a) 72.5–(2x+1)=630:972.5–(2x+1)=630:9

⇒245–2x–1=70⇒245–2x–1=70

⇒−2x=−22+70⇒−2x=−22+70

⇒−2x=−174⇒−2x=−174

⇒x=87⇒x=87

b)(10−4x)+120:23=17

10−4x+15=17

10−4x=17−15

10−4x=2

4x=10−2

4x=8

x=8:4

x=2

 

a) 72,5 - (2x + 1) = 630 : 9

⇒ 72,5 - (2x + 1) = 70

⇒ 2x + 1 = 2,5

⇒ 2x = 1,5

⇒ x = 0,75

b) (10 - 4x) + 120 : 2³ = 17

⇒ (10 - 4x) + 120 : 8 = 17

⇒ (10 - 4x) + 15 = 17

⇒ 10 - 4x = 2

⇒ 4x = 8

⇒ x = 2

Vậy x = 2

c) [124 - (20 - 4x)] : 30 + 7 = 11

⇒ [124 - (20 - 4x)] : 30 = 4

⇒ 124 - (20 - 4x) = 120

⇒ 20 - 4x = 4

⇒ 4x = 16

⇒ x = 4

Vậy x = 4

Mình ko ghi lại đề , bạn ghi ra xong rồi suy ra như mình nha .

1) \(=>A=\left(6x^2+3x-10x-5\right)-\left(6x^2+14x-9x-21\right)\)

\(=>A=-12x+16\)

2) \(=>B=8x^3+27-8x^3+2=29\)

3)\(=>C=[\left(x-1\right)-\left(x+1\right)]^3=\left(-2\right)^3=-8\)

4)\(=>D=[\left(2x+5\right)-\left(2x\right)]^3=5^3=125\)

5)\(=>E=\left(3x+1\right)^2-\left(3x+5\right)^2+12x+2\left(6x+3\right)\)

\(=>E=\left(3x+1+3x+5\right)\left(3x+1-3x-5\right)+12x+12x+6\)

\(=>E=\left(6x+6\right)\left(-4\right)+24x+6=-24x-24+24x+6=-18\)

6)\(=>F=\left(2x^2+3x-10x-15\right)-\left(2x^2-6x\right)+x+7=-8\)

k cho mik nha , 

a,<=> 145-2x-1=70

<=> 2x=74

<=> x=37

b, <=> 10-4x+15=17

<=> 4x=8

<=> x=2

\(7^2\cdot5-\left(2x+1\right)=630\div9\)

\(49\cdot5-\left(2x+1\right)=70\)

     \(245-\left(2x+1\right)=70\)

                     \(2x+1=245-70\)

                      \(2x+1=175\)

                        \(2x=175-1\)

                         \(2x=174\)

                            \(x=174\div2\)

                             \(x=87\)

\(\left(10-4x\right)+120\div2^3=17\)

  \(\left(10-4x\right)+120\div8=17\)

\(\left(10-4x\right)+15=17\)

    \(10-4x=17-15\)

      \(10-4x=2\)

                 \(4x=10-2\)

                  \(4x=8\)

                      \(x=8\div4\)

                      \(x=2\)

\(a\)\(.\)\(7^2.5-\left(2x+1\right)=630:9\)

\(49.5-\left(2x+1\right)=70\)

\(245-\left(2x+1\right)=70\)

                 \(2x+1=245-70\)

                  \(2x+1=175\)

                   \(2x=175-1\)

                   \(2x=174\)

                   \(x=174:2\)

                   \(x=87\)

Vậy \(x=87\)

\(b.\)\(\left(10-4x\right)+120:2^3=17\)

        \(\left(10-4x\right)+120:8=17\)

         \(\left(10-4x\right)+15=17\)

          \(10-4x=17-15\)

           \(10-4x=2\)

           \(4x=10-2\)

            \(4x=8\)

            \(x=8:4\)

            \(x=2\)

Vậy \(x=2\)

\(c.\)\(\left[124-\left(20-4x\right)\right]:30+7=11\)

\(\left[124-\left(20-4x\right)\right]:30=11-7\)

\(\left[124-\left(20-4x\right)\right]:30=4\)

\(\left[124-\left(20-4x\right)\right]=4.30\)

\(\left[124-\left(20-4x\right)\right]=120\)

\(124-20+4x=120\)

\(104+4x=120\)

\(4x=120-104\)

\(4x=16\)

\(x=16:4\)

\(x=4\)

Vậy \(x=4\)

\(d.\)\(\left|2x+5\right|=1\)

\(\Rightarrow2x+5\in\left\{-1;1\right\}\)

\(\Rightarrow2x\in\left\{-6;-4\right\}\)

\(\Rightarrow x\in\left\{-3;-2\right\}\)

