\(\dfrac{1}{15}\)+ \(\dfrac{2}{15}\)
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3. b) 1dfrac{13}{15}.(0,5)2.3+(dfrac{8}{15}-1dfrac{19}{60}):1dfrac{23}{24}
c) (-2)3.dfrac{-1}{24}+(dfrac{4}{5}-1,2):dfrac{2}{15}
d) (dfrac{-2}{5})2+dfrac{1}{2}.(4,5-2)-255
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3. b) \(1\dfrac{13}{15}\).(0,5)2.3+(\(\dfrac{8}{15}\)-\(1\dfrac{19}{60}\)):\(1\dfrac{23}{24}\)
c) (-2)3.\(\dfrac{-1}{24}\)+(\(\dfrac{4}{5}\)-1,2):\(\dfrac{2}{15}\)
d) (\(\dfrac{-2}{5}\))2+\(\dfrac{1}{2}\).(4,5-2)-255
\(\dfrac{2}{15}-\dfrac{7}{1}+\dfrac{13}{15}+\dfrac{1}{2}\)
\(=\dfrac{15}{15}-7+\dfrac{1}{2}=1-7+\dfrac{1}{2}=-6+\dfrac{1}{2}=\dfrac{-11}{2}\)
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e) \(\left(15-6\dfrac{13}{18}\right)\):\(12\dfrac{1}{27}\)-\(2\dfrac{1}{8}\):\(1\dfrac{11}{40}\)
g) (-3,2).\(\dfrac{-15}{64}\)+\(\left(0,8-2\dfrac{4}{15}\right)\):\(3\dfrac{2}{3}\)
Đề bài là:Tính các giá trị biểu thức sau ạ
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a: \(=\left(9-\dfrac{13}{18}\right):\dfrac{325}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{325}-\dfrac{17}{8}\cdot\dfrac{40}{51}\)
\(=\dfrac{447}{650}-\dfrac{5}{3}=-\dfrac{1909}{1950}\)
b: \(=\dfrac{48}{64}+\left(\dfrac{4}{5}-2-\dfrac{4}{15}\right):\dfrac{11}{3}\)
\(=\dfrac{3}{4}+\dfrac{-22}{15}\cdot\dfrac{3}{11}=\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{15-8}{20}=\dfrac{7}{20}\)
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BT1: Tính nhanh
1) \(\left(\dfrac{-4}{9}+\dfrac{3}{7}\right):1\dfrac{1}{15}+\left(\dfrac{4}{7}-\dfrac{5}{9}\right):1\dfrac{1}{15}\)
2) \(3\dfrac{2}{9}.15\dfrac{4}{7}-3\dfrac{2}{9}.8\dfrac{1}{7}+3\dfrac{2}{9}.\dfrac{15}{7}-3\dfrac{2}{9}.\dfrac{1}{7}\)
1: \(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}\right)+\dfrac{16}{15}\left(\dfrac{4}{7}-\dfrac{5}{9}\right)\)
\(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}+\dfrac{4}{7}-\dfrac{5}{9}\right)=0\)
2: \(=\dfrac{29}{9}\left(15+\dfrac{4}{7}-8-\dfrac{1}{7}+\dfrac{15}{7}-\dfrac{1}{7}\right)\)
\(=\dfrac{20}{9}\cdot\left(7\cdot\dfrac{18}{7}\right)=\dfrac{20}{9}\cdot18=40\)
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\(\dfrac{2}{15}-\dfrac{7}{2}+\dfrac{13}{15}+\dfrac{1}{2}\)
= \(\left(\dfrac{2}{15}+\dfrac{13}{15}\right)\)- \(\left(\dfrac{7}{2}-\dfrac{1}{2}\right)\)
= \(\dfrac{15}{15}-\dfrac{6}{2}\)
= 1 -3
= -2
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Chứng minh rằng P>3 biet P= \(\dfrac{5}{2×1}+\dfrac{4}{1×11}+\dfrac{3}{11×2}+\dfrac{1}{2×15}+\dfrac{13}{15×4}+\dfrac{15}{4×43}+\dfrac{13}{43×8}\)
\(\dfrac{5}{2x1}+\dfrac{4}{1x11}+\dfrac{3}{11x2}+\dfrac{1}{2x15}+\dfrac{13}{15x4}+\dfrac{15}{4x13}\)
=7x(\(\dfrac{5}{2x7}+\dfrac{4}{7x11}+\dfrac{3}{11x14}+\dfrac{1}{14x15}+\dfrac{13}{15x28}+\dfrac{15}{28x43}\))
=7x\(\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{15}+\dfrac{1}{15}-\dfrac{1}{28}+\dfrac{1}{28}-\dfrac{1}{43}\)=7x(\(\dfrac{1}{2}-\dfrac{1}{43}\))
=7x\(\dfrac{41}{86}\)
=\(\dfrac{287}{86}\)
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5/2x1+4/1x11+3/11x2+1/2x15+13/15x4+15/4x43=7x(5/2x7+4/7x11+3/11x14+1/14x15+13/15x28+15/28x43)=7x(1/2-1/7+1/7-1/11+1/11-1/14+1/14+1/15+1/15-1/28+1/28-1/43)=7x(1/2-1/43)=7x41/86=287/86
