\(B=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+\frac{1}{18\cdot19\cdot20}\)

\(B=\frac{1}{2}\left(\frac{2}{1\cdot2\cdot3}+\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+\frac{2}{18\cdot19\cdot20}\right)\)

\(B=\frac{1}{2}\left(\frac{1}{1\cdot2}-\frac{1}{2\cdot3}+\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{18\cdot19}-\frac{1}{19\cdot20}\right)\)

\(B=\frac{1}{2}\left(\frac{1}{1\cdot2}-\frac{1}{19\cdot20}\right)\)

\(B=\frac{1}{2}\cdot\frac{189}{380}=\frac{189}{760}\)

\(C=\frac{52}{1\cdot6}+\frac{52}{6\cdot11}+\frac{52}{11\cdot16}+...+\frac{52}{31\cdot36}\)

\(C=\frac{52}{5}\left(\frac{5}{1\cdot6}+\frac{5}{6\cdot11}+\frac{5}{11\cdot16}+...+\frac{6}{31\cdot36}\right)\)

\(C=\frac{52}{5}\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{31}-\frac{1}{36}\right)\)

\(C=\frac{52}{5}\cdot\left(1-\frac{1}{36}\right)\)

\(C=\frac{91}{9}\)

1-3+5-7+...+21-23
=(1-3)+(5-7)+...+(21-23)
Tổng số cặp là:
[(23-1):2+1]:2=6
Nháp: [(23-1):2+1]:2=(22:2+1):2=12:2=6
=1-3=-2=-2*6=-12
Đây nha bạn.
Chúc bạn học tốt!

\(1-3+5-7+...+21-23\)

\(=\left(1+5+9+13+17+21\right)-\left(3+7+11+15+19+23\right)\)

\(=\left[\left(21-1\right):2+1\right].\left(21+1\right):2-\left[\left(23-3\right):2+1\right].\left(23+3\right):2\)

\(=11.11-11.13\)

\(=121-143\)

\(=-22\)

`#3107.101107`

a,

\([(6.x - 39) \div3] .28 =5628\)

`\Rightarrow (6x - 39) \div 3 = 5628 \div 28`

`\Rightarrow (6x - 39) \div 3 = 201`

`\Rightarrow 6x - 39 = 201 . 3`

`\Rightarrow 6x - 39 = 603`

`\Rightarrow 6x = 42`

`\Rightarrow x = 42 \div 6`

`\Rightarrow x = 7`

Vậy, `x = 7`

b,

`5(7x - 45) = 2^3 . 5^2 - 3^2 . 20`

`\Rightarrow 5(7x - 45) = 8.5.5 - 9.4.5`

`\Rightarrow 5(7x - 45) = 5.(8.5 - 9.4)`

`\Rightarrow 5(7x - 45) = 5.(40 - 36)`

`\Rightarrow 7x - 45 = 5.(40 - 36) \div 5`

`\Rightarrow 7x - 45 = 4`

`\Rightarrow 7x = 49`

`\Rightarrow x = 7`

Vậy, `x = 7.`

b) 23.79 + 52.21 + 77.79 + 21.48

= 79(23+77) + 21(52+48)

= 79 .100 + 21 .100

= (79+21) .100 = 100.100 = 10000

=(23+77)*79+(48+52)*21                                                                                                                                                                                    =7900+2100 =10000

23*79+52*21+77*79+21*48

=(23+77)*79+(52+48)*21

=100*79+100*21

=7900+2100=10000

\(\frac{2}{3\times5}+\frac{2}{5\times7}+\frac{2}{7\times9}+...+\frac{2}{21\times23}\) 

\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{21}-\frac{1}{23}\)

\(=\frac{1}{3}-\frac{1}{23}\)

\(=\frac{20}{69}\)

2 / 3 x 5 + 2 / 5 x 7 + 2 / 7 x 9 + ... + 2 / 21 x 23

= 1/3 - 1/5 + 1/5 - 1/7 + 1/7 - 1/9 + ... + 1/21 - 1/23

= 1/3 - 1/13

= 20/69

     \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{21.23}\)

\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{21}-\frac{1}{23}\)

\(=\frac{1}{3}-\frac{1}{23}\)

\(=\frac{20}{69}\)

Dấu chấm ( . ) ở cấp 2 là dấu nhân ( x ) bn nhé

C>D thì phải

hoặc C<D

chọn 1 trong2

1: \(=-24\left(45-5\right)=-24\cdot40=-960\)

2: \(=-134\left(1-51+48\right)=-134\cdot\left(-2\right)=268\)

3: \(=124\left(1-52+47\right)=124\cdot\left(-3\right)=-372\)

2b 3c