Vậy \(x\in\left\{-3;-2\right\}\)

học tốt

a) \(7^2\cdot5-\left(2x+1\right)=630:9\)

\(\Leftrightarrow49\cdot5-2x-1=70\)

\(\Leftrightarrow244-2x=70\)

\(\Leftrightarrow2x=244-70\)

\(\Leftrightarrow2x=174\)

\(\Leftrightarrow x=87\)

Vậy x=87.

b) \(\left(10-4x\right)+120:2^3=17\)

\(\Leftrightarrow10-4x+120:8=17\)

\(\Leftrightarrow10-4x+15=17\)

\(\Leftrightarrow25-4x=17\)

\(\Leftrightarrow4x=25-17=8\)

\(\Leftrightarrow x=2\)

Vậy x=2

c)\([124-\left(20-4x\right)]:30+7=11\)

\(\Leftrightarrow\left(124-20+4x\right):30=4\)

\(\Leftrightarrow104+4x=120\)

\(\Leftrightarrow4x=120-104=16\)

\(\Leftrightarrow x=4\)

Vậy x=4

d) \(|2x-5|=1\)

\(\Leftrightarrow\orbr{\begin{cases}2x-5=1\\2x-5=-1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=6\\2x=4\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=2\end{cases}}\)

Vậy \(x\in\text{ }\left\{3;2\right\}\)

Sorry mình ghi nhầm đề bài phần d

Bài 1: 

b: \(=2\left(4x^2+20x+25\right)+3\left(16x^2-1\right)\)

\(=8x^2+40x+50+48x^2-3\)

\(=56x^2+40x+47\)

Bài 2: 

b: \(\Leftrightarrow3x-3+9x-18=2x-6+4x-4\)

=>12x-21=6x-10

=>6x=11

hay x=11/6

a)120-3(x+4)=23

=>3(x+4)=120-23

=>3(x+4)=97

=>x+4=97:3

=>x+4=\(\frac{97}{3}\)

=>x=\(\frac{97}{3}\)-4

=>x=\(\frac{85}{3}\)

Vậy x=\(\frac{85}{3}\)

b)[(4x+28).3+55]:5=35

=>(4x+28).3+55=35.5

=>(4x+28).3+55=175

=>(4x+28).3=175-55

=>(4x+28).3=120

=>4x+28=120:3

=>4x+28=40

=>4x=40-28

=>4x=12

=>x=12:4

=>x=3

Vậyx= 3

c)\((12x-4^3).8^3=4.8^4\)

=>\(12x-64=4.8^4:8^3\)

=>12x-64=4.8

=>12x-64=32

=>12x=96

=>x=96:12

=>x=8

Vậy x=8

d)720:[41-(2x-5)]=2³.5

=>720:[41-2x-5)]=40

=>41-(2x-5)=720:40

=>41-(2x-5)=18

=>2x-5=41-18

=>2x-5=23

=>2x=23+5

=>2x=28

=>x=28:;2

=>x=14

Vậy x=14

a, 120 - 3 [ x+4]=23

     3 [x+4]= 120-23 = 97

      3x = 97-4

      3x= 93

        x= 93:3

        x=31

em bt làm mỗi bài này thui mà ko bt đúng ko

a) 120 - 3(x + 4) = 23

=> 3(x + 4) = 120 - 23 = 97

=> x + 4 = 97 : 3

=> x + 4 = 97/3

=> x = 97/3 - 4 = 85/3

b) [(4x + 28) . 3 + 55] : 5 = 35

=> [(4x + 28) . 3 + 55] = 175

=> (4x + 28).3 + 55 = 175

=> (4x + 28).3 = 120

=> 4x + 28 = 40

=> 4x = 12

=> x = 3

c) (12x - 4³).8³ = 4.8⁴

=> (12x - 4³) = \(\frac{4\cdot8^4}{8^3}=4\cdot8=32\)

=> 12x - 64 = 32

=> 12x = 96

=> x = 96 : 12 = 8

d) Tương tự

\(x=5\)

\(x=3\)

học tốt

a, 2x+3x-3=27-x

<=>5x-3=27-x

chuyển vế, ta có:

5x+x=27+3

<=>6x=30

<=> x=5

b, 4+8x-5x+10=23

14+3x=23

=> 3x=9

=> x=3

\(a,\left(2x+3\cdot\left(x-1\right)\right)-\left(27-x\right)=0.\)

\(6x-30=6\cdot\left(x-5\right)\)

\(6\cdot\left(x-5\right)=0\)

\(x-5=0\)

\(x=5\)

\(b,\left(\left(4\cdot\left(2x+1\right)\right)-5\cdot\left(x-2\right)\right)-23=0\)

\(3x-9=3\cdot\left(x-3\right)\)

\(3\cdot\left(x-3\right)=0\)

\(x-3=0\)

\(x=3\)