a: \(x\in\varnothing\)

b: \(\Leftrightarrow\left[{}\begin{matrix}4x-1=15\\4x-1=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{7}{2}\end{matrix}\right.\)

(4x-1)^2 = 25.9 = 5.5.3.3

=> (4x-1)^2 = 15.15 = 15^2

=> 4x - 1 = 15 hoặc 4x - 1 = -15

=> 4x = 16 hoặc 4x = -14

=> x = 4 hoặc x = -7/2

\(\left(4x-1\right)^2=25.9=225\\ \Leftrightarrow\left(4x-1\right)^2=15^2=\left(-15\right)^2\\ \Leftrightarrow\left[{}\begin{matrix}4x-1=15\\4x-1=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=16\\4x=-14\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{16}{4}=4\\x=-\dfrac{14}{4}=-\dfrac{7}{2}\end{matrix}\right.\)

\(\left(4x-1\right)^2=25\cdot9\)

\(\Rightarrow\left(4x-1\right)^2=5^2\cdot3^2\)

\(\Rightarrow\left(4x-1\right)^2=\left(5\cdot3\right)^2\)

\(\Rightarrow\left(4x-1\right)^2=15^2\)

TH1: \(4x-1=15\)

\(\Rightarrow4x=15+1\)

\(\Rightarrow4x=16\)

\(\Rightarrow x=\dfrac{16}{4}\)

\(\Rightarrow x=4\)

TH2: \(4x-1=-15\)

\(\Rightarrow4x=-15+1\)

\(\Rightarrow4x=-14\)

\(\Rightarrow x=-\dfrac{14}{4}\)

\(\Rightarrow x=-\dfrac{7}{2}\)

(3^2+2^3).x+4^2.2.x=98

(9+8).x+16.2.x=98

17.x+16.2.x=98

17.x+32.x=98

(17+32).x=98

49.x=98

x=98:49

x=2

a: Ta có: \(7x+25=144\)

\(\Leftrightarrow7x=119\)

hay x=17

b: Ta có: \(33-12x=9\)

\(\Leftrightarrow12x=24\)

hay x=2

c: Ta có: \(128-3\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=105\)

\(\Leftrightarrow x+4=35\)

hay x=31

d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)

\(\Leftrightarrow5\left(726-3x\right)=2175\)

\(\Leftrightarrow726-3x=435\)

\(\Leftrightarrow3x=291\)

hay x=97

e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x+5\right)=18\)

\(\Leftrightarrow2x+5=23\)

\(\Leftrightarrow2x=18\)

hay x=9

Bn cần bài nào vậy

f: Ta có: \(10-4x+120:8=16+1\)

\(\Leftrightarrow4x=17-25=-8\)

hay x=-2

g: Ta có: \(x+9x+7x+5x=2244\)

\(\Leftrightarrow22x=2244\)

hay x=102

h: Ta có: \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)

\(\Leftrightarrow100x+5050=5750\)

\(\Leftrightarrow100x=700\)

hay x=7

a) 17 + x = -5 + 2x

=> x - 2x = -5 - 17

=> -x = -22

=> x = 22

b) 15 - 3x = -22 - 4x 

=> -3x + 4x = -22 - 15

=> x = -37

c) 47 - (4x + 5) = -(3x - 2)

=> 47 - 4x - 5 = -3x + 2

=> -4x + 3x = 2 - 47 + 5

=> -x = -40

=> x = 40

d) -58 + (3 - 7x) = 15 - 8x

=> -58 + 3 - 7x = 15 - 8x

=> -7x + 8x =15 + 58 - 3

=> x = 70

a, b dễ :>>

a) \(2^x=16\)

\(2^x=2^4\)

\(x=4\)

b) \(2^x-15=17\)

\(2^x=17+15\)

\(2^x=32\)

\(2^x=2^5\)

\(x=5\)

Trả lời :

a, 2^x = 16

=> 2^x = 2⁴

=> x = 4

b, 2^x - 15 = 17

=> 2^x = 32

=> 2^x = 2⁵

=> x = 5

c, (4x - 1)² = 25 . 9

=> (4x - 1)² = 225

=> (4x - 1)² = \(\pm\)15²

=> 4x - 1 = \(\pm\)15

\(\Rightarrow\orbr{\begin{cases}4x-1=15\\4x-1=-15\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=\frac{-7}{2}\end{cases}}\)

c) \(\left(4x-1\right)^2=25\cdot9\)

\(\left(4x-1\right)^2=225\)

\(\Rightarrow\orbr{\begin{cases}\left(4x-1\right)^2=15^2\\\left(4x-1\right)^2=\left(-15\right)^2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}4x-1=15\\4x-1=\left(-15\right)\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=\frac{-7}{2}\end{cases}}\)

Vậy: ...