Question

cac bn oi giup mk voi

b1 tim x biet

a,3^x+2+3^x+1+3^x=117

b,3^2x+1=1/81

c,(x+2)⁴=16

Answer 1

a)

\(\Rightarrow3^x\left(3^2+3+1\right)=117\)

\(\Rightarrow3^x.13=117\)

\(\Rightarrow3^x=9\)

\(\Rightarrow3^x=3^2\)

=>x=2

b)

\(3^{2x+1}=3^{-4}\)

=> 2x+1= - 4

=>\(x=-\frac{5}{2}\)

c)

\(\left(x+2\right)^4=16\)

\(\Rightarrow\left[\begin{array}{nghiempt}\left(x+2\right)^4=2^4\\\left(x+2\right)^4=\left(-2\right)^4\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x+2=2\\x+2=-2\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\-4\end{array}\right.\)