A = 1/31 . [31/5 . (9 - 1/2 ) - 17/2 . ( 4 - 1/5 ) ] - 1/2 + 1/6 + 1/12 + .... + 1/930
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Tính giá trị biểu thức:
A=\(\frac{1}{31}\left[\frac{31}{5}\left(9-\frac{1}{2}\right)-\frac{17}{2}\left(4+\frac{1}{5}\right)+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{930}\right]\)
Tính
A= \(\frac{1}{31}\left[\frac{5}{31}\left(9-\frac{1}{2}\right)-\frac{17}{2}\left(4+\frac{1}{5}\right)\right]+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{930}\)
giải nhanh hô mình với, mình cần rất rất rất gấp
A= \(\frac{1}{31}.\left[\frac{5}{31}\left(9-\frac{1}{2}\right)-\frac{17}{2}\left(4+\frac{1}{5}\right)\right]+\frac{1}{2}+\frac{1}{6}+...+\frac{1}{930}\)
= \(\frac{1}{31}.\left(\frac{5}{31}.\frac{17}{2}-\frac{17}{2}.\frac{21}{5}\right)+\frac{1}{2}+\frac{1}{6}+...+\frac{1}{930}\)
=\(\frac{1}{31}.\left[\frac{17}{2}.\left(\frac{5}{31}-\frac{21}{5}\right)\right]+\frac{1}{2}+\frac{1}{6}+...+\frac{1}{930}\)
=\(\frac{1}{31}.\left[\frac{17}{2}.\left(\frac{-626}{155}\right)\right]+\frac{1}{2}+\frac{1}{6}+...+\frac{1}{930}\)
=\(\frac{1}{31}.\left(\frac{-5321}{155}\right)+\frac{1}{2}+\frac{1}{6}+...+\frac{1}{930}\)
=\(\frac{-5321}{4805}+\frac{1}{2}+\frac{1}{6}+...+\frac{1}{930}\)
=\(\frac{-5321}{4805}+\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{30.31}\)
=\(\frac{-5321}{4805}+\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{30}-\frac{1}{31}\)
=\(\frac{-5321}{4805}+\frac{1}{1}-\frac{1}{31}\)
=\(\frac{-5321}{4805}+\frac{30}{31}\)
=\(\frac{-671}{4805}\)
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tìm x thuộc Z
a) 1/3 + (-2)/5 + 1/6 + (-1)/5 < x < ( -3)/4 + 2/7 + (-1)/4 + 3/5 + 5/7
b) 5/17 + (-4)/9 + (-20)/31 + 12/17 + (-11)/31 < x/9 < (-3)/7 + 7/15 + 4/(-7) + 8/15 +2/3
Dùng tính chất để tính
a) 17/5 . -31/125 . 1/2 . 10/17 . -1/23
b) (11/4 . -5/9 - 4/9 . 11/4) . 8/33
c) (17/28 + 18/29 - 19/30 - 20/31) . (-5/12 + 1/4 + 1/6)
d) -1/4 . 15^2/11 + 68/4 . -1/11
e) -9/25 . 53/3 - (-3/5)^2 .22/3
Xem thêm câu trả lời
Thực hiện phép tính:
4, 2/7+ 1/9+ 3/7+ 5/9+ -5/6
5, -5/7+ 3/4+ -1/5+ -2/7+ 1/4
6, -3/31+ -6/17+ 1/25+ -28/31+ -1/17+ -1/5
4: \(=\dfrac{2+3}{7}+\dfrac{1+6}{9}-\dfrac{5}{6}=\dfrac{5}{7}+\dfrac{7}{9}-\dfrac{5}{6}=\dfrac{83}{126}\)
5: \(=\dfrac{-5-2}{7}+\dfrac{3+1}{4}-\dfrac{1}{5}=-\dfrac{1}{5}\)
