Tính = cách thuận tiện nhất
a) 8/13+ 4/9+ 1/3 + 5/13+ 3
b)8/5x 4/7 + 47 x 2/5 - 1
Tính bằng cách thuận tiên nhất:
1):(3/4 x 5/97 + 1/9 x 13/47) x (1/5 - 7/25 x 5/7)
2): 8/17 x 4/15 + 8/17 x 22/15 - 8/15 x 9/17
3): 2021/2 x 1/3 + 4042/4 x 1/5 + 6063/3 x 22/15
4); 4/7 x 2/13 + 8/13 :7/4 + 4/7 : 13/2 + 4/7 x 1/13
5): 2022 x 2021 - 1/ 2021 + 2022 x 2020
6): 18 x 123 + 9 x 4567 x 2 + 3 x 5310 x 6 / (2 + 4 + 6 + 8 + ...+20 + 22) + 48
7): A= 2021 x 2021 x 202020 - 2020 x 2020 x 20212021 / 2020 x 20192019
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
Tính bằng cách thuận tiện nhất
A) 39/16 : 5/8 - 7/16 : 5/8
b) 4/3 X 9/8 - 4/3 X 3/8
`39/16 : 5/8 - 7/16 : 5/8`
`=39/16 xx 8/5- 7/16 xx 8/5`
`=8/5 xx (39/16 - 7/16)`
`= 8/5 xx2`
`= 16/5`
__
` 4/3 xx 9/8 - 4/3 xx 3/8`
`=4/3 -(9/8 - 3/8)`
`= 4/3 xx 3/4`
`=1`
\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)
a)
`39/16:5/8-7/16:5/8`
`=(39/16-7/16):5/8`
`=32/16xx8/5`
`=2xx8/5`
`=16/5`
b)
`4/3xx9/8-4/3xx3/8`
`=4/3xx(9/8-3/8)`
`=4/3xx6/8`
`=4/3xx3/4`
`=1`
tính thuận tiện
8/13+4/9+1/3+5/13+3=
8/5x4/7+4/7x 2/5 -1=
8/13+4/9+1/3+5/13+3=
(8/13+5/13)+(4/9+3/9)+3=
1+7/9+3=4 7/9
8/5x4/7+4/7x2/5=
4/7x(8/5+2/5)
=4/7x2=8/7
a) kết quả bằng 43/9
b) hiện tại chưa tính ra
Tính bằng cách thuận tiện nhất
a)3/5x17/21+17/21x2/5
b)15/8:5/20-7/8:1/4
a) \(\dfrac{3}{5}\times\dfrac{17}{21}+\dfrac{17}{21}\times\dfrac{2}{5}\)
\(=\dfrac{17}{21}\times\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{17}{21}\times1\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}\times\dfrac{20}{5}-\dfrac{7}{8}\times4\)
\(=\dfrac{15}{8}\times4-\dfrac{7}{8}\times4\)
\(=4\times\left(\dfrac{15}{8}-\dfrac{7}{8}\right)\)
\(=4\times1\)
\(=4\)
a) \(\dfrac{3}{5}\) x \(\dfrac{17}{21}+\dfrac{17}{21}\) x \(\dfrac{2}{5}\)
\(=\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\) x \(\dfrac{17}{21}\)
\(=\dfrac{5}{5}\) x \(\dfrac{17}{21}\)
\(=1\) x \(\dfrac{17}{21}\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}:\dfrac{1}{4}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\left(\dfrac{15}{8}-\dfrac{7}{8}\right):\dfrac{1}{4}\)
\(=\dfrac{8}{8}:\dfrac{1}{4}\)
\(=1:\dfrac{1}{4}\)
\(=\dfrac{1}{1}:\dfrac{1}{4}\)
\(=\dfrac{1}{1}\) x \(\dfrac{4}{1}\)
\(=\dfrac{4}{1}\)
\(=4\)
tính bằng cách thuận tiện:
1/5+5/7+1/8+13/8+4/5+4/7
(1/5+4/5)+(5/7+4/7)+(1/8+13/8)
=1+9/7+7/4
=28/28+36/28+49/28
=113/28
\(\frac{1}{5}+\frac{5}{7}+\frac{1}{8}+\frac{13}{8}+\frac{4}{5}+\frac{4}{7}\)
\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{5}{7}+\frac{4}{7}\right)+\left(\frac{1}{8}+\frac{13}{8}\right)\)
\(=1+\frac{9}{7}+\frac{7}{4}\)
\(=\frac{28}{28}+\frac{36}{28}+\frac{49}{28}\)
\(=\frac{113}{28}\)
Ai k mik mik k lại
= (1/5+4/5)+(5/7+4/7)+(1/8+13/8)
= 1 + 9/7 + 7/4
= 28/28 + 36/28 + 49/28
= 113/28
Bài 3. Một hình bình hành có chiều cao là 5/7 m. Độ dài đáy gấp hai lần chiều cao, cạnh bên là 6/7m. Tính chu vi của hình bình hành.
Bài 4. Tính bằng cách thuận tiện nhất
a) 7/4 x 11/21 + 11/21 x 5/4 =
b) 23/14 x 6/13 - 9/14 x 6/13 =
Bài 4:
a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)
b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)
Bài 3. Một hình bình hành có chiều cao là 5/7 m. Độ dài đáy gấp hai lần chiều cao, cạnh bên là 6/7m. Tính chu vi của hình bình hành.
Bài 4. Tính bằng cách thuận tiện nhất
a) 7/4 x 11/21 + 11/21 x 5/4 =
b) 23/14 x 6/13 - 9/14 x 6/13 =
Bài 4:
a: =11/21(7/4+5/4)=11/21x3=11/7
b: =6/13(23/14-9/14)=6/13
Câu 8 : hình thoi ABCD có đọ dài đường chéo AC là 4 3/4 dm; độ dài đường chéo BD ngắn hơn AC là 7/12 dm. Tính diện tích hình thoi đó
Câu 9 : tính bằng cách thuận tiện nhất
a. 2/9 + 1/5 + 7/9 + 4/5 = .............................................................................................
b. 1/12 + 3/16 + 5/12 =...................................................................................................
Câu 1:
Câu 2:
b) 1/12 + 3/16 + 5/12 + 5/16
=(1/12 + 5/12) + (3/16 + 5/16)
=1/2 + 1/2
=2/2
=1
a) 1/2 + 3/16 + 5/12 + 5/16
=5/12 + (1/2 + 3/16 + 5/16)
= 5/12 + 1
= 15/12
(Đúng tick, sai bảo)
Bổ sung câu a:>
a) 2/9 + 1/5 + 7/9 + 4/5
= (2/9 + 7/9) + (1/5 + 4/5)
= 9/9 + 5/5
= 1 + 1
=2
a (2/9+7/9)+(1/5 +1/5)=9/9+5/5=1+1=2
b( 1/12+5/12) +3/16= 1/2+3/16=8/16+3/16=11/16
Đúng tisk nhé