2-{3+5-[-12+5-(-3+7)-12]+32]
2-{3+5-[-12+5-(-3+7)-12]}+32
=2-[8-(-7-4-12)]+32
=2-[8-(-23)]+32
=2-31+32
=-29+32
=3
=2-{8-[-12+5-3-7+12]}+32
=2-{8-[(-12)+12+5-3-7]+32
=2-{8-[0+5-3-7]+32
=2-{8-(-5)}+32
=2-13+32
=21
2 - { 3 + 5 - [ - 12 + 5 - ( -3 + 7 ) - 12 ] + 32 }
\(=2-\left\{8-\left[-7+3-7-12\right]+32\right\}\)
\(=2-\left\{40-\left[-23\right]\right\}=2-63=-61\)
tính : 2- { 3+ 5 [ -12 + 5 - ( -3 + 7 ) - 12 ] + 32 }
2 - { 3 + 5 [ -12 + 5 - ( -3 + 7 ) - 12 ] + 32}
= 2 - { 3 + 5 [ -12 + 5 - 4 - 12 ] + 32}
= 2 - { 3 + 5 [ -7 - 4 - 12 ] + 32 }
= 2 - { 3 + 5 [ - 11 - 12 ] + 32 }
= 2 - { 3 + 5 x (- 23) ] + 32 }
= 2 - { 8 x (-23) ] + 32 }
= 2 - { -184 + 32 }
= 2 + 152
= 154
Tính nhẩm
a) 2 x 6 = ...... 3 x 7 = ......
12 : 2 = ...... 21 : 3 = ......
12 : 6 = ...... 21 : 7 = ......
4 x 8 = ...... 5 x 9 = ......
32 : 4 = ...... 45 : 5 = ......
32 : 8 = ...... 45 : 9 = ......
b) 600 : 3 = ...... 800 : 4 = ...... 400 : 2 = ......
600 : 2 = ...... 800 : 2 = ...... 500 : 5 = ......
) 2 x 6 = 12 3 x 7 = 21
12 : 2 = 6 21 : 3 = 7
12 : 6 = 2 21 : 7 = 3
4 x 8 = 32 5 x 9 = 45
32 : 4 = 8 45 : 5 = 9
32 : 8 = 4 45 : 9 = 5
b) 600 : 3 = 200 800 : 4 = 200 400 : 2 = 200
600 : 2 = 300 800 : 2 = 400 500 : 5 = 100
a) 2x6=12 3x7=21
12:2=6 21:3=7
12:6=2 21:7=3
4x8=32 5x9=45
32:4=8 45:5=9
32:8=4 45:9=5
b) 600:3=200 800:4=200 400:2=200
600:2=300 800:2=400 500:5=100
A Legend Never Dies
Tính nhẩm
a)2×6=12 3×7=21
12:2=6 21:3=7
12: 6=2 21:7=3
4×8=32 5×8=45
32:4=8 45:5=9
32:8=4 45:9=5
b)600:3=200 800:4=200 400:2=200
600:2=300 800:2=400 500:5=100
4/5 : ( 4/5 . -5/4) : ( 16/25 - 1/5 )
11/12 : ( 7/9 + -1/3 ) - ( 2/3 - 5/15 )
-2/5 . ( 9/8 + 16/32 -3/4 ) - 9/10
( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 )
cách giải bài này như nào: 5/20+1/4+6/24+8/32=bao nhiêu
\(\dfrac{4}{5}\) : (\(\dfrac{4}{5}\) .- \(\dfrac{5}{4}\)) : (\(\dfrac{16}{25}\) - \(\dfrac{1}{5}\))
= \(\dfrac{4}{5}\) : (-1) : (\(\dfrac{16}{25}\) - \(\dfrac{5}{25}\))
= -\(\dfrac{4}{5}\) : \(\dfrac{11}{25}\)
= - \(\dfrac{4}{5}\) x \(\dfrac{25}{11}\)
= - \(\dfrac{20}{11}\)
\(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) + \(\dfrac{-1}{3}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{5}{15}\))
= \(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) - \(\dfrac{3}{9}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{11}{12}\) : \(\dfrac{4}{9}\) - \(\dfrac{1}{3}\)
= \(\dfrac{11}{12}\) x \(\dfrac{9}{4}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{16}{48}\)
