-\dfrac{2}{2x+1}=\dfrac{6}{13}\)
\(\Leftrightarrow2x+1=13\)
hay x=6
Tìm x
1. -12.(x-5) + 7.(3-x) = 15
2. 30.(x+2) - 6.(x-5) - 24.x = 100
3. (x+1) + (x+3) + (x+5) + ... + (x+99) = 0
4. (x-3) + (x-2) + (x-1) + ... +10 +11 =11
Tìm x, biết:
a) x + 99:3 = 55
b) (x - 25): 15=20
c) (3.x - 15).7 = 42
d) (8x - 16)(x-5)=0
e) x.(x+1)=2+4+6+8+10+...+2500
a, \(x\) + 99: 3 = 55
\(x\) + 33 = 55
\(x\) = 55 - 33
\(x\) = 22
b, (\(x\) - 25):15 = 20
\(x\) - 25 = 20 x 15
\(x\) - 25 = 300
\(x\) = 300 + 25
\(x\) = 325
c, (3\(x\) - 15).7 = 42
3\(x\) - 15 = 42:7
3\(x\) - 15 = 6
3\(x\) = 6 + 15
3\(x\) = 21
\(x\) = 21: 3
\(x\) = 7
d, (8\(x\) - 16).(\(x\) -5) = 0
\(\left[{}\begin{matrix}8x-16=0\\x-5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}8x=16\\x=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=16:8\\x=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
Vậy \(x\) \(\in\) {2; 5}
Bài1: Tìm x biết:
a) 12 : 5 = x : 1,5
b) x/5 = 3/20
c) 4/x = 10/9
d) x/15 = 60/x
Bài 2:Cho x/3=y/5=z/6, tìm x,y,z biết
a) x + y -z=8
b)x-y+z=(-4)
c)x-2y+3z= (-33)
d) x^2 - 4y^2 + 2z^2 = (-475)
\(a,\dfrac{12}{5}=\dfrac{x}{1,5}\Rightarrow x=\dfrac{12\cdot1,5}{5}=3,6\\ b,\dfrac{x}{5}=\dfrac{3}{20}\Rightarrow x=\dfrac{5\cdot3}{20}=\dfrac{3}{4}\\ c,\dfrac{4}{x}=\dfrac{10}{9}\Rightarrow x=\dfrac{4\cdot9}{10}=\dfrac{18}{5}\\ d,\Rightarrow\dfrac{x}{15}=\dfrac{60}{x}\Rightarrow x^2=60\cdot15=900\Rightarrow\left[{}\begin{matrix}x=30\\x=-30\end{matrix}\right.\\ 2,\)
a, Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{x+y-z}{3+5-6}=\dfrac{8}{2}=4\\ \Rightarrow\left\{{}\begin{matrix}x=12\\y=20\\z=24\end{matrix}\right.\)
b, Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{x-y+z}{3-5+6}=\dfrac{-4}{4}=-1\\ \Rightarrow\left\{{}\begin{matrix}x=-3\\y=-5\\z=-6\end{matrix}\right.\)
c, Áp dụng t/c dtsbn:
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=\dfrac{2y}{10}=\dfrac{3z}{18}=\dfrac{x-2y+3z}{3-10+18}=\dfrac{-33}{11}=-3\\ \Rightarrow\left\{{}\begin{matrix}x=-9\\y=-15\\z=-18\end{matrix}\right.\)
d, Đặt \(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{6}=k\Rightarrow x=3k;y=5k;z=6k\)
\(x^2-4y^2+2z^2=-475\\ \Rightarrow9k^2-100k^2+72z^2=-475\\ \Rightarrow-19k^2=-475\\ \Rightarrow k^2=25\Rightarrow\left[{}\begin{matrix}k=5\\k=-5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=15;y=25;z=30\\x=-15;y=-25;z=-30\end{matrix}\right.\)
tìm x biết: (x+1)+(x-2)+(x+3)+(x+4)+(x-5)+(x+6)+(x-7)+(x+8)+(x+9)+(x-10)+......+(x+96)+(x-97)+(x+98)+(x+99)+(x-100) = 1
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