6: \(=\dfrac{-3-28}{31}+\dfrac{-6-1}{17}+\dfrac{1-5}{25}=-1-\dfrac{7}{17}-\dfrac{4}{25}=-\dfrac{668}{425}\)
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Thực hiện phép tính:
4, 2/7+ 1/9+ 3/7+ 5/9+ -5/6
5, -5/7+ 3/4+ -1/5+ -2/7+ 1/4
6, -3/31+ -6/17+ 1/25+ -28/31+ -1/17+ -1/5
4. \(\dfrac{2}{7}+\dfrac{1}{9}+\dfrac{3}{7}+\dfrac{5}{9}+\dfrac{-5}{6}\)
\(=\left(\dfrac{2}{7}+\dfrac{3}{7}\right)+\left(\dfrac{1}{9}+\dfrac{5}{9}\right)+\dfrac{-5}{6}\)
\(=\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{-5}{6}\)
\(=\dfrac{30+28+\left(-35\right)}{42}=\dfrac{23}{42}\)
5. \(\dfrac{-5}{7}+\dfrac{3}{4}+\dfrac{-1}{5}+\dfrac{-2}{7}+\dfrac{1}{4}\)
\(=\left(\dfrac{-5}{7}+\dfrac{-2}{7}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\dfrac{-1}{5}\)
\(=\dfrac{-7}{7}+\dfrac{4}{4}+\dfrac{-1}{5}\)
\(=-1+1+\dfrac{-1}{5}\)
\(=-\dfrac{1}{5}\)
6. \(\dfrac{-3}{31}+\dfrac{-6}{17}+\dfrac{1}{25}+\dfrac{-28}{31}+\dfrac{-1}{17}+\dfrac{-1}{5}\)
\(=\left(\dfrac{-3}{31}+\dfrac{-28}{31}\right)+\left(\dfrac{-6}{17}+\dfrac{-1}{17}\right)+\dfrac{1}{25}+\dfrac{-1}{5}\)
\(=\dfrac{-31}{31}+\dfrac{-7}{17}+\dfrac{1}{25}+\dfrac{-1}{5}\)
\(=-1+\dfrac{-7}{17}+\dfrac{1}{25}+\dfrac{-1}{5}\)
\(=\dfrac{-425+\left(-175\right)+17+\left(-85\right)}{425}=\dfrac{-668}{425}\)
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Thực hiện phép tính:
4, 2/7+ 1/9+ 3/7+ 5/9+ -5/6
5, -5/7+ 3/4+ -1/5+ -2/7+ 1/4
6, -3/31+ -6/17+ 1/25+ -28/31+ -1/17+ -1/5
bài 1 Tính tổng : S = 1/3 + -1/4 + 1/5 + -1/6 + 1/7 + 1/6 + 1/-5 + 1/4 + 1/-3
bài 2 cho S = 25/31 + -3/17 + 6/31 + 5/9 + -14/17 + -1/12
Giúp mik với mn
S=1/3+ - 1/4+ 1/5 + - 1/6 + 1/7 +1/6 + 1/-5 +1/4+1/-3
=(1/3+1/-3)+(-1/4+1/4)+(1/5+1/-5)+(-1/6+1/6)+1/7
=0+1/7
=1/7
25/31+ - 3/17+6/31+5/9+ - 14/17+ - 1/12
=(25/31+6/31)+(-3/17+-14/17)+(5/9+-1/12)
=1+(-1)+.....[tự tính 5/9+-1/12]
=0+........[kết quả trên]
=.........
Câu 2 tự tính chỗ..... nha
Công sức của tui đó
A frac{1}{31}. [frac{31}{5}. (9 - frac{1}{2}) - frac{17}{2}( 4 - frac{1}{5}) ] - frac{1}{2}+ frac{1}{6}+ frac{1}{12}+ ... + frac{1}{930}Mn giúp mình với mình đag cần gấp.
Đọc tiếp
A = \(\frac{1}{31}\). [\(\frac{31}{5}\). (9 - \(\frac{1}{2}\)) - \(\frac{17}{2}\)( 4 - \(\frac{1}{5}\)) ] - \(\frac{1}{2}\)+ \(\frac{1}{6}\)+ \(\frac{1}{12}\)+ ... + \(\frac{1}{930}\)
Mn giúp mình với mình đag cần gấp.