= \(\dfrac{83}{48}\)
4/5 : ( 4/5 . -5/4) : ( 16/25 - 1/5 )
11/12 : ( 7/9 + -1/3 ) - ( 2/3 - 5/15 )
-2/5 . ( 9/8 + 16/32 -3/4 ) - 9/10
( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 )
\(\dfrac{4}{5}\): (\(\dfrac{4}{5}\).-\(\dfrac{5}{4}\)) : (\(\dfrac{16}{25}\) - \(\dfrac{1}{5}\))
=\(\dfrac{4}{5}\) x - 1: (\(\dfrac{16}{25}\) - \(\dfrac{5}{25}\))
= - \(\dfrac{4}{5}\) : \(\dfrac{11}{25}\)
= - \(\dfrac{4}{5}\) x \(\dfrac{25}{11}\)
= - \(\dfrac{20}{11}\)
\(\dfrac{11}{12}\): (\(\dfrac{7}{9}\) + - \(\dfrac{1}{3}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{5}{15}\))
= \(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) - \(\dfrac{3}{9}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{11}{12}\) : \(\dfrac{4}{9}\) - \(\dfrac{1}{3}\)
= \(\dfrac{11}{12}\) x \(\dfrac{9}{4}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{16}{48}\)
= \(\dfrac{83}{48}\)
- \(\dfrac{2}{5}\).(\(\dfrac{9}{8}\) + \(\dfrac{16}{32}\) - \(\dfrac{3}{4}\)) - \(\dfrac{9}{10}\)
= - \(\dfrac{2}{5}\).(\(\dfrac{9}{8}\) + \(\dfrac{4}{8}\) - \(\dfrac{6}{8}\)) - \(\dfrac{9}{10}\)
= - \(\dfrac{2}{5}\).(\(\dfrac{13}{8}\) - \(\dfrac{6}{8}\)) - \(\dfrac{9}{10}\)
= - \(\dfrac{2}{5}\).\(\dfrac{7}{8}\) - \(\dfrac{9}{10}\)
= - \(\dfrac{7}{20}\) - \(\dfrac{18}{20}\)
= - \(\dfrac{5}{4}\)
Trục căn thức ở mẫu.
1) 5/√5 ; 3/2√3 ; 5/√7 ; 2√3/5√7 ; 5/2√3
2) 1/√3 ; 2/√3 + 1 ; 3/√5 - 1 ; 12/√5 - √3 ; 4√3 - 2/7 × √2
1)
\(\dfrac{5}{\sqrt{5}}=\dfrac{5\sqrt{5}}{5}\sqrt{5}\)
\(\dfrac{3}{2\sqrt{3}}=\dfrac{3\sqrt{3}}{2\sqrt{3}}=\sqrt{\dfrac{3}{2}}\)
\(\dfrac{5}{\sqrt{7}}=\dfrac{5\sqrt{7}}{\sqrt{49}}=\left(\dfrac{5}{7}\right)\sqrt{7}\)
1:
\(\dfrac{2\sqrt{3}}{5\sqrt{7}}=\dfrac{2\sqrt{21}}{35}\)
\(\dfrac{5}{2\sqrt{3}}=\dfrac{5\sqrt{3}}{6}\)
2: \(\dfrac{1}{\sqrt{3}}=\dfrac{\sqrt{3}}{3}\)
\(\dfrac{2}{\sqrt{3}+1}=\sqrt{3}-1\)
\(\dfrac{3}{\sqrt{5}-1}=\dfrac{3+3\sqrt{5}}{4}\)
\(\dfrac{12}{\sqrt{5}-\sqrt{3}}=6\left(\sqrt{5}+\sqrt{3}\right)=6\sqrt{5}+6\sqrt{3}\)
1) 15 - 98 + 91 - 75 + 98 - 91 - 13
2) 5 - ( 4 - 7 + 12 ) + ( 4 - 7 + 12 ) - 10
3) 20 - ( 25 - 98 + 12 ) + ( 25 - 98 - 72 )
4) - ( 17 - 4 + 13 + | -17 | + 13 )
5) | -16 | - ( 5 - 8 + 7) - ( - 5 ) - 8
6) -20 + ( 3 - 16 + 7 ) - ( 3 - 16 + 7 )
7) 32 - ( 5 - 8 + 32 ) + ( 5 - 8 + 6 )
8) -20 - ( 25 - 11 + 8 ) + ( 25 - 8 + 20 )
1)-73
2)-5
3)-64
4)-56
5)9
6)-20
7)6
8)-2
Tick nha
đăng tùng câu một thui bạn
bạn làm thế chắc tụi mk xỉu gần hết
2.x-3/3 + -3/2 = 5 - 3.x /6 - 1/3
2/3.x - 3/12 = 4/5 - (7/x -2)