a) \(xy+x+2y=5\\ \Rightarrow y\left(x+2\right)+x+2=5+2\\ \Rightarrow\left(x+2\right)\left(y+1\right)=7\)

Ta xét bảng:

Vậy \(\left(x;y\right)\in\left\{\left(-1;6\right);\left(5;0\right);\left(-3;-8\right);\left(-9;-2\right)\right\}\)

b) \(xy-3x-y=0\\ \Rightarrow x\left(y-3\right)-y+3=3\\ \Rightarrow\left(y-3\right)\left(x-1\right)=3\)

Ta xét bảng:

Vậy \(\left(x;y\right)\in\left\{\left(2;6\right);\left(4;4\right);\left(0;0\right);\left(-2;2\right)\right\}\)

c) \(xy+2x+2y=-16\\ \Rightarrow x\left(y+2\right)+2y+4=-12\\ \Rightarrow\left(y+2\right)\left(x+2\right)=-12\)

Ta xét bảng:

Vậy \(\left(x;y\right)\in\left\{\left(-1;-14\right);\left(0;-8\right);\left(1;-6\right);\left(2;-5\right);\left(4;-4\right);\left(10;-3\right);\left(-3;10\right);\left(-4;4\right);\left(-5;2\right);\left(-6;1\right);\left(-8;0\right);\left(-14;-1\right)\right\}\)

100 - 100 + 666 - 555 + 111 - 111 + 111 - 222

= 0 + 666 - 555 + 111 - 111 + 111 - 222

= 666 - 555 + 111 - 111 + 111 - 222

= 111 + 111 - 111 + 111 - 222

= 222 - 111 + 111 - 222

= 111 + 111 - 222

= 222 - 222

= 0

Chuc ban hoc tot

Bài toán : Tìm giá trị số tự nhiên lớn nhất của Y biết 

(4,36*2,5-y)chia(4,36*2,5-y)=1

12/16 = - x/4 = 21/y = z/-80

+ 12/16 = - x/4

=> Vì 12.4 = 16.(-x)

           48  = - 16x

            x   = 48 : (-16)

            x = -3

+ -3/4 = 21/ y

=> Vì (-3) . y = 4.21

           - 3y    = 84

               y    =  84 : ( -3)

               y    =  -28

+ 21/ -28 = z /-80

=> Vì 21.(-80) = (-28) . z

           - 1680  =  -28z

                   z  =  -1680: ( -28)

                   z = 60

  Vậy x = -3   ;  y = -28  ;  z = 60

12/16 = -x/4 = 21/y = z/-80

=> 3/4 = -x/4 = 21/y = z/-80

* 3/4 = -x/4 => -x = 3 => x = -3

* -3/4 = 21/y 

Ta có : -3y = 4 . 21

-3y = 84

y = 84 : ( -3 ) = -28

* 21/-28 = z/-80

Ta có : 21 . ( -80 ) = -28z

            -1680 = -28z

            z = -1680 : -28 = 60

vậy x = -3 ; y = -28 ; z = 60

khong con nao

a, Thay x,y đề bài cho ta có: 2,5 = a.1+3 => a =-1/2

b, Điều kiện song song a = a' ; b≠b' => a = -2

\(a,\dfrac{242}{363}+\dfrac{1616}{2121}=\dfrac{2}{7}\times y\)

\(\dfrac{2}{7}\times y=\dfrac{2\times121}{3\times121}+\dfrac{16\times101}{21\times101}\)

\(\dfrac{2}{7}\times y=\dfrac{2}{3}+\dfrac{16}{21}\)

\(\dfrac{2}{7}\times y=\dfrac{14}{21}+\dfrac{16}{21}\)

\(\dfrac{2}{7}\times y=\dfrac{30}{21}\)

\(\dfrac{2}{7}\times y=\dfrac{10}{7}\)

\(y=\dfrac{10}{7}:\dfrac{2}{7}\)

\(y=\dfrac{10}{7}\times\dfrac{7}{2}\)

\(y=5\)

\(---\)

\(b,\left(y+\dfrac{1}{4}\right)+\left(y+\dfrac{1}{16}\right)+\left(y+\dfrac{1}{16}\right)=2\)

\(\left(y+y+y\right)+\left(\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{16}\right)=2\)

\(3\times y+\left(\dfrac{4}{16}+\dfrac{2}{16}\right)=2\)

\(3\times y+\dfrac{6}{16}=2\)

\(3\times y+\dfrac{3}{8}=2\)

\(3\times y=2-\dfrac{3}{8}\)

\(3\times y=\dfrac{16}{8}-\dfrac{3}{8}\)

\(3\times y=\dfrac{13}{8}\)

\(y=\dfrac{13}{8}:3\)

\(y=\dfrac{13}{8}\times\dfrac{1}{3}\)

\(y=\dfrac{13}{24}\)

#\(Toru\)

` 242/363 + 1616/2121 = 2/7 xxy`

`2/7 xxy= 2/3 + 16/21`

`2/7 xxy= 14/21 +16/21`

`2/7 xxy= 30/21`

`y=10/7 : 2/7`

`y=10/7 xx 7/2`

`y=70/14`

`y=5`

__

` (y + 1/4) + (y + 1/16) + (y + 1/16) =2`

`(y+y+y)+(1/4 + 1/16+1/16)=2`

`3y + (4/16 +1/16 +1/16)=2`

`3y + 6/16=2`

`3y=2-6/16`

`3y= 32/16-6/16`

`3y= 26/16`

`y=26/16 : 3`

`y=26/48`

`y=13/24`

\(3,2:y=16:10\)

\(\dfrac{16}{5}:y=\dfrac{8}{5}\)

\(y=\dfrac{16}{5}:\dfrac{8}{5}\)

\(y=2\)

y=165:85y=165:85

$y=2.$

y=16/5:8/5y