tim x biet 3^2x=81
tim x biet 3^2x=81
Ta có 81 = \(^{3^4}\)
=> 3^2x = 81 = \(^{3^4}\)
=> 2x = 4
=> x = 4 : 2
=> x = 2
tim x biet:32x=81
32x=81
32x=34
32x=32.2
=>x=2
k mik nha
\(3^{2x}=81\Rightarrow2^{2x}=3^4\)
\(\Rightarrow2x=4\Leftrightarrow x=4:2\)
\(x=2\)
Vậy \(x=2\)
\(3^{2x}=81\)
\(\Rightarrow\)\(3^{2x}=3^4\)
\(\Rightarrow\)\(2x=4\)
\(\Rightarrow\)\(x=2\)
tim x,biet:
5x=125 32x=81 52x-3 -2.52=52.3
5x=125
Mà: 53=125
=>x=3
32x=81
Mà: 34=81
=>32x=34
=>2x=4
=>x=4:2
=>x=2
52x-3-2.52=52.3
=>52x-3-50=75
=>52x-3=75+50
=>52x-3=125
Mà: 53=125
=> 52x-3=53
=>2x-3=3
=>2x=3+3
=>2x=6
=>x=6:2
=>x=3
5x=125
Mà: 53=125
=>x=3
32x=81
Mà: 34=81
=>32x=34
=>2x=4
=>x=4:2
=>x=2
52x-3-2.52=52.3
=>52x-3-50=75
=>52x-3=75+50
=>52x-3=125
Mà: 53=125
=> 52x-3=53
=>2x-3=3
=>2x=3+3
=>2x=6
=>x=6:2
=>x=3
5x=125
Mà: 53=125
=>x=3
32x=81
Mà: 34=81
=>32x=34
=>2x=4
=>x=4:2
=>x=2
52x-3-2.52=52.3
=>52x-3-50=75
=>52x-3=75+50
=>52x-3=125
Mà: 53=125
=> 52x-3=53
=>2x-3=3
=>2x=3+3
=>2x=6
=>x=6:2
=>x=3
1)tim x biet rang:
a)3^x-1=1/243
b)2^x+2^x+3=144
c)81^-2x.27x=9^5
2)tim tiep so ghang thu 5 cua day so sau:-1/a^2;2/a^3;-6/a^4;24/a^5;...
3)tim so tu nhien x biet :
a)4^x+4^x+3=4160
b)2^x-1+5.2^x-2=7/32
Tim x biet 3^x+2=81
Tim x biet 3^x = 81
\(3^x=81\)
\(3^x=3^4\)
\(\Rightarrow x=4\)
Vậy x=4
cac bn oi giup mk voi
b1 tim x biet
a,3x+2+3x+1+3x=117
b,32x+1=1/81
c,(x+2)4=16
a)
\(\Rightarrow3^x\left(3^2+3+1\right)=117\)
\(\Rightarrow3^x.13=117\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
=>x=2
b)
\(3^{2x+1}=3^{-4}\)
=> 2x+1= - 4
=>\(x=-\frac{5}{2}\)
c)
\(\left(x+2\right)^4=16\)
\(\Rightarrow\left[\begin{array}{nghiempt}\left(x+2\right)^4=2^4\\\left(x+2\right)^4=\left(-2\right)^4\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+2=2\\x+2=-2\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\-4\end{array}\right.\)
Tim x biet
A, 5/9 + x/-1 = -1/3
B, 1/5 + 2/20 + 121/165 <x< 1/2 + 156/72 + 1/3 ( x thuoc N)
C, x + 5/3 = 1/81
D, x-1/3 + 3x-5/2 + 2x/9 + -5x+3/9 = 210/420
a: -x+5/9=-1/3
nên x=5/9+1/3=5/9+3/9=8/9
b: \(\Leftrightarrow\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{11}{15}< x< \dfrac{1}{2}+\dfrac{13}{12}+\dfrac{1}{3}\)
=>31/30<x<23/12
mà x là số nguyên
nên \(x\in\varnothing\)
c: x+5/3=1/81
nên x=1/81-135/81=-134/81
tim x biet (x+2)^2=81
\(\left(x+2\right)^2=81\)
\(\left(x+2\right)^2=9^2\)
\(\Rightarrow x+2=9\)
\(\Rightarrow x=7\)
\(\left(x+2\right)^2-9^2=0\)
\(\left(x+2+9\right)\left(x+2-9\right)=0\)
\(x=-11\)
\(x=7\)
ta thấy 9^2=81=>X+2=9
X =9-2
X =7
k cho mik nha bạn