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\(\dfrac{-2}{9}+\dfrac{8}{15}+1\dfrac{2}{3}-\dfrac{7}{9}+\dfrac{-7}{15}\)
\(\dfrac{-2}{9}+\dfrac{8}{15}+1\dfrac{2}{3}-\dfrac{7}{9}+\dfrac{-7}{15}\)
\(=\dfrac{-2}{9}+\dfrac{8}{15}+\dfrac{5}{3}-\dfrac{7}{9}+\dfrac{-7}{15}\)
\(=\left(\dfrac{-2}{9}+\dfrac{-7}{9}\right)+\left(\dfrac{8}{15}+\dfrac{-7}{15}\right)+\dfrac{5}{3}\)
\(=-1+\dfrac{1}{15}+\dfrac{5}{3}\)
\(=\dfrac{-14}{15}+\dfrac{5}{3}\)
\(=\dfrac{11}{15}\)
Chúc bạn học tốt
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= (-2/9-7/9)+(8/15-7/15)+5/3
= -1 + 1/15 + 5/3
= 11/15
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16 tháng 10 2021 lúc 15:24
VÒNG 2Bài 1: Mèo con nhanh nhẹndfrac{1}{2} + dfrac{1}{12}2 + dfrac{1}{6}dfrac{1}{20}1 - dfrac{1}{9} dfrac{1}{15} + dfrac{2}{15}dfrac{1}{2} + dfrac{2}{3}dfrac{7}{12}dfrac{4}{12} dfrac{9}{14}+ dfrac{1}{14}1 + dfrac{1}{6}dfrac{1}{4} - dfrac{1}{5}dfrac{1}{3} - dfrac{2}{9} dfrac{3}{2} + dfrac{2}{3}dfrac{1}{5}1 - dfrac{8}{9} dfrac{5}{7}1 - dfrac{2}{3}dfrac{1}{3} + dfrac{5}{9}
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VÒNG 2
Bài 1: Mèo con nhanh nhẹn
| \(\dfrac{1}{2}\) + \(\dfrac{1}{12}\) | 2 + \(\dfrac{1}{6}\) | \(\dfrac{1}{20}\) | 1 - \(\dfrac{1}{9}\) | |
| \(\dfrac{1}{15}\) + \(\dfrac{2}{15}\) | \(\dfrac{1}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{7}{12}\) | \(\dfrac{4}{12}\) | |
| \(\dfrac{9}{14}\)+ \(\dfrac{1}{14}\) | 1 + \(\dfrac{1}{6}\) | \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) | \(\dfrac{1}{3}\) - \(\dfrac{2}{9}\) | |
| \(\dfrac{3}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{1}{5}\) | 1 - \(\dfrac{8}{9}\) | ||
| \(\dfrac{5}{7}\) | 1 - \(\dfrac{2}{3}\) | \(\dfrac{1}{3}\) + \(\dfrac{5}{9}\) |
15 tháng 7 2023 lúc 9:22
Tìm x biết:
\(3x-\dfrac{15}{5.8}-\dfrac{15}{8.11}-\dfrac{15}{11.14}-...-\dfrac{15}{47.50}=2\dfrac{1}{10}\)
Giúp mik với, giải chi tiết dùm nhe :>
`3x-15/(5*8)-15/(8*11)-15/(11*14)-...-15/(47*50)=2 1/10`
`3x-(15/(5*8)+15/(8*11)+15/(11*14)+...+15/(47*50))=21/10`
`3x-5(3/(5*8)+3/(8*11)+3/(11*14)+...+3/(47*50))=21/10`
`3x-5(1/5-1/8+1/8-1/11+1/11-1/14+...+1/47-1/50)=21/10`
`3x-5(1/5-1/50)=21/10`
`3x-5*9/50=21/10`
`3x-9/10=21/10`
`3x=21/10+9/10`
`3x=3`
`x=1`
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SGK Cánh diều - Tập 2 - Trang 51
28 tháng 10 2023 lúc 0:42
Tính rồi rút gọn (theo mẫu):Mẫu: dfrac{9}{10}-dfrac{4}{10}dfrac{9-4}{10}dfrac{5}{10}dfrac{1}{2}a) dfrac{15}{8}-dfrac{13}{8} b) dfrac{7}{15}-dfrac{2}{15} c) dfrac{11}{12}-dfrac{2}{12} d) dfrac{19}{7}-dfrac{5}{7}
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Tính rồi rút gọn (theo mẫu):
| Mẫu: \(\dfrac{9}{10}-\dfrac{4}{10}=\dfrac{9-4}{10}=\dfrac{5}{10}=\dfrac{1}{2}\) |
a) \(\dfrac{15}{8}-\dfrac{13}{8}\) b) \(\dfrac{7}{15}-\dfrac{2}{15}\) c) \(\dfrac{11}{12}-\dfrac{2}{12}\) d) \(\dfrac{19}{7}-\dfrac{5}{7}\)
a: \(\dfrac{15}{8}-\dfrac{13}{8}=\dfrac{15-13}{8}=\dfrac{2}{8}=\dfrac{1}{4}\)
b: \(\dfrac{7}{15}-\dfrac{2}{15}=\dfrac{7-2}{15}=\dfrac{5}{15}=\dfrac{1}{3}\)
c: \(\dfrac{11}{12}-\dfrac{2}{12}=\dfrac{11-2}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
d: \(\dfrac{19}{7}-\dfrac{5}{7}=\dfrac{19-5}{7}=\dfrac{14}{7}=2\)
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